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Vivek Kohli

In a potentiometer, the balancing length is proportional to the emf of the cell. Given V balances at l/3, for a cell of emf 1.5V, the new balancing length is (1.5V/V) × (l/3) = 2l/3. Answer: (d) 2l/3. Class 12th ...

Vivek Kohli

Using the meter bridge formula R/S = L1/(100 – L1), we substitute R = 2Ω, L1 = 40 cm: 2/S = 40/60 Solving, S = 3Ω. Correct answer: (b) 3Ω. Class 12th Science Physics NCERT MCQ Questions NCERT Books MCQ ...

Vivek Kohli

Using the potentiometer principle: E∝L Initially, the balance length is L₁ = 50 cm. When the cell is shunted by Rₛ = 2 Ω, the new balance length is L₂ = 40 cm. Class 12th Science Physics NCERT MCQ Questions