Choice (a) is correct. As the coordinates of the centre are (3, 4) and radius = 4 because distance of a point (on x-axis) on a circle from the centre (3, 4) is the y-coordinates i.e., 4 so, the required equation is (x - 3)² + (y - 4)² = 4² This question related to Chapter 10 maths Class 11th NCERT.Read more
Choice (a) is correct.
As the coordinates of the centre are (3, 4) and radius = 4 because distance of a point (on x-axis) on a circle from the centre (3, 4) is the y-coordinates i.e., 4 so, the required equation is (x – 3)² + (y – 4)² = 4²
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
Choice (d) is correct. The given circle is x² + y² + 6x + 2y = 0 ⇒ x² + 6x + 9 + y² + 2y + 1 = 9 + 1 ⇒ (x + 3)² + (y + 1)² = 10 ⇒ {x - ( -3)}² = 10 Thus, the centre of the circle is (-3, -1). This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answerRead more
Choice (d) is correct.
The given circle is x² + y² + 6x + 2y = 0 ⇒ x² + 6x + 9 + y² + 2y + 1 = 9 + 1
⇒ (x + 3)² + (y + 1)² = 10 ⇒ {x – ( -3)}² = 10
Thus, the centre of the circle is (-3, -1).
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
Choice (a) is correct. Given circle is x² + y² = 4 ⇒ (x - 0)² + (y - 0)² = 2² ⇒ (0 - 0) is centre and 2 units is the radius of the given circle. Now, since ax + by + c = 0 is a diameter therefore (0, 0) must lie on it ⇒ a.0 + b.0 + c = 0 ⇒ 0 + 0 + c =0 ⇒ c =0 This question related to Chapter 10 maRead more
Choice (a) is correct.
Given circle is x² + y² = 4
⇒ (x – 0)² + (y – 0)² = 2²
⇒ (0 – 0) is centre and 2 units is the radius of the given circle.
Now, since ax + by + c = 0 is a diameter therefore (0, 0) must lie on it
⇒ a.0 + b.0 + c = 0
⇒ 0 + 0 + c =0
⇒ c =0
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
The equation of the directrix of the parabola y² = -8x is
Choice (a) is correct. As the coordinates of the centre are (3, 4) and radius = 4 because distance of a point (on x-axis) on a circle from the centre (3, 4) is the y-coordinates i.e., 4 so, the required equation is (x - 3)² + (y - 4)² = 4² This question related to Chapter 10 maths Class 11th NCERT.Read more
Choice (a) is correct.
As the coordinates of the centre are (3, 4) and radius = 4 because distance of a point (on x-axis) on a circle from the centre (3, 4) is the y-coordinates i.e., 4 so, the required equation is (x – 3)² + (y – 4)² = 4²
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
The centre of the circle x² + y² + 6x + 2y = 0 is
Choice (d) is correct. The given circle is x² + y² + 6x + 2y = 0 ⇒ x² + 6x + 9 + y² + 2y + 1 = 9 + 1 ⇒ (x + 3)² + (y + 1)² = 10 ⇒ {x - ( -3)}² = 10 Thus, the centre of the circle is (-3, -1). This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answerRead more
Choice (d) is correct.
The given circle is x² + y² + 6x + 2y = 0 ⇒ x² + 6x + 9 + y² + 2y + 1 = 9 + 1
⇒ (x + 3)² + (y + 1)² = 10 ⇒ {x – ( -3)}² = 10
Thus, the centre of the circle is (-3, -1).
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
If the line ax + by + c = 0 is a diameter of the circle x² + y² = 4, then the value of c is
Choice (a) is correct. Given circle is x² + y² = 4 ⇒ (x - 0)² + (y - 0)² = 2² ⇒ (0 - 0) is centre and 2 units is the radius of the given circle. Now, since ax + by + c = 0 is a diameter therefore (0, 0) must lie on it ⇒ a.0 + b.0 + c = 0 ⇒ 0 + 0 + c =0 ⇒ c =0 This question related to Chapter 10 maRead more
Choice (a) is correct.
Given circle is x² + y² = 4
⇒ (x – 0)² + (y – 0)² = 2²
⇒ (0 – 0) is centre and 2 units is the radius of the given circle.
Now, since ax + by + c = 0 is a diameter therefore (0, 0) must lie on it
⇒ a.0 + b.0 + c = 0
⇒ 0 + 0 + c =0
⇒ c =0
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10