Weight of onions = 3 kg 500 g = 3.500 kg Weight of tomatoes = 2 kg 75 g = 2.075 kg Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg Therefore, weight of potatoes = 10.000 – 5.575 = 4.425 kg Thus, the weight of potatoes is 4.425 kg. https://www.tiwariacademy.com/ncert-solutions/class-6/Read more
Weight of onions = 3 kg 500 g = 3.500 kg
Weight of tomatoes = 2 kg 75 g = 2.075 kg
Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg
Therefore, weight of potatoes = 10.000 – 5.575 = 4.425 kg
Thus, the weight of potatoes is 4.425 kg.
Total distance travel = 20 km 50 m = 20.050 km Distance travelled by bus = 10 km 200 m = 10.200 km Distance travelled by auto = 20.050 – 10.200 = 9.850 km Therefore, 9.850 km distance travels by auto. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Total distance travel = 20 km 50 m = 20.050 km
Distance travelled by bus = 10 km 200 m = 10.200 km
Distance travelled by auto = 20.050 – 10.200 = 9.850 km
Therefore, 9.850 km distance travels by auto.
Total length of cloth = 20 m 5 cm = 20.05 m Length of cloth used = 4 m 50 cm = 4.50 m Remaining cloth = 20.05 m – 4.50 m = 15.55 m Therefore, 15.55 m of cloth is left with Tina. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Total length of cloth = 20 m 5 cm = 20.05 m
Length of cloth used = 4 m 50 cm = 4.50 m
Remaining cloth = 20.05 m – 4.50 m = 15.55 m
Therefore, 15.55 m of cloth is left with Tina.
Total amount given to shopkeeper = ₹50 Cost of book = ₹35.65 Amount left = ₹50.00 – ₹35.65 = ₹14.35 Therefore, Raju got back ₹14.35 from the shopkeeper. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Total amount given to shopkeeper = ₹50
Cost of book = ₹35.65
Amount left = ₹50.00 – ₹35.65
= ₹14.35
Therefore, Raju got back ₹14.35 from the shopkeeper.
Weight of Rice = 5 kg 400 g = 5.400 kg Weight of Sugar = 2 kg 20 g = 2.020 kg Weight of Flour = 10 kg 850 g = 10.850 kg Total weight = 5.400 + 2.020 + 10.850 = 18.270 kg Therefore, the total weight of Ravi’s purchase = 18.270 kg. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Weight of Rice = 5 kg 400 g = 5.400 kg
Weight of Sugar = 2 kg 20 g = 2.020 kg
Weight of Flour = 10 kg 850 g = 10.850 kg
Total weight = 5.400 + 2.020 + 10.850 = 18.270 kg
Therefore, the total weight of Ravi’s purchase = 18.270 kg.
Distance travelled by bus = 15 km 268 m = 15.268 km Distance travelled by car = 7 km 7 m = 7.007 km Distance travelled on foot = 500 m = 0.500 km Total distance travelled = 15.268 + 7.007 + 0.500 = 22.775 km Therefore, total distance travelled by Sunita is 22.775 km. https://www.tiwariacademy.com/ncRead more
Distance travelled by bus = 15 km 268 m = 15.268 km
Distance travelled by car = 7 km 7 m = 7.007 km
Distance travelled on foot = 500 m = 0.500 km
Total distance travelled = 15.268 + 7.007 + 0.500 = 22.775 km
Therefore, total distance travelled by Sunita is 22.775 km.
Distance travelled in morning = 2 km 35 m = 2.035 km Distance travelled in evening = 1 km 7 m = 1.007 km Total distance travelled = 2.035 + 1.007 = 3.042 km Therefore, the total distance travelled by Naresh is 3.042 km. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Distance travelled in morning = 2 km 35 m = 2.035 km
Distance travelled in evening = 1 km 7 m = 1.007 km
Total distance travelled = 2.035 + 1.007 = 3.042 km
Therefore, the total distance travelled by Naresh is 3.042 km.
Aakash bought vegetables weighing 10 kg. Out of this 3 kg 500 g in onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes?
Weight of onions = 3 kg 500 g = 3.500 kg Weight of tomatoes = 2 kg 75 g = 2.075 kg Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg Therefore, weight of potatoes = 10.000 – 5.575 = 4.425 kg Thus, the weight of potatoes is 4.425 kg. https://www.tiwariacademy.com/ncert-solutions/class-6/Read more
Weight of onions = 3 kg 500 g = 3.500 kg
Weight of tomatoes = 2 kg 75 g = 2.075 kg
Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg
Therefore, weight of potatoes = 10.000 – 5.575 = 4.425 kg
Thus, the weight of potatoes is 4.425 kg.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessNamita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?
Total distance travel = 20 km 50 m = 20.050 km Distance travelled by bus = 10 km 200 m = 10.200 km Distance travelled by auto = 20.050 – 10.200 = 9.850 km Therefore, 9.850 km distance travels by auto. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Total distance travel = 20 km 50 m = 20.050 km
Distance travelled by bus = 10 km 200 m = 10.200 km
Distance travelled by auto = 20.050 – 10.200 = 9.850 km
Therefore, 9.850 km distance travels by auto.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessTina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?
Total length of cloth = 20 m 5 cm = 20.05 m Length of cloth used = 4 m 50 cm = 4.50 m Remaining cloth = 20.05 m – 4.50 m = 15.55 m Therefore, 15.55 m of cloth is left with Tina. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Total length of cloth = 20 m 5 cm = 20.05 m
Length of cloth used = 4 m 50 cm = 4.50 m
Remaining cloth = 20.05 m – 4.50 m = 15.55 m
Therefore, 15.55 m of cloth is left with Tina.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessRani had ₹18.50. She bought one ice-cream for ₹11.75. How much money does she have now?
Total money = ₹18.50 Cost of Ice-cream = ₹11.75 Amount left = ₹18.50 – ₹11.75 = ₹6.75 Therefore, Rani has ₹6.75 now. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Total money = ₹18.50
Cost of Ice-cream = ₹11.75
Amount left = ₹18.50 – ₹11.75
= ₹6.75
Therefore, Rani has ₹6.75 now.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessRaju bought a book of ₹35.65. He gave ₹50 to the shopkeeper. How much money did he get back from the shopkeeper?
Total amount given to shopkeeper = ₹50 Cost of book = ₹35.65 Amount left = ₹50.00 – ₹35.65 = ₹14.35 Therefore, Raju got back ₹14.35 from the shopkeeper. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Total amount given to shopkeeper = ₹50
Cost of book = ₹35.65
Amount left = ₹50.00 – ₹35.65
= ₹14.35
Therefore, Raju got back ₹14.35 from the shopkeeper.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessFind the value of: 9.756 – 6.28
9 . 7 5 6 - 6 . 2 8 = 3 . 4 7 6 = 3.476 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
9 . 7 5 6 – 6 . 2 8
= 3 . 4 7 6
= 3.476
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessSubtract: ₹18.25 from ₹20.75
2 0 . 7 5 - 1 8 . 2 5 0 2 . 5 0 = ₹2.50 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
2 0 . 7 5 – 1 8 . 2 5
0 2 . 5 0
= ₹2.50
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessRavi purchases 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.
Weight of Rice = 5 kg 400 g = 5.400 kg Weight of Sugar = 2 kg 20 g = 2.020 kg Weight of Flour = 10 kg 850 g = 10.850 kg Total weight = 5.400 + 2.020 + 10.850 = 18.270 kg Therefore, the total weight of Ravi’s purchase = 18.270 kg. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Weight of Rice = 5 kg 400 g = 5.400 kg
Weight of Sugar = 2 kg 20 g = 2.020 kg
Weight of Flour = 10 kg 850 g = 10.850 kg
Total weight = 5.400 + 2.020 + 10.850 = 18.270 kg
Therefore, the total weight of Ravi’s purchase = 18.270 kg.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessSunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m by foot in order to reach her school. How far is her school from her residence?
Distance travelled by bus = 15 km 268 m = 15.268 km Distance travelled by car = 7 km 7 m = 7.007 km Distance travelled on foot = 500 m = 0.500 km Total distance travelled = 15.268 + 7.007 + 0.500 = 22.775 km Therefore, total distance travelled by Sunita is 22.775 km. https://www.tiwariacademy.com/ncRead more
Distance travelled by bus = 15 km 268 m = 15.268 km
Distance travelled by car = 7 km 7 m = 7.007 km
Distance travelled on foot = 500 m = 0.500 km
Total distance travelled = 15.268 + 7.007 + 0.500 = 22.775 km
Therefore, total distance travelled by Sunita is 22.775 km.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessNaresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?
Distance travelled in morning = 2 km 35 m = 2.035 km Distance travelled in evening = 1 km 7 m = 1.007 km Total distance travelled = 2.035 + 1.007 = 3.042 km Therefore, the total distance travelled by Naresh is 3.042 km. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Distance travelled in morning = 2 km 35 m = 2.035 km
Distance travelled in evening = 1 km 7 m = 1.007 km
Total distance travelled = 2.035 + 1.007 = 3.042 km
Therefore, the total distance travelled by Naresh is 3.042 km.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See less