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Ashok0210

Asked: March 21, 2021In: Class 12 Physics

Suppose that the electric field amplitude of an electromagnetic wave is Eo = 120 N/C and that its frequency is v = 50.0 MHz. (a) Determine, Bo, ω, k, and λ. (b) Find expressions for E and B.

Class 12 Physics CBSE and UP Board Electromagnetic Waves Chapter-8 Exercise 8.8 NCERT Solutions for Class 12 Physics Chapter 8 Question 8

Ashok0210

Asked: March 21, 2021In: Class 12 Physics

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is Bo = 510 nT. What is the amplitude of the electric field part of the wave?

Class 12 Physics CBSE and UP Board Electromagnetic Waves Chapter-8 Exercise 8.7 NCERT Solutions for Class 12 Physics Chapter 8 Question 7

Ashok0210

Asked: March 21, 2021In: Class 12 Physics

A charged particle oscillates about its mean equilibrium position with a frequency of 10⁹ Hz. What is the frequency of the electromagnetic waves produced by the oscillator?

Class 12 Physics CBSE and UP Board Electromagnetic Waves Chapter-8 Exercise 8.6 NCERT Solutions for Class 12 Physics Chapter 8 Question 6

Ashok0210

Asked: March 21, 2021In: Class 12 Physics

A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

Class 12 Physics CBSE and UP Board Electromagnetic Waves Chapter-8 Exercise 8.5 NCERT Solutions for Class 12 Physics Chapter 8 Question 5

Ashok0210

Asked: March 21, 2021In: Class 12 Physics

A plane electromagnetic wave travels in vacuum along z-direction. What can you say about the directions of its electric and magnetic field vectors? If the frequency of the wave is 30 MHz, what is its wavelength?

Class 12 Physics CBSE and UP Board Electromagnetic Waves Chapter-8 Exercise 8.4 NCERT Solutions for Class 12 Physics Chapter 8 Question 4

Ashok0210

Asked: March 21, 2021In: Class 12 Physics

What physical quantity is the same for X-rays of wavelength 10⁻¹⁰ m, red light of wavelength 6800 A and radio waves of wavelength 500 m?

Class 12 Physics CBSE and UP Board Electromagnetic Waves Chapter-8 Exercise 8.3 NCERT Solutions for Class 12 Physics Chapter 8 Question 3

Ashok0210

Asked: March 21, 2021In: Class 12 Physics

A parallel plate capacitor (Fig. 8.7) made of circular plates each of radius R = 6.0 cm has a capacitance C=100pF.The capacitor is connected to a 230 V ac supply with a (angular) frequency of to a 230 V ac supply with a (angular) frequency of 300 rad s⁻¹. (a) What is the rms value of the conduction current? (b) Is the conduction current equal to the displacement current? (c) Determine the amplitude of B at a point 3.0 cm from the axis between the plates.

Class 12 Physics CBSE and UP Board Electromagnetic Waves Chapter-8 Exercise 8.2 NCERT Solutions for Class 12 Physics Chapter 8 Question 2

Ashok0210

Asked: March 21, 2021In: Class 12 Physics

Figure 8.6 shows a capacitor made of two circular plates each of radius 12 cm, and separated by 5.0 cm. The capacitor is being charged by an external source (not shown in the figure). The charging current is constant and equal to 0.15 A. (a) Calculate the capacitance and the rate of charge of potential difference between the plates. (b) Obtain the displacement current across the plates. (c) Is Kirchhoffs first rule (junction rule) valid at each plate of the capacitor? Explain.

Class 12 Physics CBSE and UP Board Electromagnetic Waves Chapter-8 Exercise 8.1 NCERT Solutions for Class 12 Physics Chapter 8 Question 1

Ashok0210

Asked: March 21, 2021In: Class 12 Physics

A prism is made of glass of unknown refractive index. A parallel beam of light is incident on a face of the prism. The angle of minimum deviation is measured to be 40°. What is the refractive index of the material of the prism? The refracting angle of the prism is 60°. If the prism is placed in water (refractive index 1.33), predict the new angle of minimum deviation of a parallel beam of light.

Class 12 Physics CBSE and UP Board Ray Optics and Optical Instruments Chapter-9 Exercise 9.6 NCERT Solutions for Class 12 Physics Chapter 9 Question-6

Ashok0210

Asked: March 21, 2021In: Class 12 Physics

A small bulb is placed at the bottom of a tank containing water to a depth of 80 cm. What is the area of the surface of water through which light from the bulb can emerge out? Refractive index of water is 1.33. (Consider the bulb to be a point source.)

Class 12 Physics CBSE and UP Board Ray Optics and Optical Instruments Chapter-9 Exercise 9.5 NCERT Solutions for Class 12 Physics Chapter 9 Question-5

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Vanishree Singh

Suppose that the electric field amplitude of an electromagnetic wave is Eo = 120 N/C and that its frequency is v = 50.0 MHz. (a) Determine, Bo, ω, k, and λ. (b) Find expressions for E and B.

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is Bo = 510 nT. What is the amplitude of the electric field part of the wave?

A charged particle oscillates about its mean equilibrium position with a frequency of 10⁹ Hz. What is the frequency of the electromagnetic waves produced by the oscillator?

A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

A plane electromagnetic wave travels in vacuum along z-direction. What can you say about the directions of its electric and magnetic field vectors? If the frequency of the wave is 30 MHz, what is its wavelength?

What physical quantity is the same for X-rays of wavelength 10⁻¹⁰ m, red light of wavelength 6800 A and radio waves of wavelength 500 m?

A small bulb is placed at the bottom of a tank containing water to a depth of 80 cm. What is the area of the surface of water through which light from the bulb can emerge out? Refractive index of water is 1.33. (Consider the bulb to be a point source.)

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