Expanding the left side yields 3a square + 3b square + 3c square – 2ab – 2bc – 2ca, which does not match the right side. Therefore, the given mathematical equation is false.
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We substitute a = 3x, b = -2y and c = 4z into the expansion formula. Squaring terms makes them positive, while the cross-products involving the negative y term become negative.
We expand this by substituting a = p, b = 3q and c = 7r into the identity. Squaring the individual items and finding their paired double products yields the answer.
This expression matches the identity template a square – 2ab + b square. The middle variable terms cancel out completely when multiplying p/4 and 4/p, leaving only the constant integer minus 2.
This six-term polynomial matches the expanded three-term identity. The squared bases are m/3, k/2, and 3n, which merge into the single grouped factor (m/3 + k/2 + 3n) square.