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  1. Asked: In:

    Solve the following equation: 9x/7-6x = 15

    Best Answer
    Omkari

    9x/7-6x = 15 ⟹ 9x=15(7-6x) ⟹ 9x=105-90x ⟹ 9x+90x=105 ⟹ 99x=105 ⟹ x=105/99 ⟹ x=35/33 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

    9x/7-6x = 15
    ⟹ 9x=15(7-6x) ⟹ 9x=105-90x ⟹ 9x+90x=105
    ⟹ 99x=105 ⟹ x=105/99 ⟹ x=35/33

    Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

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  2. Asked: In:

    Solve the following equation: 8x-3/3x = 2

    Best Answer
    Omkari

    8x-3/3x = 2 ⟹ 8x-3=2x3x ⟹ 8x-3=6x ⟹ 8x-6x=3 ⟹ 2x=3 ⟹ x=3/2 Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

    8x-3/3x = 2
    ⟹ 8x-3=2x3x ⟹ 8x-3=6x ⟹ 8x-6x=3 ⟹ 2x=3 ⟹ x=3/2

    Class 8 Maths Chapter 2 Exercise 2.6 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

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    • 6
  3. Asked: In:

    Simplify and solve the following linear equation: 0.25(4f-3) =0.05(10f-9)

    Omkari

    0.25(4f-3) =0.05(10f-9) ⟹ 1.00f-0.75=0.50f-0.45 ⟹ 1.00f-0.50f =-0.45+0.75 ⟹ 0.50f =0.3 ⟹ f = 0.3/0.50 ⟹ f=0.6 To check: 0.25(4f-3)=0.05(10f-9) ⟹ 0.25(4X0.6-3)=0.05(10x0.6-9) ⟹ 0.25(2.4-3)=0.05(6.0-9) ⟹ 0.25x(-0.6) =0.05X(-3) ⟹ -0.150=-0.150 ⟹ L.H.S. = R. H. S. Therefore, it is correct. Class 8 MathsRead more

    0.25(4f-3) =0.05(10f-9)
    ⟹ 1.00f-0.75=0.50f-0.45 ⟹ 1.00f-0.50f =-0.45+0.75
    ⟹ 0.50f =0.3 ⟹ f = 0.3/0.50 ⟹ f=0.6
    To check:
    0.25(4f-3)=0.05(10f-9) ⟹ 0.25(4X0.6-3)=0.05(10×0.6-9)
    ⟹ 0.25(2.4-3)=0.05(6.0-9) ⟹ 0.25x(-0.6) =0.05X(-3)
    ⟹ -0.150=-0.150 ⟹ L.H.S. = R. H. S.
    Therefore, it is correct.

    Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

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    • 4
  4. Asked: In:

    Simplify and solve the following linear equation: 3(5z-7)-2(9z-11) =4(8z-13)-17

    Best Answer
    Omkari

    3(5z-7)-2(9z-11) =4(8z-13)-17 ⟹ 15z-21-18z+22=32z-52-17 ⟹ -3z+1=32z-69 ⟹ -3z-32z=-69-1 ⟹ -35z=-70 ⟹ z=-70/-35=2 To check: 3(5z-7)-2(9z-11)=4(8z-13)-17 ⟹ 3(5X2-7)-2(9X2-11)=4(8X2-13)-17 ⟹ 3(10-7)-2(18-11)=4(16-13)-17 ⟹ 3x3-2x7=4x3-17 ⟹ 9-14=12-17 ⟹-5=-5 ⟹ L.H.S. = R. H. S. Therefore, it is correct. CRead more

    3(5z-7)-2(9z-11) =4(8z-13)-17 ⟹ 15z-21-18z+22=32z-52-17
    ⟹ -3z+1=32z-69 ⟹ -3z-32z=-69-1 ⟹ -35z=-70 ⟹ z=-70/-35=2
    To check:
    3(5z-7)-2(9z-11)=4(8z-13)-17 ⟹ 3(5X2-7)-2(9X2-11)=4(8X2-13)-17
    ⟹ 3(10-7)-2(18-11)=4(16-13)-17 ⟹ 3×3-2×7=4×3-17
    ⟹ 9-14=12-17 ⟹-5=-5 ⟹ L.H.S. = R. H. S.
    Therefore, it is correct.

    Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

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    • 6
  6. Asked: In:

    Simplify and solve the following linear equation: 15(y-4) -2 (y-9) +5 (y+6) =0

    Best Answer
    Omkari

    15(y-4) -2 (y-9) +5 (y+6) =0 ⟹ 15y-60-2y+18+5y+30=0 ⟹ 18y-12=0 ⟹ 18y=12 ⟹ y-12/18 ⟹ y=2/3 Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

    15(y-4) -2 (y-9) +5 (y+6) =0 ⟹ 15y-60-2y+18+5y+30=0
    ⟹ 18y-12=0
    ⟹ 18y=12
    ⟹ y-12/18
    ⟹ y=2/3

    Class 8 Maths Chapter 2 Exercise 2.5 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

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    • 5