Let the present age of Amon’s son be x years. Therefore, Aman’s age = 3x years According to question, 3x-10=5(x-10) ⇒ 3x-10=5x-50 ⇒ 3x-5x=-50+10 ⇒ -2x = -40 ⇒ x=-40/-2 =20years Hence, Aman’s son’s age = 20 years and Aman’s age = 3 x 2 = 60 years Class 8 Maths Chapter 2 Exercise 2.4 Solution in VideoRead more
Let the present age of Amon’s son be x years.
Therefore, Aman’s age = 3x years
According to question,
3x-10=5(x-10)
⇒ 3x-10=5x-50
⇒ 3x-5x=-50+10
⇒ -2x = -40
⇒ x=-40/-2 =20years
Hence, Aman’s son’s age = 20 years and Aman’s age = 3 x 2 = 60 years
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let present age of granddaughter be x years. Therefore, Grandfather’s age = 10x years According to question, 10x=x+54 ⇒ 10x-x+54 ⇒ 9x=54 ⇒ x=54/9=6years Hence, granddaughter’s age = 6 years and grandfather’s age = 10 x 6 = 60 years. Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video for more ansRead more
Let present age of granddaughter be x years.
Therefore, Grandfather’s age = 10x years
According to question,
10x=x+54
⇒ 10x-x+54
⇒ 9x=54
⇒ x=54/9=6years
Hence, granddaughter’s age = 6 years and grandfather’s age = 10 x 6 = 60 years.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let the total number of deer in the herd be x. According to question, x=x/2+3/4x(x-(x/2)+9 ⇒ x=x/2+3/4(2x-x/2)+9 ⇒ x=x/2+3/4X x/2 + 9 ⇒ x=x/2+3/8 x + 9 ⇒ x-x/2 - 3x/8 =9 ⇒ 8x-4x-3x/8=9 ⇒ x/8=9 ⇒ x=9x8=72 Hence, the total number of deer in the herd is 72. Class 8 Maths Chapter 2 Exercise 2.4 SolutionRead more
Let the total number of deer in the herd be x.
According to question,
x=x/2+3/4x(x-(x/2)+9
⇒ x=x/2+3/4(2x-x/2)+9
⇒ x=x/2+3/4X x/2 + 9
⇒ x=x/2+3/8 x + 9
⇒ x-x/2 – 3x/8 =9
⇒ 8x-4x-3x/8=9
⇒ x/8=9
⇒ x=9×8=72
Hence, the total number of deer in the herd is 72.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let ratio between shirt material and trouser material be 3x : 2x The cost of shirt material = 50X3x=150x The selling price at 12% gain = 100+P%/10x c.p = 100+12/100x150x = 112/100x150x=168x The cost of trouser material = 90 X 2x =180x The selling price at 12% gain = 100+P%/100 x C.P = 100+10/100x180Read more
Let ratio between shirt material and trouser material be 3x : 2x
The cost of shirt material = 50X3x=150x
The selling price at 12% gain = 100+P%/10x c.p = 100+12/100x150x
= 112/100x150x=168x
The cost of trouser material = 90 X 2x =180x
The selling price at 12% gain = 100+P%/100 x C.P = 100+10/100x180x
= 110/100x180x = 198x
According to the question,
168x+198x=36,600
⇒ 366x=36600
⇒ x=36600/366 = 100 meters
Now, trouser material = 2x = 2 x 100 = 200 meters
Hence, Hasan bought 200 meters of the trouser material.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let the length and breadth of the rectangular plot be 11x and 4x respectively. Perimeter of the plot = Total Cost/Cost of 1 meter = 75000/100=750m We know that Perimeter of rectangle = 2 (length + breadth) Therefore, according to the question, 750=2(11x+4x) ⇒ 750=2X15x ⇒ 750=30x ⇒ 30x=750 ⇒ x=750/30Read more
Let the length and breadth of the rectangular plot be 11x and 4x respectively.
Perimeter of the plot = Total Cost/Cost of 1 meter = 75000/100=750m
We know that Perimeter of rectangle = 2 (length + breadth)
Therefore, according to the question, 750=2(11x+4x)
⇒ 750=2X15x ⇒ 750=30x ⇒ 30x=750 ⇒ x=750/30=25
Hence, length of rectangular plot = 11 x 25 = 275 m and breadth of rectangular plot = 4 x 25 = 100 m
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let Shobo’s present age be x years. And Shobo’s mother’s present age = 6x years According to the question, x+5=1/3X6x ⇒ x+5=2x ⇒ 2x=x+5 ⇒ 2x-x=5 ⇒ x=5 Years. Hence, Shobo’s present age = 5 years and Shobo’s mother’s present age = 6 x 5 = 30 years Class 8 Maths Chapter 2 Exercise 2.4 Solution in VideRead more
Let Shobo’s present age be x years.
And Shobo’s mother’s present age = 6x years
According to the question, x+5=1/3X6x
⇒ x+5=2x ⇒ 2x=x+5 ⇒ 2x-x=5
⇒ x=5 Years.
Hence, Shobo’s present age = 5 years and Shobo’s mother’s present age = 6 x 5 = 30 years
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let the unit place digit of a two-digit number be x. Therefore, the tens place digit = 3x 2-digit number = 10 x tens place digit + unit place digit Original number = 10 x 3x + x =30x + x = 31x According to the question, New number + Original number = 88 ⇒ 10x+3x+31x=88 ⇒ 44x=88 ⇒ x=88/44=2 Hence, thRead more
Let the unit place digit of a two-digit number be x.
Therefore, the tens place digit = 3x
2-digit number = 10 x tens place digit + unit place digit
Original number = 10 x 3x + x =30x + x = 31x
According to the question, New number + Original number = 88
⇒ 10x+3x+31x=88 ⇒ 44x=88 ⇒ x=88/44=2
Hence, the 2-digit number = 31x=31X2=62
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let the unit place digit of a two-digit number be x. Therefore, the tens place digit = 9-x 2-digit number = 10 x tens place digit + unit place digit Original number = 10(9-x)+x According to the question, New number = Original number + 27 ⇒ 10x+(9-x)=10(9-x)+x+27 ⇒ 10+9-x=90-10x+x+27 ⇒ 9x+9=117-9x ⇒Read more
Let the unit place digit of a two-digit number be x.
Therefore, the tens place digit = 9-x
2-digit number = 10 x tens place digit + unit place digit
Original number = 10(9-x)+x
According to the question, New number = Original number + 27
⇒ 10x+(9-x)=10(9-x)+x+27 ⇒ 10+9-x=90-10x+x+27
⇒ 9x+9=117-9x ⇒ 9x+9x=117-9
⇒ 18x = 108
⇒ x=108/18=6
Hence, the 2-digit number = 10(9-x)+x=10(9-6)+6=10 x 3 + 6 = 30+6 =36
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let another number be x. Then positive number = 5x According to the question, 5x+21=2(x+21) ⇒ 5x+21=2x+42 ⇒ 5x-2x=42-21 ⇒ 3x=21 ⇒ x=21/3=7 Hence another number = 7 and positive number = 5x7=35 Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video for more answers vist to: https://www.tiwariacademy.Read more
Let another number be x.
Then positive number = 5x
According to the question, 5x+21=2(x+21)
⇒ 5x+21=2x+42 ⇒ 5x-2x=42-21 ⇒ 3x=21
⇒ x=21/3=7
Hence another number = 7 and positive number = 5×7=35
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let Amina think a number x. According to the question,8(x-(5/2))=3x ⇒ 8x-8x5/2=3x ⇒ 8x-4x5=3x ⇒ 8x-20=3x ⇒ 8x-3x=20 ⇒ 5x=20 ⇒ x=20/5=4 Hence, the number is 4. Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/mathsRead more
Let Amina think a number x.
According to the question,8(x-(5/2))=3x
⇒ 8x-8×5/2=3x ⇒ 8x-4×5=3x ⇒ 8x-20=3x
⇒ 8x-3x=20 ⇒ 5x=20 ⇒ x=20/5=4
Hence, the number is 4.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Aman’s age is three times his son’s age. Ten years ago he was five times his son’s age. Find their present ages.
Let the present age of Amon’s son be x years. Therefore, Aman’s age = 3x years According to question, 3x-10=5(x-10) ⇒ 3x-10=5x-50 ⇒ 3x-5x=-50+10 ⇒ -2x = -40 ⇒ x=-40/-2 =20years Hence, Aman’s son’s age = 20 years and Aman’s age = 3 x 2 = 60 years Class 8 Maths Chapter 2 Exercise 2.4 Solution in VideoRead more
Let the present age of Amon’s son be x years.
Therefore, Aman’s age = 3x years
According to question,
3x-10=5(x-10)
⇒ 3x-10=5x-50
⇒ 3x-5x=-50+10
⇒ -2x = -40
⇒ x=-40/-2 =20years
Hence, Aman’s son’s age = 20 years and Aman’s age = 3 x 2 = 60 years
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
A grandfather is ten times older than his granddaughter. He is also 54 years older than her. Find their present ages.
Let present age of granddaughter be x years. Therefore, Grandfather’s age = 10x years According to question, 10x=x+54 ⇒ 10x-x+54 ⇒ 9x=54 ⇒ x=54/9=6years Hence, granddaughter’s age = 6 years and grandfather’s age = 10 x 6 = 60 years. Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video for more ansRead more
Let present age of granddaughter be x years.
Therefore, Grandfather’s age = 10x years
According to question,
10x=x+54
⇒ 10x-x+54
⇒ 9x=54
⇒ x=54/9=6years
Hence, granddaughter’s age = 6 years and grandfather’s age = 10 x 6 = 60 years.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Half of a herd of deer are grazing in the field and three fourths of the remaining are playing nearby. The rest 9 are drinking water from the pond. Find the number of deer in the herd.
Let the total number of deer in the herd be x. According to question, x=x/2+3/4x(x-(x/2)+9 ⇒ x=x/2+3/4(2x-x/2)+9 ⇒ x=x/2+3/4X x/2 + 9 ⇒ x=x/2+3/8 x + 9 ⇒ x-x/2 - 3x/8 =9 ⇒ 8x-4x-3x/8=9 ⇒ x/8=9 ⇒ x=9x8=72 Hence, the total number of deer in the herd is 72. Class 8 Maths Chapter 2 Exercise 2.4 SolutionRead more
Let the total number of deer in the herd be x.
According to question,
x=x/2+3/4x(x-(x/2)+9
⇒ x=x/2+3/4(2x-x/2)+9
⇒ x=x/2+3/4X x/2 + 9
⇒ x=x/2+3/8 x + 9
⇒ x-x/2 – 3x/8 =9
⇒ 8x-4x-3x/8=9
⇒ x/8=9
⇒ x=9×8=72
Hence, the total number of deer in the herd is 72.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him ₹50 per meter and trouser material that costs him ₹90 per meter. For every 2 meters of the trouser material he buys 3 meters of the shirt material. He sells the materials at 12% and 10% respectively. His total sale is ₹36,000. How much trouser material did he buy?
Let ratio between shirt material and trouser material be 3x : 2x The cost of shirt material = 50X3x=150x The selling price at 12% gain = 100+P%/10x c.p = 100+12/100x150x = 112/100x150x=168x The cost of trouser material = 90 X 2x =180x The selling price at 12% gain = 100+P%/100 x C.P = 100+10/100x180Read more
Let ratio between shirt material and trouser material be 3x : 2x
The cost of shirt material = 50X3x=150x
The selling price at 12% gain = 100+P%/10x c.p = 100+12/100x150x
= 112/100x150x=168x
The cost of trouser material = 90 X 2x =180x
The selling price at 12% gain = 100+P%/100 x C.P = 100+10/100x180x
= 110/100x180x = 198x
According to the question,
168x+198x=36,600
⇒ 366x=36600
⇒ x=36600/366 = 100 meters
Now, trouser material = 2x = 2 x 100 = 200 meters
Hence, Hasan bought 200 meters of the trouser material.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
There is a narrow rectangular plot, reserved for a school, in Mahuli village. The length and breadth of the plot are in the ratio 11:4. At the rate ` 100 per meter it will cost the village panchayat ` 75,000 to fence the plot. What are the dimensions of the plot?
Let the length and breadth of the rectangular plot be 11x and 4x respectively. Perimeter of the plot = Total Cost/Cost of 1 meter = 75000/100=750m We know that Perimeter of rectangle = 2 (length + breadth) Therefore, according to the question, 750=2(11x+4x) ⇒ 750=2X15x ⇒ 750=30x ⇒ 30x=750 ⇒ x=750/30Read more
Let the length and breadth of the rectangular plot be 11x and 4x respectively.
Perimeter of the plot = Total Cost/Cost of 1 meter = 75000/100=750m
We know that Perimeter of rectangle = 2 (length + breadth)
Therefore, according to the question, 750=2(11x+4x)
⇒ 750=2X15x ⇒ 750=30x ⇒ 30x=750 ⇒ x=750/30=25
Hence, length of rectangular plot = 11 x 25 = 275 m and breadth of rectangular plot = 4 x 25 = 100 m
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Shobo’s mother’s present age is six times Shobo’s present age. Shobo’s age five years from now will be one third of his mother’s present age. What are their present age?
Let Shobo’s present age be x years. And Shobo’s mother’s present age = 6x years According to the question, x+5=1/3X6x ⇒ x+5=2x ⇒ 2x=x+5 ⇒ 2x-x=5 ⇒ x=5 Years. Hence, Shobo’s present age = 5 years and Shobo’s mother’s present age = 6 x 5 = 30 years Class 8 Maths Chapter 2 Exercise 2.4 Solution in VideRead more
Let Shobo’s present age be x years.
And Shobo’s mother’s present age = 6x years
According to the question, x+5=1/3X6x
⇒ x+5=2x ⇒ 2x=x+5 ⇒ 2x-x=5
⇒ x=5 Years.
Hence, Shobo’s present age = 5 years and Shobo’s mother’s present age = 6 x 5 = 30 years
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
One of the two digits of a two-digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?
Let the unit place digit of a two-digit number be x. Therefore, the tens place digit = 3x 2-digit number = 10 x tens place digit + unit place digit Original number = 10 x 3x + x =30x + x = 31x According to the question, New number + Original number = 88 ⇒ 10x+3x+31x=88 ⇒ 44x=88 ⇒ x=88/44=2 Hence, thRead more
Let the unit place digit of a two-digit number be x.
Therefore, the tens place digit = 3x
2-digit number = 10 x tens place digit + unit place digit
Original number = 10 x 3x + x =30x + x = 31x
According to the question, New number + Original number = 88
⇒ 10x+3x+31x=88 ⇒ 44x=88 ⇒ x=88/44=2
Hence, the 2-digit number = 31x=31X2=62
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Sum of the digits of a two-digit number is 9. When we interchange the digits, it is found that the resulting new number is greater than the original number by 27. What is the twodigit number?
Let the unit place digit of a two-digit number be x. Therefore, the tens place digit = 9-x 2-digit number = 10 x tens place digit + unit place digit Original number = 10(9-x)+x According to the question, New number = Original number + 27 ⇒ 10x+(9-x)=10(9-x)+x+27 ⇒ 10+9-x=90-10x+x+27 ⇒ 9x+9=117-9x ⇒Read more
Let the unit place digit of a two-digit number be x.
Therefore, the tens place digit = 9-x
2-digit number = 10 x tens place digit + unit place digit
Original number = 10(9-x)+x
According to the question, New number = Original number + 27
⇒ 10x+(9-x)=10(9-x)+x+27 ⇒ 10+9-x=90-10x+x+27
⇒ 9x+9=117-9x ⇒ 9x+9x=117-9
⇒ 18x = 108
⇒ x=108/18=6
Hence, the 2-digit number = 10(9-x)+x=10(9-6)+6=10 x 3 + 6 = 30+6 =36
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers?
Let another number be x. Then positive number = 5x According to the question, 5x+21=2(x+21) ⇒ 5x+21=2x+42 ⇒ 5x-2x=42-21 ⇒ 3x=21 ⇒ x=21/3=7 Hence another number = 7 and positive number = 5x7=35 Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video for more answers vist to: https://www.tiwariacademy.Read more
Let another number be x.
Then positive number = 5x
According to the question, 5x+21=2(x+21)
⇒ 5x+21=2x+42 ⇒ 5x-2x=42-21 ⇒ 3x=21
⇒ x=21/3=7
Hence another number = 7 and positive number = 5×7=35
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Amina thinks of a number and subtracts 5/2 from it. She multiplies the result by 8. The result now obtained is 3 times the same number she thought of. What is the number?
Let Amina think a number x. According to the question,8(x-(5/2))=3x ⇒ 8x-8x5/2=3x ⇒ 8x-4x5=3x ⇒ 8x-20=3x ⇒ 8x-3x=20 ⇒ 5x=20 ⇒ x=20/5=4 Hence, the number is 4. Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/mathsRead more
Let Amina think a number x.
According to the question,8(x-(5/2))=3x
⇒ 8x-8×5/2=3x ⇒ 8x-4×5=3x ⇒ 8x-20=3x
⇒ 8x-3x=20 ⇒ 5x=20 ⇒ x=20/5=4
Hence, the number is 4.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/