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Virat
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Wheel circumference is π x d = (22/7) x 60 = 1320/7 cm (approx 1.886 m). For 100 rotations, total distance is 100 x (1320/7) = 132000/7 cm ≈ 18857.14 cm = 188.57 m.

chapter 6 measuring space: perimeter and area question answerhow far a cyclist will have travelledsolutions - measuring space: perimeter and areawheel of a bicycle has a diameter of 60 cm
Virat
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For (a + b)(a – b), remove corner square b² from square a²; rearrange the remaining L-shape into rectangle (a + b) by (a – b). For (a + b + c)², divide a square into 9 blocks yielding a² ...

algebra can sometimes be shown as area relationshipschapter 6 measuring space: perimeter and area question answerclass 9 ganita manjari chapter 6 measuring space: perimeter and area solutionsdraw figures corresponding to the identities
Kriti
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In 60 minutes, the minute hand turns 360°, so in 10 minutes it turns (360/60) x 10 = 60°. The area swept is a sector: (60/360) x (22/7) x 7² = 77/3 = 25.67 cm².

area swept by the minute hand in 10chapter 6 measuring space: perimeter and area question answerclass 9 ganita manjari chapter 6 measuring space: perimeter and area solutionslength of the minute hand of a clock is 7 cmsolutions - measuring space: perimeter and area
Kriti
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Median AD divides ΔABC into equal areas: Area(ΔABD) = Area(ΔACD). Similarly, in ΔPBC, median PD gives Area(ΔPBD) = Area(ΔPCD). Subtracting these two equations yields Area(ΔABP) = Area(ΔACP).

chapter 6 measuring space: perimeter and area question answerganita manjari class 9 exercise 6.2 solutionsmidpoint of bc is d (fig. 6.32)ncert solutions – measuring space: perimeter and areashow that area (Δabp) = area (Δacp)
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