Choices (d) is correct. Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1 ⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1. Thus, z lies on a circle with centre (-1, 0) and radius 1. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex NRead more
Choices (d) is correct.
Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1
⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1.
Thus, z lies on a circle with centre (-1, 0) and radius 1.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
The complex number z = x + iy satisfies the condition ∣ z + 1 ∣ = 1, then z lies on
Choices (d) is correct. Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1 ⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1. Thus, z lies on a circle with centre (-1, 0) and radius 1. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex NRead more
Choices (d) is correct.
Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1
⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1.
Thus, z lies on a circle with centre (-1, 0) and radius 1.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
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