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Ashok0210

Asked: March 5, 2021In: Class 12 Physics

Figure 7.21 shows a series LCR circuit connected to a variable frequency 230 V source. L = 5.0 H, C = 80μF, R = 40 Ω (a) Determine the source frequency which drives the circuit in resonance. (b) Obtain the impedance of the circuit and the amplitude of current at e ^ the resonating frequency. (c) Determine the rms potential drops across the three elements of the circuit. Show that the potential drop across the LC combination is zero at the resonating frequency.

Class 12 Physics CBSE and UP Board Alternating Current Chapter-7 Exercise 7.11 NCERT Solutions for Class 12 Physics Chapter 7 Question 11

Ashok0210

Asked: March 5, 2021In: Class 12 Physics

Keeping the source frequency equal to the resonating frequency of the series LCR circuit, if the three elements, L, C and R are arranged in parallel, show that the total current in the parallel LCR circuit is minimum at this frequency. Obtain the current rms value in each branch of the circuit for the elements and source specified in Exercise 7.11 for this frequency.

Class 12 Physics CBSE and UP Board Alternating Current Chapter-7 Exercise 7.17 Additional Exercise NCERT Solutions for Class 12 Physics Chapter 7 Question 17

Ashok0210

Asked: March 5, 2021In: Class 12 Physics

Obtain the answers to (a) and (b) in Exercise 7.15 if the circuit is connected to a 110 V, 12 kHz supply? Hence, explain the statement that a capacitor is a conductor at very high frequencies. Compare this behaviour with that of a capacitor in a dc circuit after the steady state.

Class 12 Physics CBSE and UP Board Alternating Current Chapter-7 Exercise 7.16 Additional Exercise NCERT Solutions for Class 12 Physics Chapter 7 Question 16

Ashok0210

Asked: March 5, 2021In: Class 12 Physics

A 100 μF capacitor in series with a 40 Ω resistance is connected to a 110 V, 60 Hz supply. (a) What is the maximum current in the circuit? (b) What is the time lag between the current maximum and the voltage maximum?

Class 12 Physics CBSE and UP Board Alternating Current Chapter-7 Exercise 7.15 Additional Exercise NCERT Solutions for Class 12 Physics Chapter 7 Question 15

Ashok0210

Asked: March 4, 2021In: Class 12 Physics

(a) Obtain an expression for the mutual inductance between a long straight wire and a square loop of side a as shown in Fig. 6.21. (b) Now assume that the straight wire carries a current of 50 A and the loop is moved to the right with a constant velocity, v = 10 m/s. Calculate the induced emf in the loop at the instant when x = 0.2 m. Take a = 0.1 m and assume that the loop has a large resistance.

Class 12 Physics CBSE and UP Board Electromagnetic Induction Chapter-6 Exercise 6.16 Additional Exercise NCERT Solutions for Class 12 Physics Chapter 6 Question 16

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Obtain the answers to (a) and (b) in Exercise 7.15 if the circuit is connected to a 110 V, 12 kHz supply? Hence, explain the statement that a capacitor is a conductor at very high frequencies. Compare this behaviour with that of a capacitor in a dc circuit after the steady state.

A 100 μF capacitor in series with a 40 Ω resistance is connected to a 110 V, 60 Hz supply. (a) What is the maximum current in the circuit? (b) What is the time lag between the current maximum and the voltage maximum?

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