To construction: ∆PQR, in which PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. Steps of construction: (a) Draw a line segment QR = 3.5 cm. (b) Taking Q as centre and radius 4 cm, draw an arc. (c) Similarly, taking R as centre and radius 4 cm, draw an another arc which intersects first arc at P. (d) Join PQ aRead more
To construction: ∆PQR, in which PQ = 4 cm, QR = 3.5 cm and PR = 4 cm.
Steps of construction:
(a) Draw a line segment QR = 3.5 cm.
(b) Taking Q as centre and radius 4 cm, draw an arc.
(c) Similarly, taking R as centre and radius 4 cm, draw an another arc which
intersects first arc at P.
(d) Join PQ and PR.
It is the required isosceles ∆PQR
To construct: A ∆ABC where AB = BC = CA = 5.5 cm Steps of construction: (a) Draw a line segment BC = 5.5 cm (b) Taking points B and C as centers and radius 5.5 cm, draw arcs which intersect at point A. (c) Join AB and AC. It is the required ∆ABC. Class 7 Maths Chapter 10 Exercise 10.2 for more answeRead more
To construct: A ∆ABC where AB = BC = CA = 5.5 cm
Steps of construction:
(a) Draw a line segment BC = 5.5 cm
(b) Taking points B and C as centers and radius 5.5 cm, draw arcs which intersect at
point A.
(c) Join AB and AC.
It is the required ∆ABC.
To construct: ∆XYZ, where XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm. Steps of construction: (a) Draw a line segment YZ = 5 cm. (b) Taking Z as centre and radius 6 cm, draw an arc. (c) Similarly, taking Y as centre and radius 4.5 cm, draw another arc which intersects first arc at point X. (d) Join XY andRead more
To construct: ∆XYZ, where XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.
Steps of construction:
(a) Draw a line segment YZ = 5 cm.
(b) Taking Z as centre and radius 6 cm, draw an arc.
(c) Similarly, taking Y as centre and radius 4.5 cm, draw another arc which
intersects first arc at point X.
(d) Join XY and XZ.
It is the required ∆XYZ.
To construct: A pair of parallel lines intersecting other part of parallel lines. Steps of construction: (a) Draw a line l and take a point P outside of l . (b) Take point Q on line l and join PQ. (c) Make equal angle at point P such that ∠Q = ∠P. (d) Extend line at P to get line m. (e) Similarly, tRead more
To construct: A pair of parallel lines intersecting other part of parallel lines.
Steps of construction:
(a) Draw a line l and take a point P outside of l .
(b) Take point Q on line l and join PQ.
(c) Make equal angle at point P such that ∠Q = ∠P.
(d) Extend line at P to get line m.
(e) Similarly, take a point R online m, at point R, draw angles such that ∠P = ∠R.
(f) Extended line at R which intersects at S online l. Draw line RS.
Thus, we get parallelogram PQRS
To construct: A line parallel to given line when perpendicular line is also given. Steps of construction: (a) Draw a line l and take a point P on it. (b) At point P, draw a perpendicular line n. (c) Take PX = 4 cm on line n. (d) At point X, again draw a perpendicular line m. It is the required constRead more
To construct: A line parallel to given line when perpendicular line is also given.
Steps of construction:
(a) Draw a line l and take a point P on it.
(b) At point P, draw a perpendicular line n.
(c) Take PX = 4 cm on line n.
(d) At point X, again draw a perpendicular line m.
It is the required construction
To construct: A line, parallel to given line by using ruler and compasses. Steps of construction: (a) Draw a line-segment AB and take a point C outside AB. (b) Take any point D on AB and join C to D. (c) With D as center and take convenient radius, draw an arc cutting AB at E and CD at F. (d) With CRead more
To construct: A line, parallel to given line by using ruler and compasses.
Steps of construction:
(a) Draw a line-segment AB and take a point C outside AB.
(b) Take any point D on AB and join C to D.
(c) With D as center and take convenient radius, draw an arc cutting AB at E and CD at F.
(d) With C as center and same radius as in step 3, draw an arc GH cutting CD at I.
(e) With the same arc EF, draw the equal arc cutting GH at J.
(f) Join JC to draw a line l.
This the required line 𝐴𝐵 ∥ 𝑙.
Draw ∆PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?
To construction: ∆PQR, in which PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. Steps of construction: (a) Draw a line segment QR = 3.5 cm. (b) Taking Q as centre and radius 4 cm, draw an arc. (c) Similarly, taking R as centre and radius 4 cm, draw an another arc which intersects first arc at P. (d) Join PQ aRead more
To construction: ∆PQR, in which PQ = 4 cm, QR = 3.5 cm and PR = 4 cm.
Steps of construction:
(a) Draw a line segment QR = 3.5 cm.
(b) Taking Q as centre and radius 4 cm, draw an arc.
(c) Similarly, taking R as centre and radius 4 cm, draw an another arc which
intersects first arc at P.
(d) Join PQ and PR.
It is the required isosceles ∆PQR
Class 7 Maths Chapter 10 Exercise 10.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-10/
Construct an equilateral triangle of side 5.5 cm.
To construct: A ∆ABC where AB = BC = CA = 5.5 cm Steps of construction: (a) Draw a line segment BC = 5.5 cm (b) Taking points B and C as centers and radius 5.5 cm, draw arcs which intersect at point A. (c) Join AB and AC. It is the required ∆ABC. Class 7 Maths Chapter 10 Exercise 10.2 for more answeRead more
To construct: A ∆ABC where AB = BC = CA = 5.5 cm
Steps of construction:
(a) Draw a line segment BC = 5.5 cm
(b) Taking points B and C as centers and radius 5.5 cm, draw arcs which intersect at
point A.
(c) Join AB and AC.
It is the required ∆ABC.
Class 7 Maths Chapter 10 Exercise 10.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-10/
Construct ∆XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.
To construct: ∆XYZ, where XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm. Steps of construction: (a) Draw a line segment YZ = 5 cm. (b) Taking Z as centre and radius 6 cm, draw an arc. (c) Similarly, taking Y as centre and radius 4.5 cm, draw another arc which intersects first arc at point X. (d) Join XY andRead more
To construct: ∆XYZ, where XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.
Steps of construction:
(a) Draw a line segment YZ = 5 cm.
(b) Taking Z as centre and radius 6 cm, draw an arc.
(c) Similarly, taking Y as centre and radius 4.5 cm, draw another arc which
intersects first arc at point X.
(d) Join XY and XZ.
It is the required ∆XYZ.
Class 7 Maths Chapter 10 Exercise 10.2
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-10/
Let l be a line and P be a point not on l. Through P, draw a line m parallel to l. Now join P to any point Q on l. Choose any other point R on m. Through R, draw a line parallel to PQ. Let this meet l at S. What shape do the two sets of parallel lines enclose?
To construct: A pair of parallel lines intersecting other part of parallel lines. Steps of construction: (a) Draw a line l and take a point P outside of l . (b) Take point Q on line l and join PQ. (c) Make equal angle at point P such that ∠Q = ∠P. (d) Extend line at P to get line m. (e) Similarly, tRead more
To construct: A pair of parallel lines intersecting other part of parallel lines.
Steps of construction:
(a) Draw a line l and take a point P outside of l .
(b) Take point Q on line l and join PQ.
(c) Make equal angle at point P such that ∠Q = ∠P.
(d) Extend line at P to get line m.
(e) Similarly, take a point R online m, at point R, draw angles such that ∠P = ∠R.
(f) Extended line at R which intersects at S online l. Draw line RS.
Thus, we get parallelogram PQRS
Class 7 Maths Chapter 10 Exercise 10.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-10/
Draw a line l. Draw a perpendicular to l at any point on l. On this perpendicular choose a point X, 4 cm away from l. Through X, draw a line m parallel to l.
To construct: A line parallel to given line when perpendicular line is also given. Steps of construction: (a) Draw a line l and take a point P on it. (b) At point P, draw a perpendicular line n. (c) Take PX = 4 cm on line n. (d) At point X, again draw a perpendicular line m. It is the required constRead more
To construct: A line parallel to given line when perpendicular line is also given.
Steps of construction:
(a) Draw a line l and take a point P on it.
(b) At point P, draw a perpendicular line n.
(c) Take PX = 4 cm on line n.
(d) At point X, again draw a perpendicular line m.
It is the required construction
Class 7 Maths Chapter 10 Exercise 10.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-10/
Draw a line, say AB, take a point C outside it. Through C, draw a line parallel to AB using ruler and compasses only.
To construct: A line, parallel to given line by using ruler and compasses. Steps of construction: (a) Draw a line-segment AB and take a point C outside AB. (b) Take any point D on AB and join C to D. (c) With D as center and take convenient radius, draw an arc cutting AB at E and CD at F. (d) With CRead more
To construct: A line, parallel to given line by using ruler and compasses.
Steps of construction:
(a) Draw a line-segment AB and take a point C outside AB.
(b) Take any point D on AB and join C to D.
(c) With D as center and take convenient radius, draw an arc cutting AB at E and CD at F.
(d) With C as center and same radius as in step 3, draw an arc GH cutting CD at I.
(e) With the same arc EF, draw the equal arc cutting GH at J.
(f) Join JC to draw a line l.
This the required line 𝐴𝐵 ∥ 𝑙.
Class 7 Maths Chapter 10 Exercise 10.1
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-10/