Weight of onions = 3 kg 500 g = 3.500 kg Weight of tomatoes = 2 kg 75 g = 2.075 kg Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg Therefore, weight of potatoes = 10.000 – 5.575 = 4.425 kg Thus, the weight of potatoes is 4.425 kg. https://www.tiwariacademy.com/ncert-solutions/class-6/Read more
Weight of onions = 3 kg 500 g = 3.500 kg
Weight of tomatoes = 2 kg 75 g = 2.075 kg
Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg
Therefore, weight of potatoes = 10.000 – 5.575 = 4.425 kg
Thus, the weight of potatoes is 4.425 kg.
Total distance travel = 20 km 50 m = 20.050 km Distance travelled by bus = 10 km 200 m = 10.200 km Distance travelled by auto = 20.050 – 10.200 = 9.850 km Therefore, 9.850 km distance travels by auto. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Total distance travel = 20 km 50 m = 20.050 km
Distance travelled by bus = 10 km 200 m = 10.200 km
Distance travelled by auto = 20.050 – 10.200 = 9.850 km
Therefore, 9.850 km distance travels by auto.
Before comparing, we write both terms in like decimals: (a) 0.3 0.02 (c) 3.0 or 0.8 ⇒ 3.0 > 0.8 (d) 0.50 or 0.05 ⇒ 0.50 > 0.05 (e) 1.23 or 1.20 ⇒ 1.23 > 1.20 (f) 0.099 or 0.190 ⇒ 0.099 < 0.190 (g) 1.50 or 1.50 ⇒ 1.50 = 1.50 (h) 1.431 5.603 (k) Five more examples: 1) 1.8 or 1.82 2) 1.0009Read more
Before comparing, we write both terms in like decimals:
(a) 0.3 0.02
(c) 3.0 or 0.8 ⇒ 3.0 > 0.8
(d) 0.50 or 0.05 ⇒ 0.50 > 0.05
(e) 1.23 or 1.20 ⇒ 1.23 > 1.20
(f) 0.099 or 0.190 ⇒ 0.099 < 0.190
(g) 1.50 or 1.50 ⇒ 1.50 = 1.50
(h) 1.431 5.603
(k) Five more examples:
1) 1.8 or 1.82
2) 1.0009 or 1.09
3) 10.01 or 100.1
4) 5.100 or 5.0100
5) 04.213 or 0421.3
Before comparing, we write both terms in like decimals
1) 1.80 or 1.82 ⇒ 1.82 is greater than 1.8
2) 1.0009 or 1.0900 ⇒ 1.09 is greater than 1.0009
3) 10.01 or 100.10 ⇒ 100.1 is greater than 10.01
4) 5.1000 or 5.0100 ⇒ 5.100 is greater than 5.0100
5) 04.213 or 0421.300 ⇒ 0421.3 is greater than 04.213
Aakash bought vegetables weighing 10 kg. Out of this 3 kg 500 g in onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes?
Weight of onions = 3 kg 500 g = 3.500 kg Weight of tomatoes = 2 kg 75 g = 2.075 kg Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg Therefore, weight of potatoes = 10.000 – 5.575 = 4.425 kg Thus, the weight of potatoes is 4.425 kg. https://www.tiwariacademy.com/ncert-solutions/class-6/Read more
Weight of onions = 3 kg 500 g = 3.500 kg
Weight of tomatoes = 2 kg 75 g = 2.075 kg
Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg
Therefore, weight of potatoes = 10.000 – 5.575 = 4.425 kg
Thus, the weight of potatoes is 4.425 kg.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessNamita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?
Total distance travel = 20 km 50 m = 20.050 km Distance travelled by bus = 10 km 200 m = 10.200 km Distance travelled by auto = 20.050 – 10.200 = 9.850 km Therefore, 9.850 km distance travels by auto. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Total distance travel = 20 km 50 m = 20.050 km
Distance travelled by bus = 10 km 200 m = 10.200 km
Distance travelled by auto = 20.050 – 10.200 = 9.850 km
Therefore, 9.850 km distance travels by auto.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessExpress as rupees using decimals: 5 paise
∴1 paisa = ₹ 1/100 ∴5 paise = 1/100x5 = ₹ 0.05 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
∴1 paisa = ₹ 1/100
∴5 paise = 1/100×5 = ₹ 0.05
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessWhich is greater: (a) 0.3 or 0.4 (b) 0.07 or 0.02 (c) 3 or 0.8 (d) 0.5 or 0.05 (e) 1.23 or 1.2 (f) 0.099 or 0.19 (g) 1.5 or 1.50 (h) 1.431 or 1.490 (i) 3.3 or 3.300 (j) 5.64 or 5.603 (k) Make five more examples and find the greater.
Before comparing, we write both terms in like decimals: (a) 0.3 0.02 (c) 3.0 or 0.8 ⇒ 3.0 > 0.8 (d) 0.50 or 0.05 ⇒ 0.50 > 0.05 (e) 1.23 or 1.20 ⇒ 1.23 > 1.20 (f) 0.099 or 0.190 ⇒ 0.099 < 0.190 (g) 1.50 or 1.50 ⇒ 1.50 = 1.50 (h) 1.431 5.603 (k) Five more examples: 1) 1.8 or 1.82 2) 1.0009Read more
Before comparing, we write both terms in like decimals:
(a) 0.3 0.02
(c) 3.0 or 0.8 ⇒ 3.0 > 0.8
(d) 0.50 or 0.05 ⇒ 0.50 > 0.05
(e) 1.23 or 1.20 ⇒ 1.23 > 1.20
(f) 0.099 or 0.190 ⇒ 0.099 < 0.190
(g) 1.50 or 1.50 ⇒ 1.50 = 1.50
(h) 1.431 5.603
(k) Five more examples:
1) 1.8 or 1.82
2) 1.0009 or 1.09
3) 10.01 or 100.1
4) 5.100 or 5.0100
5) 04.213 or 0421.3
Before comparing, we write both terms in like decimals
1) 1.80 or 1.82 ⇒ 1.82 is greater than 1.8
2) 1.0009 or 1.0900 ⇒ 1.09 is greater than 1.0009
3) 10.01 or 100.10 ⇒ 100.1 is greater than 10.01
4) 5.1000 or 5.0100 ⇒ 5.100 is greater than 5.0100
5) 04.213 or 0421.300 ⇒ 0421.3 is greater than 04.213
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessWrite as fractions in lowest terms: (a) 0.60 (b) 0.05 (c) 0.75 (d) 0.18 (e) 0.25 (f) 0.125 (g) 0.066
(a) 0.60 = 3/5 (b) 0.05 = 1/20 (c) 0.75 = 3/4 (d) 0.18 = 9/50 (e) 0.25 = 1/4 (f) 0.125 = 1/8 (g) 0.066 = 33/500 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
(a) 0.60 = 3/5
(b) 0.05 = 1/20
(c) 0.75 = 3/4
(d) 0.18 = 9/50
(e) 0.25 = 1/4
(f) 0.125 = 1/8
(g) 0.066 = 33/500
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See less