(a) False. Since, squares have all sides are equal. (b) True. Since, in rhombus, opposite angles are equal and diagonals intersect at mid-point. (c) True. Since, squares have the same property of rhombus but not a rectangle. (d) False. Since, all squares have the same property of parallelogram. (e)Read more
(a) False. Since, squares have all sides are equal.
(b) True. Since, in rhombus, opposite angles are equal and diagonals intersect at mid-point.
(c) True. Since, squares have the same property of rhombus but not a rectangle.
(d) False. Since, all squares have the same property of parallelogram.
(e) False. Since, all kites do not have equal sides.
(f) True. Since, all rhombuses have equal sides and diagonals bisect each other.
(g) True. Since, trapezium has only two parallel sides.
(h) True. Since, all squares have also two parallel lines.
Class 8 Maths Chapter 3 Exercise 3.4 Solution in Video
Yes, one more method is there to find ∠P.
∠s + ∠R + ∠Q+ ∠P=360° [Angle sum property of quadrilateral]
⇒ 90°+90° + 130°+ ∠p=360°
⇒ 310°+ ∠P=360°
⇒ ∠P=360°-310°
⇒ ∠P=50°
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
Here, ∠m+ ∠L= 100°+80°=180° [Sum of interior opposite angles is ] 180° ∴ NM and KL are parallel. Hence, KLMN is a trapezium. Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Here, ∠m+ ∠L= 100°+80°=180°
[Sum of interior opposite angles is ] 180°
∴ NM and KL are parallel.
Hence, KLMN is a trapezium.
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
In parallelogram RISK, ∠RIS = ∠=120° [Angles of linear pair] Opposite angles of a ||ᵍᵐ are equal] ∠m+120°=180° [Linear pair] ⇒ ∠m+180°-120°=60° and ∠ECI = ∠L=70° [Corresponding angles] ⇒ m+n+∠ECI=180° [Angle sum property of a triangle] ⇒60°+n+70°=180° ⇒ 130°+n=180° ⇒ n=180°-130°=50° also x = n = 50°Read more
In parallelogram RISK,
∠RIS = ∠=120° [Angles of linear pair]
Opposite angles of a ||ᵍᵐ are equal]
∠m+120°=180° [Linear pair]
⇒ ∠m+180°-120°=60°
and ∠ECI = ∠L=70°
[Corresponding angles]
⇒ m+n+∠ECI=180°
[Angle sum property of a triangle]
⇒60°+n+70°=180°
⇒ 130°+n=180°
⇒ n=180°-130°=50°
also x = n = 50°
[Vertically opposite angles]
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
State whether true or false: (a) All rectangles are squares. (b) All rhombuses are parallelograms. (c) All squares are rhombuses and also rectangles. (d) All squares are not parallelograms. (e) All kites are rhombuses. (f) All rhombuses are kites. (g) All parallelograms are trapeziums. (h) All squares are trapeziums.
(a) False. Since, squares have all sides are equal. (b) True. Since, in rhombus, opposite angles are equal and diagonals intersect at mid-point. (c) True. Since, squares have the same property of rhombus but not a rectangle. (d) False. Since, all squares have the same property of parallelogram. (e)Read more
(a) False. Since, squares have all sides are equal.
(b) True. Since, in rhombus, opposite angles are equal and diagonals intersect at mid-point.
(c) True. Since, squares have the same property of rhombus but not a rectangle.
(d) False. Since, all squares have the same property of parallelogram.
(e) False. Since, all kites do not have equal sides.
(f) True. Since, all rhombuses have equal sides and diagonals bisect each other.
(g) True. Since, trapezium has only two parallel sides.
(h) True. Since, all squares have also two parallel lines.
Class 8 Maths Chapter 3 Exercise 3.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Find the measure of ∠P and ∠S if 𝑆̅̅𝑃̅||𝑅̅̅𝑄̅ in given figure. (If you find m∠R is there more than one method to find m∠P)
Here, ∠P+ ∠Q 180° [Sum of co-interior angles is 180°] ⇒ ∠P+130°=180° ⇒ ∠P=180°-130° ⇒ ∠P=50° ∵ ∠R=90° [Given] ∴ ∠S+90°=180° ⇒ ∠S=180°-90° ⇒ ∠S= 90° Yes, one more method is there to find ∠P. ∠s + ∠R + ∠Q+ ∠P=360° [Angle sum property of quadrilateral] ⇒ 90°+90° + 130°+ ∠p=360° ⇒ 310°+ ∠P=360° ⇒ ∠P=360Read more
Here, ∠P+ ∠Q 180° [Sum of co-interior angles is 180°]
⇒ ∠P+130°=180°
⇒ ∠P=180°-130°
⇒ ∠P=50°
∵ ∠R=90° [Given]
∴ ∠S+90°=180°
⇒ ∠S=180°-90°
⇒ ∠S= 90°
Yes, one more method is there to find ∠P.
∠s + ∠R + ∠Q+ ∠P=360° [Angle sum property of quadrilateral]
⇒ 90°+90° + 130°+ ∠p=360°
⇒ 310°+ ∠P=360°
⇒ ∠P=360°-310°
⇒ ∠P=50°
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Explain how this figure is a trapezium. Which is its two sides are parallel?
Here, ∠m+ ∠L= 100°+80°=180° [Sum of interior opposite angles is ] 180° ∴ NM and KL are parallel. Hence, KLMN is a trapezium. Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Here, ∠m+ ∠L= 100°+80°=180°
[Sum of interior opposite angles is ] 180°
∴ NM and KL are parallel.
Hence, KLMN is a trapezium.
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
In the figure, both RISK and CLUE are parallelograms. Find the value of x.
In parallelogram RISK, ∠RIS = ∠=120° [Angles of linear pair] Opposite angles of a ||ᵍᵐ are equal] ∠m+120°=180° [Linear pair] ⇒ ∠m+180°-120°=60° and ∠ECI = ∠L=70° [Corresponding angles] ⇒ m+n+∠ECI=180° [Angle sum property of a triangle] ⇒60°+n+70°=180° ⇒ 130°+n=180° ⇒ n=180°-130°=50° also x = n = 50°Read more
In parallelogram RISK,
∠RIS = ∠=120° [Angles of linear pair]
Opposite angles of a ||ᵍᵐ are equal]
∠m+120°=180° [Linear pair]
⇒ ∠m+180°-120°=60°
and ∠ECI = ∠L=70°
[Corresponding angles]
⇒ m+n+∠ECI=180°
[Angle sum property of a triangle]
⇒60°+n+70°=180°
⇒ 130°+n=180°
⇒ n=180°-130°=50°
also x = n = 50°
[Vertically opposite angles]
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
The adjacent figure HOPW is a parallelogram. Find the angle measures x, y and z. State the properties you use to find them.
Here ∠HOP + 70° = 180° [Angles of linear pair] ∠HOP=180°-70° = 180° and ∠E= ∠HOP [Opposite angles of a ||ᵍᵐare equal] ⇒ x=100° ∠PHE= ∠HPO [Alternate angles] ∴ y=40° Now ∠EHO= ∠O=70° [Corresponding angles] ⇒40°+Z=70° ⇒Z=70°-40° = 30° Hence, x=110°,y=40° and z=30° Class 8 Maths Chapter 3 Exercise 3.3Read more
Here ∠HOP + 70° = 180° [Angles of linear pair]
∠HOP=180°-70° = 180°
and ∠E= ∠HOP [Opposite angles of a ||ᵍᵐare equal]
⇒ x=100°
∠PHE= ∠HPO [Alternate angles]
∴ y=40°
Now ∠EHO= ∠O=70° [Corresponding angles]
⇒40°+Z=70°
⇒Z=70°-40° = 30°
Hence, x=110°,y=40° and z=30°
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/