We express the product as (20 – 2) (30 – 1) and expand using the distributive property. Evaluating the separate numerical products step by step gives the clean final total.
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We express the product as (20 – 2) (30 – 1) and expand using the distributive property. Evaluating the separate numerical products step by step gives the clean final total.
We rewrite 97 as 100 – 3 and apply the subtraction square identity. Squaring 100 and 3, then subtracting twice their product gives the plain numerical solution.
Piyush365
Asked: In: Class 9 Maths
We split 135 into 100 + 30 + 5 and expand it using the three-term identity. Summing the separate square values and their paired products provides the final answer.
Virat
Asked: In: Class 9 Maths
We express 27 as 30 – 3 and utilize the subtraction square identity. Squaring the terms and subtracting their double cross-product leaves the final calculation of 729.