(i) By Varignon’s Theorem, PQRS is a parallelogram, so its diagonals PR and QS bisect each other. (ii) PQ = RS = AC/2 and QR = SP = BD/2. If AC = BD, PQRS is a rhombus, having perpendicular diagonals. Yes, ...
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Asked: In: Class 9 Maths
(i) By the Midpoint Theorem, PQ = BC/2 = BR = RC, QR = AB/2 = AP = PB and PR = AC/2 = AQ = QC, so △PQR ≅ △QPA ≅ △RPB ≅ △CQR by SSS. (ii) Yes, construct ...