(a) The equilateral triangle being a regular polygon of 3 sides has the least measure of an interior angle of 60° ∵ Sum of all the angles of a triangle = 180° ∴ x+x+x=180° ⇒ 3x = 180° ⇒ x=60° (b) By (a), we can observe that the greatest exterior angle is 180°-60°=120°. Class 8 Maths Chapter 3 ExerciRead more
(a) The equilateral triangle being a regular polygon of 3 sides has the least measure of an
interior angle of 60°
∵ Sum of all the angles of a triangle = 180°
∴ x+x+x=180°
⇒ 3x = 180°
⇒ x=60°
(b) By (a), we can observe that the greatest exterior angle is 180°-60°=120°.
Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video
(a) No. (Since 22 is not a divisor of 360° ) (b) No,(Because each exterior angle is 180°-22°=158°, which is not a divisor of360°) Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
(a) No. (Since 22 is not a divisor of 360° )
(b) No,(Because each exterior angle is 180°-22°=158°, which is not a divisor of360°)
Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video
Let number of sides be n. Exterior angle = 180°-165°=15° Sum of exterior angles of a regular polygon = 360° Number of sides = Sum of exterior angles/Each interior angle = 360°/15° = 24 Hence, the regular polygon has 24 sides. Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video for more answers viRead more
Let number of sides be n.
Exterior angle = 180°-165°=15°
Sum of exterior angles of a regular polygon = 360°
Number of sides = Sum of exterior angles/Each interior angle = 360°/15° = 24
Hence, the regular polygon has 24 sides.
Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video
Let number of sides be n. Sum of exterior angles of a regular polygon = 360° Number of sides = Sum of exterior angles/Each interior angle = 360°/24°=15 Hence, the regular polygon has 15 sides. Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video for more answers vist to: https://www.tiwariacademy.Read more
Let number of sides be n.
Sum of exterior angles of a regular polygon = 360°
Number of sides = Sum of exterior angles/Each interior angle = 360°/24°=15
Hence, the regular polygon has 15 sides.
Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video
(i) Sum of angles of a regular polygon = (n-2) x 180° = (9-2)x180° =7x180°=1260° Each interior angle = Sum of interior angles/Number of sides =1260°/9=140° Each exterior angle = 180°-140°=40° (ii) Sum of exterior angles of a regular polygon = 360° Each interior angle = Sum of interior angles/NumberRead more
(i) Sum of angles of a regular polygon = (n-2) x 180°
= (9-2)x180° =7×180°=1260°
Each interior angle = Sum of interior angles/Number of sides =1260°/9=140°
Each exterior angle = 180°-140°=40°
(ii) Sum of exterior angles of a regular polygon = 360°
Each interior angle = Sum of interior angles/Number of sides = 360°/15=24°
Here, 125° + m = 180° [Linear pair] ⇒ m = 180 - 125° = 55° and 125°+n=180° [Linear pair] ⇒ n=180°-125° = 55° ∵ Exterior angle x° = Sum of opposite interior angles ∴x=55°+55°=110° (b) Sum of angles of a pentagon = (n-2) x 180° = (5-2) x 180° = 3x180°=540° By linear pairs of angles, ∠1 +90° = 180° ...Read more
Here, 125° + m = 180° [Linear pair]
⇒ m = 180 – 125° = 55°
and 125°+n=180° [Linear pair]
⇒ n=180°-125° = 55°
∵ Exterior angle x° = Sum of opposite interior angles
∴x=55°+55°=110°
(b) Sum of angles of a pentagon = (n-2) x 180°
= (5-2) x 180°
= 3×180°=540°
By linear pairs of angles,
∠1 +90° = 180° …………(i)
∠2 +60° = 180° …………(ii)
∠3 +90° = 180° …………(iii)
∠4 +70° =180° …………(iv)
∠5 +x = 180° …………(v)
(a) What is the minimum interior angle possible for a regular polygon? Why? (b) What is the maximum exterior angle possible for a regular polygon?
(a) The equilateral triangle being a regular polygon of 3 sides has the least measure of an interior angle of 60° ∵ Sum of all the angles of a triangle = 180° ∴ x+x+x=180° ⇒ 3x = 180° ⇒ x=60° (b) By (a), we can observe that the greatest exterior angle is 180°-60°=120°. Class 8 Maths Chapter 3 ExerciRead more
(a) The equilateral triangle being a regular polygon of 3 sides has the least measure of an
interior angle of 60°
∵ Sum of all the angles of a triangle = 180°
∴ x+x+x=180°
⇒ 3x = 180°
⇒ x=60°
(b) By (a), we can observe that the greatest exterior angle is 180°-60°=120°.
Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
(a) Is it possible to have a regular polygon with of each exterior angle as 22°? (b) Can it be an interior angle of a regular polygon? Why?
(a) No. (Since 22 is not a divisor of 360° ) (b) No,(Because each exterior angle is 180°-22°=158°, which is not a divisor of360°) Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
(a) No. (Since 22 is not a divisor of 360° )
(b) No,(Because each exterior angle is 180°-22°=158°, which is not a divisor of360°)
Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
How many sides does a regular polygon have if each of its interior angles is 165°?
Let number of sides be n. Exterior angle = 180°-165°=15° Sum of exterior angles of a regular polygon = 360° Number of sides = Sum of exterior angles/Each interior angle = 360°/15° = 24 Hence, the regular polygon has 24 sides. Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video for more answers viRead more
Let number of sides be n.
Exterior angle = 180°-165°=15°
Sum of exterior angles of a regular polygon = 360°
Number of sides = Sum of exterior angles/Each interior angle = 360°/15° = 24
Hence, the regular polygon has 24 sides.
Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
How many sides does a regular polygon have, if the measure of an exterior angle is 24°?
Let number of sides be n. Sum of exterior angles of a regular polygon = 360° Number of sides = Sum of exterior angles/Each interior angle = 360°/24°=15 Hence, the regular polygon has 15 sides. Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video for more answers vist to: https://www.tiwariacademy.Read more
Let number of sides be n.
Sum of exterior angles of a regular polygon = 360°
Number of sides = Sum of exterior angles/Each interior angle = 360°/24°=15
Hence, the regular polygon has 15 sides.
Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Find the measure of each exterior angle of a regular polygon of: (a) 9 sides (b) 15 sides
(i) Sum of angles of a regular polygon = (n-2) x 180° = (9-2)x180° =7x180°=1260° Each interior angle = Sum of interior angles/Number of sides =1260°/9=140° Each exterior angle = 180°-140°=40° (ii) Sum of exterior angles of a regular polygon = 360° Each interior angle = Sum of interior angles/NumberRead more
(i) Sum of angles of a regular polygon = (n-2) x 180°
= (9-2)x180° =7×180°=1260°
Each interior angle = Sum of interior angles/Number of sides =1260°/9=140°
Each exterior angle = 180°-140°=40°
(ii) Sum of exterior angles of a regular polygon = 360°
Each interior angle = Sum of interior angles/Number of sides = 360°/15=24°
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Find x in the following figures:
Here, 125° + m = 180° [Linear pair] ⇒ m = 180 - 125° = 55° and 125°+n=180° [Linear pair] ⇒ n=180°-125° = 55° ∵ Exterior angle x° = Sum of opposite interior angles ∴x=55°+55°=110° (b) Sum of angles of a pentagon = (n-2) x 180° = (5-2) x 180° = 3x180°=540° By linear pairs of angles, ∠1 +90° = 180° ...Read more
Here, 125° + m = 180° [Linear pair]
⇒ m = 180 – 125° = 55°
and 125°+n=180° [Linear pair]
⇒ n=180°-125° = 55°
∵ Exterior angle x° = Sum of opposite interior angles
∴x=55°+55°=110°
(b) Sum of angles of a pentagon = (n-2) x 180°
= (5-2) x 180°
= 3×180°=540°
By linear pairs of angles,
∠1 +90° = 180° …………(i)
∠2 +60° = 180° …………(ii)
∠3 +90° = 180° …………(iii)
∠4 +70° =180° …………(iv)
∠5 +x = 180° …………(v)
Adding eq. (i), (ii), (iii), (iv) and (v),
x + ( ∠1 + ∠2 + ∠3 + ∠4 +∠5) + 310° = 900
⇒ x+540°+310°=900° ⇒x+850°=900° ⇒x=900°-850°=50°
Class 8 Maths Chapter 3 Exercise 3.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/