Distance covered by car = 57336.0 km - 57321.0 km = 15.0 km Time taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hour So, speed in km/min Speed= ๐ท๐๐ ๐ก๐๐๐๐ ๐๐๐ฃ๐๐๐๐ / ๐๐๐๐ ๐ก๐๐๐๐ =15 km / 20km = 0.75 ๐๐ / ๐๐๐ Speed= ๐ท๐๐ ๐ก๐๐๐๐ ๐๐๐ฃ๐๐๐๐ / ๐๐๐๐ ๐ก๐๐๐๐ = 15 km / 1/3h= 15 x 3 km = 45 km / h hRead more
Distance covered by car = 57336.0 km – 57321.0 km = 15.0 km
Time taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hour
So, speed in km/min
Speed= ๐ท๐๐ ๐ก๐๐๐๐ ๐๐๐ฃ๐๐๐๐ / ๐๐๐๐ ๐ก๐๐๐๐ =15 km / 20km = 0.75 ๐๐ / ๐๐๐
Speed= ๐ท๐๐ ๐ก๐๐๐๐ ๐๐๐ฃ๐๐๐๐ / ๐๐๐๐ ๐ก๐๐๐๐ = 15 km / 1/3h= 15 x 3 km = 45 km / h
A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. The total distance covered by the car is:
(ii) 25 km https://www.tiwariacademy.com/ncert-solutions/class-7/science/chapter-13/
(ii) 25 km
https://www.tiwariacademy.com/ncert-solutions/class-7/science/chapter-13/
See lessThe basic unit of speed is:
(iv) m/s https://www.tiwariacademy.com/ncert-solutions/class-7/science/chapter-13/
(iv) m/s
https://www.tiwariacademy.com/ncert-solutions/class-7/science/chapter-13/
See lessWhich of the following relations is correct?
(ii) ๐๐๐๐๐ = ๐ท๐๐ ๐ก๐๐๐๐ / ๐๐๐๐ https://www.tiwariacademy.com/ncert-solutions/class-7/science/chapter-13/
(ii) ๐๐๐๐๐ = ๐ท๐๐ ๐ก๐๐๐๐ / ๐๐๐๐
https://www.tiwariacademy.com/ncert-solutions/class-7/science/chapter-13/
See lessSalma takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a speed of 2 m/s, calculate the distance between her house and the school.
Speed = 2 m/s Time taken = 15 minutes = 15 ร 60 seconds = 900 seconds Now, distance = speed ร time = 2 ร 900 = 1800 m = 1.8 km https://www.tiwariacademy.com/ncert-solutions/class-7/science/chapter-13/
Speed = 2 m/s
Time taken = 15 minutes = 15 ร 60 seconds = 900 seconds
Now, distance = speed ร time = 2 ร 900 = 1800 m = 1.8 km
https://www.tiwariacademy.com/ncert-solutions/class-7/science/chapter-13/
See lessThe odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.
Distance covered by car = 57336.0 km - 57321.0 km = 15.0 km Time taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hour So, speed in km/min Speed= ๐ท๐๐ ๐ก๐๐๐๐ ๐๐๐ฃ๐๐๐๐ / ๐๐๐๐ ๐ก๐๐๐๐ =15 km / 20km = 0.75 ๐๐ / ๐๐๐ Speed= ๐ท๐๐ ๐ก๐๐๐๐ ๐๐๐ฃ๐๐๐๐ / ๐๐๐๐ ๐ก๐๐๐๐ = 15 km / 1/3h= 15 x 3 km = 45 km / h hRead more
Distance covered by car = 57336.0 km – 57321.0 km = 15.0 km
Time taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hour
So, speed in km/min
Speed= ๐ท๐๐ ๐ก๐๐๐๐ ๐๐๐ฃ๐๐๐๐ / ๐๐๐๐ ๐ก๐๐๐๐ =15 km / 20km = 0.75 ๐๐ / ๐๐๐
Speed= ๐ท๐๐ ๐ก๐๐๐๐ ๐๐๐ฃ๐๐๐๐ / ๐๐๐๐ ๐ก๐๐๐๐ = 15 km / 1/3h= 15 x 3 km = 45 km / h
https://www.tiwariacademy.com/ncert-solutions/class-7/science/chapter-13/
See less