The desired concentration is (3/4) × 8% = 6%. The original 10 litres contain 10 × 0.08 = 0.8 litres of pure spice. If x litres of regular water are added, the new concentration is 0.8/(10 + x) = 0.06. Solving this equation gives 0.06(10 + x) = 0.8, leading to 0.06x = 0.2, which means x = 20/6 = 3.33Read more
The desired concentration is (3/4) × 8% = 6%. The original 10 litres contain 10 × 0.08 = 0.8 litres of pure spice. If x litres of regular water are added, the new concentration is 0.8/(10 + x) = 0.06. Solving this equation gives 0.06(10 + x) = 0.8, leading to 0.06x = 0.2, which means x = 20/6 = 3.33 litres (or 3 1/3 litres) of water must be added.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
The correct option is (v) Salt: 3.33%, Sugar: 2.67%. The first solution contains 30 mL of salt, while the second contains 24 mL of sugar. In the combined 900 mL mixture, the salt concentration is (30/900) × 100 = 3.33% and the sugar concentration is (24/900) × 100 = 2.67%. For more NCERT SoluRead more
The correct option is (v) Salt: 3.33%, Sugar: 2.67%. The first solution contains 30 mL of salt, while the second contains 24 mL of sugar. In the combined 900 mL mixture, the salt concentration is (30/900) × 100 = 3.33% and the sugar concentration is (24/900) × 100 = 2.67%.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
Before calculating, since 55 km is higher than 44.5 km, the new average will rise slightly, perhaps around 45 km. Computing accurately, the total distance covered during the first 20 days is 890 km. Adding the 21st day's 55 km gives 945 km in total. Dividing 945 km by 21 days yields an exact averageRead more
Before calculating, since 55 km is higher than 44.5 km, the new average will rise slightly, perhaps around 45 km. Computing accurately, the total distance covered during the first 20 days is 890 km. Adding the 21st day’s 55 km gives 945 km in total. Dividing 945 km by 21 days yields an exact average daily distance of 45 km.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
The shopkeeper earns a profit of 30% on books, giving ₹2400 and 50% on book covers, giving ₹500. The total profit generated is ₹2900 on total sales of ₹9000. Hence, the overall profit percentage on total sales is (2900/9000) × 100, which equals approximately 32.22% (or 32 2/9%). For more NCERRead more
The shopkeeper earns a profit of 30% on books, giving ₹2400 and 50% on book covers, giving ₹500. The total profit generated is ₹2900 on total sales of ₹9000. Hence, the overall profit percentage on total sales is (2900/9000) × 100, which equals approximately 32.22% (or 32 2/9%).
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
Not directly without modification. Our original algorithm assumes that the divisors appear in strictly increasing order so that the largest common factor is simply the rightmost element. Listing divisors in pairs—like (1, 18), (2, 9), (3, 6)—mixes small and large numbers together. To make the algoriRead more
Not directly without modification. Our original algorithm assumes that the divisors appear in strictly increasing order so that the largest common factor is simply the rightmost element. Listing divisors in pairs—like (1, 18), (2, 9), (3, 6)—mixes small and large numbers together. To make the algorithm work, we would first have to sort the combined list into ascending order.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 11 The World of Algorithms Question Answer (2026-27)
At a panipuri (golgappa) stall, the concentration of spice in the pani (spiced water) was 8%. Many customers complained that it was too spicy. What quantity of regular water should be mixed into the 10 litres of pani so that the spice level is reduced to 3/4th of the original concentration?
The desired concentration is (3/4) × 8% = 6%. The original 10 litres contain 10 × 0.08 = 0.8 litres of pure spice. If x litres of regular water are added, the new concentration is 0.8/(10 + x) = 0.06. Solving this equation gives 0.06(10 + x) = 0.8, leading to 0.06x = 0.2, which means x = 20/6 = 3.33Read more
The desired concentration is (3/4) × 8% = 6%. The original 10 litres contain 10 × 0.08 = 0.8 litres of pure spice. If x litres of regular water are added, the new concentration is 0.8/(10 + x) = 0.06. Solving this equation gives 0.06(10 + x) = 0.8, leading to 0.06x = 0.2, which means x = 20/6 = 3.33 litres (or 3 1/3 litres) of water must be added.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/
See lessA 600 mL solution with 5% salt is mixed with a 300 mL solution with 8% sugar. What are the concentrations of salt and sugar in the mixture? (i) Salt: 5%, Sugar: 8% (ii) Salt: 13%, Sugar: 3% (iii) Salt: 6%, Sugar: 6% (iv) Salt: 5.55%, Sugar: 8.88% (v) Salt: 3.33%, Sugar: 2.67% (vi) Salt: 4.1%, Sugar: 7.08%
The correct option is (v) Salt: 3.33%, Sugar: 2.67%. The first solution contains 30 mL of salt, while the second contains 24 mL of sugar. In the combined 900 mL mixture, the salt concentration is (30/900) × 100 = 3.33% and the sugar concentration is (24/900) × 100 = 2.67%. For more NCERT SoluRead more
The correct option is (v) Salt: 3.33%, Sugar: 2.67%. The first solution contains 30 mL of salt, while the second contains 24 mL of sugar. In the combined 900 mL mixture, the salt concentration is (30/900) × 100 = 3.33% and the sugar concentration is (24/900) × 100 = 2.67%.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/
See lessA white stork’s migration is tracked. The average daily distance travelled, calculated over 20 days, is 44.5 km. On the 21st day, it flew 55 km. What is the average daily distance travelled over these 21 days? Make a guess before you calculate.
Before calculating, since 55 km is higher than 44.5 km, the new average will rise slightly, perhaps around 45 km. Computing accurately, the total distance covered during the first 20 days is 890 km. Adding the 21st day's 55 km gives 945 km in total. Dividing 945 km by 21 days yields an exact averageRead more
Before calculating, since 55 km is higher than 44.5 km, the new average will rise slightly, perhaps around 45 km. Computing accurately, the total distance covered during the first 20 days is 890 km. Adding the 21st day’s 55 km gives 945 km in total. Dividing 945 km by 21 days yields an exact average daily distance of 45 km.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/
See lessA stationery shop owner made ₹8000 selling books, of which 30% is the profit amount, and ₹1000 selling book covers, of which 50% is the profit amount. What is the percentage of profit on the total sales?
The shopkeeper earns a profit of 30% on books, giving ₹2400 and 50% on book covers, giving ₹500. The total profit generated is ₹2900 on total sales of ₹9000. Hence, the overall profit percentage on total sales is (2900/9000) × 100, which equals approximately 32.22% (or 32 2/9%). For more NCERRead more
The shopkeeper earns a profit of 30% on books, giving ₹2400 and 50% on book covers, giving ₹500. The total profit generated is ₹2900 on total sales of ₹9000. Hence, the overall profit percentage on total sales is (2900/9000) × 100, which equals approximately 32.22% (or 32 2/9%).
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 10 How Quantities Combine Understanding Data Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-10/
See lessIf we list out the divisors in pairs, will our GCD algorithm still work in the manner we have described?
Not directly without modification. Our original algorithm assumes that the divisors appear in strictly increasing order so that the largest common factor is simply the rightmost element. Listing divisors in pairs—like (1, 18), (2, 9), (3, 6)—mixes small and large numbers together. To make the algoriRead more
Not directly without modification. Our original algorithm assumes that the divisors appear in strictly increasing order so that the largest common factor is simply the rightmost element. Listing divisors in pairs—like (1, 18), (2, 9), (3, 6)—mixes small and large numbers together. To make the algorithm work, we would first have to sort the combined list into ascending order.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 11 The World of Algorithms Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-11/
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