This statement is sometimes true. For example, 2 + 2 = 4 (a multiple of 4), but 2 + 6 = 8 (not always divisible by 4). It depends on the specific even numbers. Class 6 Mathematics Ganita Prakash Prime Time Class ...
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The smallest number is 2520. It is the least common multiple (LCM) of the numbers 1 to 10, calculated using their prime factorizations: 2³ × 3² × 5 × 7 = 2520. Class 6 Mathematics Ganita Prakash Prime Time Class 6 Mathematics ...
The smallest number is 2520 ÷ 7 = 360. The least common multiple (LCM) of numbers 1 to 10 is 2520. Excluding 7, dividing 2520 by 7 gives the smallest valid number, 360. Class 6 Mathematics Ganita Prakash Prime Time Class 6 ...
Co-prime pairs are: Co-prime numbers are two numbers that share no common factors other than 1. Their greatest common divisor (GCD) is 1. Examples include (8, 15) and (21, 22), which have no shared prime factors. (18, 35): GCD = 1 (15, ...
The smallest 4-digit palindrome divisible by 4 is 2002, and the largest is 9999. Both numbers meet the conditions for divisibility and being palindromes when checked through divisibility tests. class 6 Mathematics Textbook Chapter 5 question answer class 6 Mathematics Chapter 5 ...
A number is divisible by 4 if the number formed by its last two digits is divisible by 4. For example, 132 is divisible by 4 because 32 (the last two digits) is divisible by 4. Between 1730 and 1740: ...
The numbers divisible by 4 in this range are 332 and 336. Dividing these numbers by 4 yields whole numbers: 332 ÷ 4 = 83 and 336 ÷ 4 = 84. class 6 Mathematics Textbook Chapter 5 question answer class 6 Mathematics ...
Changing the last two digits to 56 makes the number divisible by 8. For example, 8556 is a multiple of 8 because 8556 ÷ 8 = 1069 with no remainder. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 Mathematics ...
The two numbers are 25 and 400. Their product 25 × 400 = 10000 satisfies the condition. Both numbers end in digits other than 0, meeting the given requirements. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 Mathematics Textbook ...
Only 5600, 6000, and 77622160 are divisible by all. Divisibility by 2, 4, 5, 8, and 10 requires multiples of their least common multiple (LCM), 40. These numbers meet the criteria. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 ...