1. 11² = 121 101² = 10201 10101² = 102030201 1010101² = 1020304030201 101010101² = 10203040504030201 Class 8 Maths Chapter 6 Exercise 6.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/

    11² = 121
    101² = 10201
    10101² = 102030201
    1010101² = 1020304030201
    101010101² = 10203040504030201

    Class 8 Maths Chapter 6 Exercise 6.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/

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  2. 11² = 121 101² = 10201 1001² = 1002001 100001² = 10000200001 1000000² = 100000020000001 Class 8 Maths Chapter 6 Exercise 6.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/

    11² = 121
    101² = 10201
    1001² = 1002001
    100001² = 10000200001
    1000000² = 100000020000001

    Class 8 Maths Chapter 6 Exercise 6.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/

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  3. (i) 431 – Unit’s digit of given number is 1 and square of 1 is 1. Therefore, square of 431 would be an odd number. (ii) 2826 – Unit’s digit of given number is 6 and square of 6 is 36. Therefore, square of 2826 would not be an odd number. (iii) 7779 – Unit’s digit of given number is 9 and square of 9Read more

    (i) 431 – Unit’s digit of given number is 1 and square of 1 is 1. Therefore, square of 431 would be an odd number.
    (ii) 2826 – Unit’s digit of given number is 6 and square of 6 is 36. Therefore, square of 2826 would not be an odd number.
    (iii) 7779 – Unit’s digit of given number is 9 and square of 9 is 81. Therefore, square of 7779 would be an odd number.
    (iv) 82004 – Unit’s digit of given number is 4 and square of 4 is 16. Therefore, square of 82004 would not be an odd number.

    Class 8 Maths Chapter 6 Exercise 6.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/

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  4. (i) Since, perfect square numbers contain their unit’s place digit 1, 4, 5, 6, 9 and even numbers of 0. Therefore 1057 is not a perfect square because its unit’s place digit is 7. (ii) Since, perfect square numbers contain their unit’s place digit 0, 1, 4, 5, 6, 9 and even number of 0. Therefore 234Read more

    (i) Since, perfect square numbers contain their unit’s place digit 1, 4, 5, 6, 9 and even numbers of 0.
    Therefore 1057 is not a perfect square because its unit’s place digit is 7.
    (ii) Since, perfect square numbers contain their unit’s place digit 0, 1, 4, 5, 6, 9 and even number of 0. Therefore 23453 is not a perfect square because its unit’s place digit is 3.
    (iii) Since, perfect square numbers contain their unit’s place digit 0, 1, 4, 5, 6, 9 and even number of 0. Therefore 7928 is not a perfect square because its unit’s place digit is 8.
    (iv) Since, perfect square numbers contain their unit’s place digit 0, 1, 4, 5, 6, 9 and even number of 0. Therefore 222222 is not a perfect square because its unit’s place digit is 2.
    (v) Since, perfect square numbers contain their unit’s place digit 0, 1, 4, 5, 6, 9 and even number of 0. Therefore 64000 is not a perfect square because its unit’s place digit is single 0.
    (vi) Since, perfect square numbers contain their unit’s place digit 0, 1, 4, 5, 6, 9 and even number of 0. Therefore 89722 is not a perfect square because its unit’s place digit is 2.
    (vii) Since, perfect square numbers contain their unit’s place digit 0, 1, 4, 5, 6, 9 and even number of 0. Therefore 222000 is not a perfect square because its unit’s place digit is triple 0.
    (viii) Since, perfect square numbers contain their unit’s place digit 0, 1, 4, 5, 6, 9 and even number of 0. Therefore 505050 is not a perfect square because its unit’s place digit is 0.

    Class 8 Maths Chapter 6 Exercise 6.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/

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  5. (i) The number 81 contains its unit’s place digit 1. So, square of 1 is 1. Hence, unit’s digit of square of 81 is 1. (ii) The number 272 contains its unit’s place digit 2. So, square of 2 is 4. Hence, unit’s digit of square of 272 is 4. (iii) The number 799 contains its unit’s place digit 9. So, squRead more

    (i) The number 81 contains its unit’s place digit 1. So, square of 1 is 1. Hence, unit’s digit of square of 81 is 1.
    (ii) The number 272 contains its unit’s place digit 2. So, square of 2 is 4. Hence, unit’s digit of square of 272 is 4.
    (iii) The number 799 contains its unit’s place digit 9. So, square of 9 is 81. Hence, unit’s digit of square of 799 is 1.
    (iv) The number 3853 contains its unit’s place digit 3. So, square of 3 is 9. Hence, unit’s digit of square of 3853 is 9.
    (v) The number 1234 contains its unit’s place digit 4. So, square of 4 is 16. Hence, unit’s digit of square of 1234 is 6.
    (vi) The number 26387 contains its unit’s place digit 7. So, square of 7 is 49. Hence, unit’s digit of square of 26387 is 9.
    (vii) The number 52698 contains its unit’s place digit 8. So, square of 8 is 64. Hence, unit’s digit of square of 52698 is 4.
    (viii) The number 99880 contains its unit’s place digit 0. So, square of 0 is 0. Hence, unit’s digit of square of 99880 is 0.
    (ix) The number 12796 contains its unit’s place digit 6. So, square of 6 is 36. Hence, unit’s digit of square of 12796 is 6.
    (x) The number 55555 contains its unit’s place digit 5. So, square of 5 is 25. Hence, unit’s digit of square of 55555 is 5.

    Class 8 Maths Chapter 6 Exercise 6.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-6/

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