For x = -2, y = 1, giving (-2, 1) in Quadrant II. For x = 1, y = -4, giving (1, -4) in Quadrant IV. Both points satisfy -5x – 3y = 7. class 9 maths ganita manjari part 2 ...
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Virat
Asked: In: Class 9 Maths
For x = 1, y = 4, giving (1, 4) in Quadrant I. For x = -2, y = -1, giving (-2, -1) in Quadrant III. Both points satisfy -5x + 3y = 7. Cbse released Class 9 Ganita Manjari Part ...
Virat
Asked: In: Class 9 Maths
For x = 2, y = 1, giving (2, 1) in Quadrant I. For x = -1, y = -4, giving (-1, -4) in Quadrant III. Both points satisfy 5x – 3y = 7. Class 9 Maths Ganita Manjari Part 2 ...
Virat
Asked: In: Class 9 Maths
For x = 2, y = -1, giving the point (2, -1) in Quadrant IV. For x = -1, y = 4, giving the point (-1, 4) in Quadrant II. Both satisfy the equation. Class 9 Maths Ganita Manjari Part 2 ...
Virat
Asked: In: Class 9 Maths
Substituting (2, -1) into 2mx + 3y = 7 yields 4m – 3 = 7, which gives m = 2.5. Substituting into 4x + ny = -10 gives 8 – n = -10, resulting in n = 18. Ganita Manjari part ...