Let each adjacent angle be x. ∴ x+x=180° ⇒ 2x=180° ⇒ x=180°/2 =90° Hence, each adjacent angle is 90° ∴ x+x+x=180° ⇒ 3x=180° ⇒ x=60° Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Let each adjacent angle be x.
∴ x+x=180° ⇒ 2x=180° ⇒ x=180°/2 =90°
Hence, each adjacent angle is 90°
∴ x+x+x=180° ⇒ 3x=180° ⇒ x=60°
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
Let two adjacent angles be 3x and 2 . x Since the adjacent angles in a parallelogram are supplementary. ∴ 3x+2x=180° ⇒ 5x=180°/5=36° ∴ One angle = 3x=3x36°=108° and another angle = 2x= 2x36° =72° Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video for more answers vist to: https://www.tiwariacadeRead more
Let two adjacent angles be 3x and 2 . x
Since the adjacent angles in a parallelogram are supplementary.
∴ 3x+2x=180°
⇒ 5x=180°/5=36°
∴ One angle = 3x=3×36°=108°
and another angle = 2x= 2×36° =72°
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
ABCD is a quadrilateral in which angles ∠A = ∠C = 110°.Therefore, it could be a kite. Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
ABCD is a quadrilateral in which angles ∠A = ∠C = 110°.Therefore, it could be a kite.
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
(i) ∠ D + ∠ B = 180° It can be, but here, it needs not to be. (ii) No, in this case because one pair of opposite sides are equal and another pair of opposite sides are unequal. So, it is not a parallelogram. (iii) No. ∠A ≠ ∠C. Since opposite angles are equal in parallelogram and here opposite anglesRead more
(i) ∠ D + ∠ B = 180° It can be, but here, it needs not to be.
(ii) No, in this case because one pair of opposite sides are equal and another pair of opposite sides are unequal. So, it is not a parallelogram.
(iii) No. ∠A ≠ ∠C. Since opposite angles are equal in parallelogram and here opposite angles are not equal in quadrilateral ABCD. Therefore it is not aparallelogram.
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
(i) AD = BC [Since opposite sides of a parallelogram are equal] (ii) ∠DCB = ∠DAB [Since opposite angles of a parallelogram are equal] (iii) OC = OA [Since diagonals of a parallelogram bisect each other] (iv) m ∠DAB+m∠CDA = 180° [Adjacent angles in a parallelogram are supplementary] Class 8 Maths ChaRead more
(i) AD = BC [Since opposite sides of a parallelogram are equal]
(ii) ∠DCB = ∠DAB [Since opposite angles of a parallelogram are equal]
(iii) OC = OA [Since diagonals of a parallelogram bisect each other]
(iv) m ∠DAB+m∠CDA = 180°
[Adjacent angles in a parallelogram are supplementary]
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
Two adjacent angles of a parallelogram have equal measure. Find the measure of the angles of the parallelogram.
Let each adjacent angle be x. ∴ x+x=180° ⇒ 2x=180° ⇒ x=180°/2 =90° Hence, each adjacent angle is 90° ∴ x+x+x=180° ⇒ 3x=180° ⇒ x=60° Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Let each adjacent angle be x.
∴ x+x=180° ⇒ 2x=180° ⇒ x=180°/2 =90°
Hence, each adjacent angle is 90°
∴ x+x+x=180° ⇒ 3x=180° ⇒ x=60°
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
The measure of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.
Let two adjacent angles be 3x and 2 . x Since the adjacent angles in a parallelogram are supplementary. ∴ 3x+2x=180° ⇒ 5x=180°/5=36° ∴ One angle = 3x=3x36°=108° and another angle = 2x= 2x36° =72° Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video for more answers vist to: https://www.tiwariacadeRead more
Let two adjacent angles be 3x and 2 . x
Since the adjacent angles in a parallelogram are supplementary.
∴ 3x+2x=180°
⇒ 5x=180°/5=36°
∴ One angle = 3x=3×36°=108°
and another angle = 2x= 2×36° =72°
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Draw a rough figure of a quadrilateral that is not a parallelogram but has exactly two opposite angles of equal measures.
ABCD is a quadrilateral in which angles ∠A = ∠C = 110°.Therefore, it could be a kite. Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
ABCD is a quadrilateral in which angles ∠A = ∠C = 110°.Therefore, it could be a kite.
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Can a quadrilateral ABCD be a parallelogram, if: (i) ∠D+ ∠B=180°? (ii) AB = DC = 8 cm, AD = 4 cm and BC = 4.4 cm? (iii) ∠A=70° and ∠c=65°?
(i) ∠ D + ∠ B = 180° It can be, but here, it needs not to be. (ii) No, in this case because one pair of opposite sides are equal and another pair of opposite sides are unequal. So, it is not a parallelogram. (iii) No. ∠A ≠ ∠C. Since opposite angles are equal in parallelogram and here opposite anglesRead more
(i) ∠ D + ∠ B = 180° It can be, but here, it needs not to be.
(ii) No, in this case because one pair of opposite sides are equal and another pair of opposite sides are unequal. So, it is not a parallelogram.
(iii) No. ∠A ≠ ∠C. Since opposite angles are equal in parallelogram and here opposite angles are not equal in quadrilateral ABCD. Therefore it is not aparallelogram.
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/
Given a parallelogram ABCD. Complete each statement along with the definition or property used. (i) AD = __________ (ii) ∠DCB = __________ (iii) OC = __________ (iv) m∠DAB + m∠cda=__________
(i) AD = BC [Since opposite sides of a parallelogram are equal] (ii) ∠DCB = ∠DAB [Since opposite angles of a parallelogram are equal] (iii) OC = OA [Since diagonals of a parallelogram bisect each other] (iv) m ∠DAB+m∠CDA = 180° [Adjacent angles in a parallelogram are supplementary] Class 8 Maths ChaRead more
(i) AD = BC [Since opposite sides of a parallelogram are equal]
(ii) ∠DCB = ∠DAB [Since opposite angles of a parallelogram are equal]
(iii) OC = OA [Since diagonals of a parallelogram bisect each other]
(iv) m ∠DAB+m∠CDA = 180°
[Adjacent angles in a parallelogram are supplementary]
Class 8 Maths Chapter 3 Exercise 3.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-3/