The possible outcomes when a dice is thrown = {1, 2, 3, 4, 5,6}
Number of possible outcomes of a dice = 6
(i) Prime numbers on a dice are 2, 3, and 5.
Total prime numbers on a dice = 3
Probability of getting a prime number = 3/6 = 1/2
(ii) Numbers lying between 2 and 6 = 3, 4, 5
Total numbers lying between 2 and 6 = 3
Probability of getting a number lying between 2 and 6 = 3/6 = 1/2
(iii) Odd numbers on a dice = 1, 3, and 5
Total odd numbers on a dice = 3
Probability of getting an odd number = 3/6 = 1/2

(i) Total number of cards = 5
Total number of queens = 1
P(getting a queen) = (Number of favourable outcomes)/(Number of total possible outcomes) = 1/5
(ii) When the queen is drawn and put aside, the total number of remaining cards will be 4.
(a) Total number of aces = 1
P(getting Ace) = (Number of favourable outcomes) = 1/4
(b) As queen is already drawn, therefore, the number of queens will be 0.
P(getting a queen) = (Number of favourable outcomes)/(Number of total possible outcomes) = 0/4 = 0

(i) Total number ofbulbs = 20
Total number of defective bulbs =4
P(getting a defective bulb) = (Number of favourable outcomes)/(Number of total possible outcomes) = 4/20 = 1/5
(ii) Remaining total number of bulbs = 19
Remaining total number of non-defective bulbs = 16 – 1 = 15
P(getting a not defective bulb) = (Number of favourable outcomes)/(Number of total possible outcomes) = 15/19