Infinitely many solutions require (a + b)/3 = −2b/(−1) = (5a + 2b + 1)/14. Equating gives a = 5b and 5a − 26b = −1. Substituting a = 5b yields b = 1, which gives a = 5. Class 9 ...
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For a unique solution, a₁/a₂ ≠ b₁/b₂. Here, 4/2 ≠ p/2, which simplifies to 2 ≠ p/2, giving p ≠ 4. Thus, a unique solution exists for all real values of p except 4. Ganita Manjari Class 9 Maths part 2 ...
Exactly one unique line exists. A specified slope m and a fixed point (x₁, y₁) uniquely determine the line using the point-slope relation y − y₁ = m(x − x₁). Ganita Manjari Part 2 Class 9 Maths chapter 13 question answer Class ...
Infinitely many lines exist with a given slope. In the slope-intercept form y = mx + c, varying the y-intercept c generates an infinite family of parallel lines with the same slope m. Class 9 Maths (Ganita Manjari part two) Chapter ...
Both plans cost the same at 50 + 0.20m = 30 + 0.30m, giving 0.10m = 20, so m = 200 minutes. Plan B is cheaper for under 200 minutes; Plan A is cheaper for over 200 minutes. NCERT Solution for ...