Let Shobo’s present age be x years. And Shobo’s mother’s present age = 6x years According to the question, x+5=1/3X6x ⇒ x+5=2x ⇒ 2x=x+5 ⇒ 2x-x=5 ⇒ x=5 Years. Hence, Shobo’s present age = 5 years and Shobo’s mother’s present age = 6 x 5 = 30 years Class 8 Maths Chapter 2 Exercise 2.4 Solution in VideRead more
Let Shobo’s present age be x years.
And Shobo’s mother’s present age = 6x years
According to the question, x+5=1/3X6x
⇒ x+5=2x ⇒ 2x=x+5 ⇒ 2x-x=5
⇒ x=5 Years.
Hence, Shobo’s present age = 5 years and Shobo’s mother’s present age = 6 x 5 = 30 years
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let the unit place digit of a two-digit number be x. Therefore, the tens place digit = 3x 2-digit number = 10 x tens place digit + unit place digit Original number = 10 x 3x + x =30x + x = 31x According to the question, New number + Original number = 88 ⇒ 10x+3x+31x=88 ⇒ 44x=88 ⇒ x=88/44=2 Hence, thRead more
Let the unit place digit of a two-digit number be x.
Therefore, the tens place digit = 3x
2-digit number = 10 x tens place digit + unit place digit
Original number = 10 x 3x + x =30x + x = 31x
According to the question, New number + Original number = 88
⇒ 10x+3x+31x=88 ⇒ 44x=88 ⇒ x=88/44=2
Hence, the 2-digit number = 31x=31X2=62
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let the unit place digit of a two-digit number be x. Therefore, the tens place digit = 9-x 2-digit number = 10 x tens place digit + unit place digit Original number = 10(9-x)+x According to the question, New number = Original number + 27 ⇒ 10x+(9-x)=10(9-x)+x+27 ⇒ 10+9-x=90-10x+x+27 ⇒ 9x+9=117-9x ⇒Read more
Let the unit place digit of a two-digit number be x.
Therefore, the tens place digit = 9-x
2-digit number = 10 x tens place digit + unit place digit
Original number = 10(9-x)+x
According to the question, New number = Original number + 27
⇒ 10x+(9-x)=10(9-x)+x+27 ⇒ 10+9-x=90-10x+x+27
⇒ 9x+9=117-9x ⇒ 9x+9x=117-9
⇒ 18x = 108
⇒ x=108/18=6
Hence, the 2-digit number = 10(9-x)+x=10(9-6)+6=10 x 3 + 6 = 30+6 =36
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let another number be x. Then positive number = 5x According to the question, 5x+21=2(x+21) ⇒ 5x+21=2x+42 ⇒ 5x-2x=42-21 ⇒ 3x=21 ⇒ x=21/3=7 Hence another number = 7 and positive number = 5x7=35 Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video for more answers vist to: https://www.tiwariacademy.Read more
Let another number be x.
Then positive number = 5x
According to the question, 5x+21=2(x+21)
⇒ 5x+21=2x+42 ⇒ 5x-2x=42-21 ⇒ 3x=21
⇒ x=21/3=7
Hence another number = 7 and positive number = 5×7=35
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Let Amina think a number x. According to the question,8(x-(5/2))=3x ⇒ 8x-8x5/2=3x ⇒ 8x-4x5=3x ⇒ 8x-20=3x ⇒ 8x-3x=20 ⇒ 5x=20 ⇒ x=20/5=4 Hence, the number is 4. Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/mathsRead more
Let Amina think a number x.
According to the question,8(x-(5/2))=3x
⇒ 8x-8×5/2=3x ⇒ 8x-4×5=3x ⇒ 8x-20=3x
⇒ 8x-3x=20 ⇒ 5x=20 ⇒ x=20/5=4
Hence, the number is 4.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
Shobo’s mother’s present age is six times Shobo’s present age. Shobo’s age five years from now will be one third of his mother’s present age. What are their present age?
Let Shobo’s present age be x years. And Shobo’s mother’s present age = 6x years According to the question, x+5=1/3X6x ⇒ x+5=2x ⇒ 2x=x+5 ⇒ 2x-x=5 ⇒ x=5 Years. Hence, Shobo’s present age = 5 years and Shobo’s mother’s present age = 6 x 5 = 30 years Class 8 Maths Chapter 2 Exercise 2.4 Solution in VideRead more
Let Shobo’s present age be x years.
And Shobo’s mother’s present age = 6x years
According to the question, x+5=1/3X6x
⇒ x+5=2x ⇒ 2x=x+5 ⇒ 2x-x=5
⇒ x=5 Years.
Hence, Shobo’s present age = 5 years and Shobo’s mother’s present age = 6 x 5 = 30 years
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
One of the two digits of a two-digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?
Let the unit place digit of a two-digit number be x. Therefore, the tens place digit = 3x 2-digit number = 10 x tens place digit + unit place digit Original number = 10 x 3x + x =30x + x = 31x According to the question, New number + Original number = 88 ⇒ 10x+3x+31x=88 ⇒ 44x=88 ⇒ x=88/44=2 Hence, thRead more
Let the unit place digit of a two-digit number be x.
Therefore, the tens place digit = 3x
2-digit number = 10 x tens place digit + unit place digit
Original number = 10 x 3x + x =30x + x = 31x
According to the question, New number + Original number = 88
⇒ 10x+3x+31x=88 ⇒ 44x=88 ⇒ x=88/44=2
Hence, the 2-digit number = 31x=31X2=62
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Sum of the digits of a two-digit number is 9. When we interchange the digits, it is found that the resulting new number is greater than the original number by 27. What is the twodigit number?
Let the unit place digit of a two-digit number be x. Therefore, the tens place digit = 9-x 2-digit number = 10 x tens place digit + unit place digit Original number = 10(9-x)+x According to the question, New number = Original number + 27 ⇒ 10x+(9-x)=10(9-x)+x+27 ⇒ 10+9-x=90-10x+x+27 ⇒ 9x+9=117-9x ⇒Read more
Let the unit place digit of a two-digit number be x.
Therefore, the tens place digit = 9-x
2-digit number = 10 x tens place digit + unit place digit
Original number = 10(9-x)+x
According to the question, New number = Original number + 27
⇒ 10x+(9-x)=10(9-x)+x+27 ⇒ 10+9-x=90-10x+x+27
⇒ 9x+9=117-9x ⇒ 9x+9x=117-9
⇒ 18x = 108
⇒ x=108/18=6
Hence, the 2-digit number = 10(9-x)+x=10(9-6)+6=10 x 3 + 6 = 30+6 =36
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers?
Let another number be x. Then positive number = 5x According to the question, 5x+21=2(x+21) ⇒ 5x+21=2x+42 ⇒ 5x-2x=42-21 ⇒ 3x=21 ⇒ x=21/3=7 Hence another number = 7 and positive number = 5x7=35 Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video for more answers vist to: https://www.tiwariacademy.Read more
Let another number be x.
Then positive number = 5x
According to the question, 5x+21=2(x+21)
⇒ 5x+21=2x+42 ⇒ 5x-2x=42-21 ⇒ 3x=21
⇒ x=21/3=7
Hence another number = 7 and positive number = 5×7=35
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/
Amina thinks of a number and subtracts 5/2 from it. She multiplies the result by 8. The result now obtained is 3 times the same number she thought of. What is the number?
Let Amina think a number x. According to the question,8(x-(5/2))=3x ⇒ 8x-8x5/2=3x ⇒ 8x-4x5=3x ⇒ 8x-20=3x ⇒ 8x-3x=20 ⇒ 5x=20 ⇒ x=20/5=4 Hence, the number is 4. Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/mathsRead more
Let Amina think a number x.
According to the question,8(x-(5/2))=3x
⇒ 8x-8×5/2=3x ⇒ 8x-4×5=3x ⇒ 8x-20=3x
⇒ 8x-3x=20 ⇒ 5x=20 ⇒ x=20/5=4
Hence, the number is 4.
Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/