Using Ohm’s law: V=IR Given: V=200V, R = 100Ω Current: I = V/R = 200/100 =2A Charge flow in 1 second: Q = I × t = 2 × 1 = 2C Number of electrons: n = ...
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The electric potential due to a dipole at a point on its axial line at a distance r from its center is given by: V = 1/4πϵ0 p/r² where p is the dipole moment. On the equatorial line of a ...
Total initial charge: (+3e)+(+5e)+(−3e)=5e When conductors touch, charge redistributes while conserving total charge. The total charge remains 5e, so the final charges must sum to 5e. Now, checking the options: Possible answers: (b) and (c). Class 12th Science Physics NCERT ...
Object X is negatively charged and is repelled by object Y, meaning Y must also be negatively charged. Object Z is attracted to object Y. Since Y is negative, Z could be positively charged (opposite charges attract) or neutral (neutral ...
The charge of one electron is − 1.6 × 10−¹⁹ C. The object gains 5.0 × 10¹⁸ electrons, resulting in a charge change of: q = (5.0 × 10¹⁸) × (−1.6×10⁻¹⁹) = −0.80C Net charge = 1C−0.80C= +0.20C. Correct answer: ...