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  1. Asked: In:

    The most appropriate definition of a natural resource is that it is a substance commodity that is (a) present only on land.(b) a gift of nature which is very useful to mankind. (c) a man-made substance placed in nature.(d) available only in the forest

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    Get Hindi Medium and English Medium NCERT Solution for Class 10 science to download Please visit to website https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-16/

    Get Hindi Medium and English Medium NCERT Solution for Class 10 science
    to download Please visit to website
    https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-16/

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    A mercury lamp is a convenient source for studying frequency dependence of photoelectric emission, since it gives a number of spectral lines ranging from the UV to the red end of the visible spectrum. In our experiment with rubidium photo-cell, the following lines from a mercury source were used: λ ₁ = 3650 Å, λ ₂= 4047 Å, λ ₃ = 4358 Å, λ₄ = 5461 Å, λ₅ = 6907 Å, The stopping voltages, respectively, were measured to be: V0₁ = 1.28 V, V0₂= 0.95 V, V0₃= 0.74 V, V0₄ = 0.16 V, V0₅ = 0 V Determine the value of Planck’s constant h, the threshold frequency and work function for the material. [Note: You will notice that to get h from the data, you will need to know e (which you can take to be 1.6 × 10⁻¹⁹C). Experiments of this kind on Na, Li, K, etc. were performed by Millikan, who, using his own value of e (from the oil-drop experiment) confirmed Einstein’s photoelectric equation and at the same time gave an independent estimate of the value of h.]

    Vadrmati

    Get Hindi Medium and English Medium NCERT Solution for Class 12 Social Science to download Please visit to website https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-11/

    Get Hindi Medium and English Medium NCERT Solution for Class 12 Social Science
    to download Please visit to website
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-11/

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  3. Asked: In:

    (a) A monoenergetic electron beam with electron speed of 5.20 × 10⁶ m s⁻¹ is subject to a magnetic field of 1.30 × 10⁻⁴ T normal to the beam velocity. What is the radius of the circle traced by the beam, given e/m for electron equals 1.76 × 10¹¹C kg⁻¹. (b) Is the formula you employ in (a) valid for calculating radius of the path of a 20 MeV electron beam? If not, in what way is it modified? [Note: Exercises 11.20(b) and 11.21(b) take you to relativistic mechanics which is beyond the scope of this book. They have been inserted here simply to emphasise the point that the formulas you use in part (a) of the exercises are not valid at very high speeds or energies. See answers at the end to know what ‘very high speed or energy’ means.]

    Vadrmati

    Get Hindi Medium and English Medium NCERT Solution for Class 12 Social Science to download Please visit to website https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-11/

    Get Hindi Medium and English Medium NCERT Solution for Class 12 Social Science
    to download Please visit to website
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-11/

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  4. Asked: In:

    The most rapidly dwindling natural resource in the world is

    Vadrmati

    Get Hindi Medium and English Medium NCERT Solution for Class 10 science to download Please visit to website https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-16/

    Get Hindi Medium and English Medium NCERT Solution for Class 10 science
    to download Please visit to website
    https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-16/

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  6. Asked: In:

    Tehri Dam is being constructed on

    Vadrmati

    Get Hindi Medium and English Medium NCERT Solution for Class 10 science to download Please visit to website https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-16/

    Get Hindi Medium and English Medium NCERT Solution for Class 10 science
    to download Please visit to website
    https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-16/

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