Home/ Vanie Singh/Answers
  1. Asked: In:

    Tell what property allows you to compute 1/3x(6×4/3) as (1/3×6) x4/3

    Best Answer
    Vanie Singh

    By using associative property of multiplication, ax(bxc)=(axb)xc. Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-1/

    By using associative property of multiplication, ax(bxc)=(axb)xc.

    Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-1/

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  2. Asked: In:

    Multiply 6/13 by the reciprocal of -7/16.

    Best Answer
    Vanie Singh

    The reciprocal of -7/16 is -16/7 According to the question, 6/13x(-16/7)=-96/91 Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-1/

    The reciprocal of -7/16 is -16/7
    According to the question,
    6/13x(-16/7)=-96/91

    Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-1/

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    • 3
  3. Asked: In:

    Name the property under multiplication used in each of the following: -4/5×1=1x-4/5

    Best Answer
    Vanie Singh

    (i) 1 is the multiplicative identity. (ii) Commutative property. (iii) Multiplicative Inverse property Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-1/

    (i) 1 is the multiplicative identity.
    (ii) Commutative property.
    (iii) Multiplicative Inverse property

    Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-1/

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  4. Asked: In:

    Find the multiplicative inverse of the following: -13

    Best Answer
    Vanie Singh

    We know that multiplicative inverse of a rational number is a (1/a), such that ax1/a=1. Multiplicative inverse of is -13 is -1/13. Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-1/

    We know that multiplicative inverse of a rational number is a (1/a), such that ax1/a=1.

    Multiplicative inverse of is -13 is -1/13.

    Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-1/

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    • 3
  6. Asked: In:

    Verify that for: -(-x) = x for: x=11/15

    Best Answer
    Vanie Singh

    Putting x=11/15 in -(-x)=x, -(-11/15)=11/15 ⇒ 11/15=11/15 ⇒ L.H.S. = R.H.S. Hence, verified. Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-1/

    Putting x=11/15 in -(-x)=x,
    -(-11/15)=11/15 ⇒ 11/15=11/15
    ⇒ L.H.S. = R.H.S.
    Hence, verified.

    Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-1/

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    • 3
  7. Asked: In:

    Write the additive inverse of each of the following: 2/8

    Best Answer
    Vanie Singh

    We know that additive inverse of a rational number a/b is (-a/b), such that a/b+(-a/b)=0 Additive inverse of 2/8 is -2/8 Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video

    We know that additive inverse of a rational number a/b is (-a/b), such that
    a/b+(-a/b)=0

    Additive inverse of 2/8 is -2/8

    Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video

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  8. Asked: In:

    Using appropriate properties find: (i) – 2/3×3/5+5/2-3/5×1/6 (ii) 2/5x (3/-7)-1/6×3/2+1/14×2/5

    Vanie Singh

    Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video

    Class 8 Maths Chapter 1 Exercise 1.1 Solution in Video

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  9. Asked: In:

    Using appropriate properties find: (i) – 2/3×3/5+5/2-3/5×1/6 (ii) 2/5x (3/-7)-1/6×3/2+1/14×2/5

    Best Answer
    Vanie Singh

    (i) -2/3x3/5+5/2-3/5x1/6 = -2/3x3/5-3/5x1/6+5/2 = 3/5 (-2/3-1/6) + 5/2 = 3/5 (-4-4)/6) + 5/2 = 3/5x-5/6+5/2 = -1/2+5/2 = -1+5/2 = 4/2 = 2 (ii) 2/5x(3/-7)-1/6×3/2+1/14×2/5 = 2/5x(-3/7)+1/14x2/5-1/6x3/2 = 2/5x  (-3/7+1/14)-1/4 = 2/5x(-6+1/14)-1/4=2/5x-5/14-1/4 = -1/7-1/4 = -4-7/28 = -11/8

    (i) -2/3×3/5+5/2-3/5×1/6 = -2/3×3/5-3/5×1/6+5/2

    = 3/5 (-2/3-1/6) + 5/2

    = 3/5 (-4-4)/6) + 5/2 = 3/5x-5/6+5/2

    = -1/2+5/2 = -1+5/2 = 4/2 = 2

    (ii) 2/5x(3/-7)-1/6×3/2+1/14×2/5

    = 2/5x(-3/7)+1/14×2/5-1/6×3/2

    = 2/5x  (-3/7+1/14)-1/4

    = 2/5x(-6+1/14)-1/4=2/5x-5/14-1/4

    = -1/7-1/4 = -4-7/28 = -11/8

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