1. (a) The equilateral triangle being a regular polygon of 3 sides has the least measure of an interior angle of 60° ∵ Sum of all the angles of a triangle = 180° ∴ x+x+x=180° ⇒ 3x = 180° ⇒ x=60° (b) By (a), we can observe that the greatest exterior angle is 180°-60°=120°. Class 8 Maths Chapter 3 ExerciRead more

    (a) The equilateral triangle being a regular polygon of 3 sides has the least measure of an
    interior angle of 60°
    ∵ Sum of all the angles of a triangle = 180°
    ∴ x+x+x=180°
    ⇒ 3x = 180°
    ⇒ x=60°
    (b) By (a), we can observe that the greatest exterior angle is 180°-60°=120°.

    Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/

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  2. (a) No. (Since 22 is not a divisor of 360° ) (b) No,(Because each exterior angle is 180°-22°=158°, which is not a divisor of360°) Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/

    (a) No. (Since 22 is not a divisor of 360° )
    (b) No,(Because each exterior angle is 180°-22°=158°, which is not a divisor of360°)

    Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/

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  3. Let number of sides be n. Exterior angle = 180°-165°=15° Sum of exterior angles of a regular polygon = 360° Number of sides = Sum of exterior angles/Each interior angle = 360°/15° = 24 Hence, the regular polygon has 24 sides. Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video for more answers viRead more

    Let number of sides be n.
    Exterior angle = 180°-165°=15°
    Sum of exterior angles of a regular polygon = 360°
    Number of sides = Sum of exterior angles/Each interior angle = 360°/15° = 24
    Hence, the regular polygon has 24 sides.

    Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/

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  4. Let number of sides be n. Sum of exterior angles of a regular polygon = 360° Number of sides = Sum of exterior angles/Each interior angle = 360°/24°=15 Hence, the regular polygon has 15 sides. Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video for more answers vist to: https://www.tiwariacademy.Read more

    Let number of sides be n.
    Sum of exterior angles of a regular polygon = 360°
    Number of sides = Sum of exterior angles/Each interior angle = 360°/24°=15
    Hence, the regular polygon has 15 sides.

    Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/

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  5. (i) Sum of angles of a regular polygon = (n-2) x 180° = (9-2)x180° =7x180°=1260° Each interior angle = Sum of interior angles/Number of sides =1260°/9=140° Each exterior angle = 180°-140°=40° (ii) Sum of exterior angles of a regular polygon = 360° Each interior angle = Sum of interior angles/NumberRead more

    (i) Sum of angles of a regular polygon = (n-2) x 180°
    = (9-2)x180° =7×180°=1260°
    Each interior angle = Sum of interior angles/Number of sides =1260°/9=140°
    Each exterior angle = 180°-140°=40°
    (ii) Sum of exterior angles of a regular polygon = 360°
    Each interior angle = Sum of interior angles/Number of sides = 360°/15=24°

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/

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