Username*
E-Mail*
Password*
Confirm Password*
Captcha* Click on image to update the captcha.
Username or email*
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
You must login to ask question.
(D) 90 m s = area of BCHF = BC X BF = 6 X 15 = 90 m
(C) 80 m s = area under v-t graph = 1/2 (AG + BF) GF = 1/2 (5 + 15) 8 = 80 m
The displacement of the body from t = 8 s to t = 14 s is:
(D) 90 m s = area of BCHF = BC X BF = 6 X 15 = 90 m
(D) 90 m
See lesss = area of BCHF
= BC X BF
= 6 X 15
= 90 m
What is the displacement of the body in first 8 second of the motion?
(C) 80 m s = area under v-t graph = 1/2 (AG + BF) GF = 1/2 (5 + 15) 8 = 80 m
(C) 80 m
See lesss = area under v-t graph
= 1/2 (AG + BF) GF
= 1/2 (5 + 15) 8
= 80 m