(i) [(6aᵧ) + (4aₛ) + (5aₖ) + (4aₚ) + (4a₉)] / 23. (ii) With 13 nylon and 10 feather shuttles, the expression is [(13aₙ) + (10a𝒻)] / 23. Yes, both methods yield the exact same overall average. Ganita Manjari part 2 ...
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(i) Total runs are 6 + 12 = 18 over 2 overs, giving a run rate of 9. (ii) Total runs are (19 × 6) + 12 = 126; dividing by 20 gives a run rate of 6.3. Ganita Manjari Part ...
(i) Salinity is approximately 11.33%. (ii) Yes, because 0.01% lies between 34% and 0.001%; he needs about 3777 litres. (iii) No, because mixture salinity cannot fall below 0.01%. Class 9 Maths How Quantities Combine Understanding Data Question Answer Class 9 Maths ...
There are more females because 14.925 kg is below the 15.15 kg midpoint. (i) Expressions (a) and (b) are correct. (ii) 25 males. (iii) 13.839 kg. (iv) 16.5 kg. (v) 16.46 kg. Class 9 Ganita Manjari Part 2 All Chapter Solutions
Average scores are 4.3 for food, 3.3 for ambience and 2.8 for service. Applying weights 6:5:4 gives [(4.3 × 6) + (3.3 × 5) + (2.8 × 4)] / 15 = 53.5 / 15 ≈ 3.57. Class 9 Ganita Manjari Part ...