Time taken by jaidev =11/5 minutes Time taken by Rahul =7/4 minutes Difference =11/5-7/4=11x4-7x5/20 [ L.C.M. of 5 and 4 is 20] = 44-35/20 = 9/20 minutes Thus, Rahul takes less time, which is 9/20 minutes. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
Time taken by jaidev =11/5 minutes
Time taken by Rahul =7/4 minutes
Difference =11/5-7/4=11×4-7×5/20 [ L.C.M. of 5 and 4 is 20]
= 44-35/20 = 9/20 minutes
Thus, Rahul takes less time, which is 9/20 minutes.
Total distance between school and house = 9/10km Distance covered by bus = 1/2 km Remaining distance= 9/10-1/2=9x1-1x5/10 [L.C.M. of 10 and 2 is 10] = 9-5/10=2/5 km. Therefore, the distance covered by walking us 2/5 km https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
Total distance between school and house = 9/10km
Distance covered by bus = 1/2 km
Remaining distance= 9/10-1/2=9×1-1×5/10 [L.C.M. of 10 and 2 is 10]
= 9-5/10=2/5 km.
Therefore, the distance covered by walking us 2/5 km
Total length of wire = 7/8 meter Length of first part = 1/4 meter Remaining part = 7/8-1/4=7x1-2x1/8 = 7-2/8=5/8 meter Therefore, the length of remaining part is 5/8 meter. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
Total length of wire = 7/8 meter
Length of first part = 1/4 meter
Remaining part = 7/8-1/4=7×1-2×1/8
= 7-2/8=5/8 meter
Therefore, the length of remaining part is 5/8 meter.
Cake taken by Naina = 3/2 piece and Cake taken by Najma = 4/3 piece Total cake taken = 3/2+4/3 = 3/2+4/3 = 3x3+4x2/6 [ L.C.M. of 2 and 3 is 6] = 9+8/6=17/6 = 9/8/6 = 17/6 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
Cake taken by Naina = 3/2 piece and Cake taken by Najma = 4/3 piece
Total cake taken = 3/2+4/3 = 3/2+4/3
= 3×3+4×2/6 [ L.C.M. of 2 and 3 is 6]
= 9+8/6=17/6
= 9/8/6 = 17/6
Ribbon bought by Sarita = 2/5 m and Ribbon bought by Lalita = 3/4m Total length of ribbon = 2/5+3/4 = 2x4+5x3/20 [L.C.M. of 5 and 4 is 20] = 8+15/20 = 23/20 = 23/20 Therefore, they bought 23/20 m of ribbon. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
Ribbon bought by Sarita = 2/5 m and Ribbon bought by Lalita = 3/4m
Total length of ribbon = 2/5+3/4
= 2×4+5×3/20 [L.C.M. of 5 and 4 is 20]
= 8+15/20 = 23/20 = 23/20
Therefore, they bought 23/20 m of ribbon.
Jaidev takes 11/5 minutes to walk across the school ground. Rahul takes 7/4 minutes to do same. Who takes less time and by what fraction?
Time taken by jaidev =11/5 minutes Time taken by Rahul =7/4 minutes Difference =11/5-7/4=11x4-7x5/20 [ L.C.M. of 5 and 4 is 20] = 44-35/20 = 9/20 minutes Thus, Rahul takes less time, which is 9/20 minutes. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
Time taken by jaidev =11/5 minutes
Time taken by Rahul =7/4 minutes
Difference =11/5-7/4=11×4-7×5/20 [ L.C.M. of 5 and 4 is 20]
= 44-35/20 = 9/20 minutes
Thus, Rahul takes less time, which is 9/20 minutes.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
See lessNandini house is 9/10 km from her school. She walked some distance and then took a bus for ½ km to reach the school. How far did she walk?
Total distance between school and house = 9/10km Distance covered by bus = 1/2 km Remaining distance= 9/10-1/2=9x1-1x5/10 [L.C.M. of 10 and 2 is 10] = 9-5/10=2/5 km. Therefore, the distance covered by walking us 2/5 km https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
Total distance between school and house = 9/10km
Distance covered by bus = 1/2 km
Remaining distance= 9/10-1/2=9×1-1×5/10 [L.C.M. of 10 and 2 is 10]
= 9-5/10=2/5 km.
Therefore, the distance covered by walking us 2/5 km
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
See lessA piece of wire 7/8 meter-long broke into two pieces. One piece was ¼ meter long. How long is the other piece?
Total length of wire = 7/8 meter Length of first part = 1/4 meter Remaining part = 7/8-1/4=7x1-2x1/8 = 7-2/8=5/8 meter Therefore, the length of remaining part is 5/8 meter. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
Total length of wire = 7/8 meter
Length of first part = 1/4 meter
Remaining part = 7/8-1/4=7×1-2×1/8
= 7-2/8=5/8 meter
Therefore, the length of remaining part is 5/8 meter.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
See lessNaina was given ¾ piece of cake and Najma was given 4/3 piece of cake. Find the total amount of cake given to both of them.
Cake taken by Naina = 3/2 piece and Cake taken by Najma = 4/3 piece Total cake taken = 3/2+4/3 = 3/2+4/3 = 3x3+4x2/6 [ L.C.M. of 2 and 3 is 6] = 9+8/6=17/6 = 9/8/6 = 17/6 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
Cake taken by Naina = 3/2 piece and Cake taken by Najma = 4/3 piece
Total cake taken = 3/2+4/3 = 3/2+4/3
= 3×3+4×2/6 [ L.C.M. of 2 and 3 is 6]
= 9+8/6=17/6
= 9/8/6 = 17/6
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
See lessSarika bought 2/5 meter of ribbon and Lalita 3/4 meter of ribbon. What is the total length of the ribbon they bought?
Ribbon bought by Sarita = 2/5 m and Ribbon bought by Lalita = 3/4m Total length of ribbon = 2/5+3/4 = 2x4+5x3/20 [L.C.M. of 5 and 4 is 20] = 8+15/20 = 23/20 = 23/20 Therefore, they bought 23/20 m of ribbon. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
Ribbon bought by Sarita = 2/5 m and Ribbon bought by Lalita = 3/4m
Total length of ribbon = 2/5+3/4
= 2×4+5×3/20 [L.C.M. of 5 and 4 is 20]
= 8+15/20 = 23/20 = 23/20
Therefore, they bought 23/20 m of ribbon.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-7/
See less