1. Let the breadth of the pool be x m. Then, the length of the pool = (2x+2)m Perimeter = 2(l+b) ⇒ 154 = 2(2x+2+x) ⇒ 154/2 = 2(2x+2+x)/2 [Dividing both sides by 2] ⇒ 77=3x+2 ⇒ 77-2=3x+2-2 [Subtracting 2 from both sides] ⇒ 75=3x ⇒ 75/3=3x/3 [Dividing both sides by 3] ⇒ 25=x ⇒ x=25 Length of the pool= 2xRead more

    Let the breadth of the pool be x m.
    Then, the length of the pool = (2x+2)m
    Perimeter = 2(l+b)
    ⇒ 154 = 2(2x+2+x)
    ⇒ 154/2 = 2(2x+2+x)/2 [Dividing both sides by 2]
    ⇒ 77=3x+2
    ⇒ 77-2=3x+2-2 [Subtracting 2 from both sides]
    ⇒ 75=3x
    ⇒ 75/3=3x/3 [Dividing both sides by 3]
    ⇒ 25=x ⇒ x=25
    Length of the pool= 2x+2=2×25+2=50+2=52 m, Breadth of the pool=25m Hence, the length of the pool is 52 m and breadth is 25 m.

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

    See less
    • 4
  2. Let the number be x. According to the question, 1/2(x-1/2)=1/8 ⇒ 2x1/2(x-1/2)=1/8x2 [Multiplying both sides by 2] ⇒ x-1/2=1/4 ⇒ x-1/2+1/2=1/4+1/2 [Adding both sides1/2] ⇒ x=1+2/4 ⇒ x=3/4 Hence, the required number is 3/4 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8Read more

    Let the number be x.
    According to the question, 1/2(x-1/2)=1/8
    ⇒ 2×1/2(x-1/2)=1/8×2 [Multiplying both sides by 2]
    ⇒ x-1/2=1/4
    ⇒ x-1/2+1/2=1/4+1/2 [Adding both sides1/2]
    ⇒ x=1+2/4 ⇒ x=3/4
    Hence, the required number is 3/4

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

    See less
    • 4