Choice (c) is correct. Here, z = 1 - cos 2 θ + i sin 2 θ ∣ z ∣ = ∣1 - cos 2 θ + i sin 2 θ∣ = √(1 - cos 2θ)² + (sin 2θ)² = √ 1 -2 cos 2 θ + sin² 2θ = √1 - 2 cos2θ + 1 = √2 -2 cos 2 θ = √2(1- cos 2θ ) = √2(2 sin² θ) = 2 ∣ sin θ ∣ This question related to Chapter 4 maths Class 11th NCERT. From the ChRead more
Choice (c) is correct.
Here, z = 1 – cos 2 θ + i sin 2 θ
∣ z ∣ = ∣1 – cos 2 θ + i sin 2 θ∣ = √(1 – cos 2θ)² + (sin 2θ)²
= √ 1 -2 cos 2 θ + sin² 2θ = √1 – 2 cos2θ + 1
= √2 -2 cos 2 θ = √2(1- cos 2θ ) = √2(2 sin² θ) = 2 ∣ sin θ ∣
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
Choice (b) is correct. i¹⁰⁰² = i¹⁰⁰⁰ × i² = (i⁴ )²⁵⁰ × (-1) = 1²⁵⁰ × (-1) = -1 This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.cRead more
Choice (b) is correct.
i¹⁰⁰² = i¹⁰⁰⁰ × i²
= (i⁴ )²⁵⁰ × (-1) = 1²⁵⁰ × (-1) = -1
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
Choice (c) is correct. We know that the square root of negative number is imaginary number. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwRead more
Choice (c) is correct. We know that the square root of negative number is imaginary number.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
Choice (d) is correct. Given, a + ib = c +id ⇒ a = c and b = d ⇒ a² + b² = c² + d² This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacadRead more
Choice (d) is correct.
Given, a + ib = c +id
⇒ a = c and b = d
⇒ a² + b² = c² + d²
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
Choices (d) is correct. Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1 ⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1. Thus, z lies on a circle with centre (-1, 0) and radius 1. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex NRead more
Choices (d) is correct.
Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1
⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1.
Thus, z lies on a circle with centre (-1, 0) and radius 1.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
Choice (c) is correct. ∣ z ∣ = 4 ⇒ ∣ x + iy ∣ = 4 ⇒ √x² + y² = 4 ⇒ x² + y² = 16 This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacademRead more
Choice (c) is correct.
∣ z ∣ = 4 ⇒ ∣ x + iy ∣ = 4
⇒ √x² + y² = 4 ⇒ x² + y² = 16
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
Choice (c) is correct. As sec θ ≤ - 1 or sec θ ≥ 1, so sec θ cannot be equal to 1/2. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-sRead more
Choice (c) is correct.
As sec θ ≤ – 1 or sec θ ≥ 1, so sec θ cannot be equal to 1/2.
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
Choice (b) is correct. As tangent function is negative in 2nd and 4th quadrants. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutRead more
Choice (b) is correct. As tangent function is negative in 2nd and 4th quadrants.
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
Choice (b) is correct. We know that sine function is an increasing function in first quadrant and 1 radian = 57.296 degrees. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit hereRead more
Choice (b) is correct. We know that sine function is an increasing function in first quadrant and 1 radian = 57.296 degrees. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
If z = 1 – cos 2 θ + i sin 2 θ, then ∣ z ∣
Choice (c) is correct. Here, z = 1 - cos 2 θ + i sin 2 θ ∣ z ∣ = ∣1 - cos 2 θ + i sin 2 θ∣ = √(1 - cos 2θ)² + (sin 2θ)² = √ 1 -2 cos 2 θ + sin² 2θ = √1 - 2 cos2θ + 1 = √2 -2 cos 2 θ = √2(1- cos 2θ ) = √2(2 sin² θ) = 2 ∣ sin θ ∣ This question related to Chapter 4 maths Class 11th NCERT. From the ChRead more
Choice (c) is correct.
Here, z = 1 – cos 2 θ + i sin 2 θ
∣ z ∣ = ∣1 – cos 2 θ + i sin 2 θ∣ = √(1 – cos 2θ)² + (sin 2θ)²
= √ 1 -2 cos 2 θ + sin² 2θ = √1 – 2 cos2θ + 1
= √2 -2 cos 2 θ = √2(1- cos 2θ ) = √2(2 sin² θ) = 2 ∣ sin θ ∣
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
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The value of i¹⁰⁰² is
Choice (b) is correct. i¹⁰⁰² = i¹⁰⁰⁰ × i² = (i⁴ )²⁵⁰ × (-1) = 1²⁵⁰ × (-1) = -1 This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.cRead more
Choice (b) is correct.
i¹⁰⁰² = i¹⁰⁰⁰ × i²
= (i⁴ )²⁵⁰ × (-1) = 1²⁵⁰ × (-1) = -1
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
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Which of the following options define imaginary number?
Choice (c) is correct. We know that the square root of negative number is imaginary number. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwRead more
Choice (c) is correct. We know that the square root of negative number is imaginary number.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
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If a + ib = c + id, then
Choice (d) is correct. Given, a + ib = c +id ⇒ a = c and b = d ⇒ a² + b² = c² + d² This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacadRead more
Choice (d) is correct.
Given, a + ib = c +id
⇒ a = c and b = d
⇒ a² + b² = c² + d²
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
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The complex number z = x + iy satisfies the condition ∣ z + 1 ∣ = 1, then z lies on
Choices (d) is correct. Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1 ⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1. Thus, z lies on a circle with centre (-1, 0) and radius 1. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex NRead more
Choices (d) is correct.
Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1
⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1.
Thus, z lies on a circle with centre (-1, 0) and radius 1.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-4
What does ∣ z ∣ = 4 represent on a plane where z = 4 represent on a plane where z = x + iy, a complex number?
Choice (c) is correct. ∣ z ∣ = 4 ⇒ ∣ x + iy ∣ = 4 ⇒ √x² + y² = 4 ⇒ x² + y² = 16 This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacademRead more
Choice (c) is correct.
∣ z ∣ = 4 ⇒ ∣ x + iy ∣ = 4
⇒ √x² + y² = 4 ⇒ x² + y² = 16
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
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Which of the following is not correct?
Choice (c) is correct. As sec θ ≤ - 1 or sec θ ≥ 1, so sec θ cannot be equal to 1/2. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-sRead more
Choice (c) is correct.
As sec θ ≤ – 1 or sec θ ≥ 1, so sec θ cannot be equal to 1/2.
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
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Tangent function is negative in
Choice (b) is correct. As tangent function is negative in 2nd and 4th quadrants. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutRead more
Choice (b) is correct. As tangent function is negative in 2nd and 4th quadrants.
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
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If tan θ = 3 and θ lies in third quadrant, then the value of sin θ is
Choice (d) is correct. Given that , tan θ = 3 we know that, sec² θ = 1 + tan² θ ⇒ sec² θ = 1 + 3² = 1 + 9 = 10 ⇒ cos² θ = 1/10 We know that sin² θ = 1 - cos² θ sin² θ = 1 - 1/10 = 10 - 1/10 = 9/10 ⇒ sin θ = ± √9/10 = ± 3/√10 ⇒ sin θ = -3√10 This question related to Chapter 3 maths Class 11th NCERT.Read more
Choice (d) is correct. Given that , tan θ = 3
we know that, sec² θ = 1 + tan² θ
⇒ sec² θ = 1 + 3² = 1 + 9 = 10 ⇒ cos² θ = 1/10
We know that sin² θ = 1 – cos² θ
sin² θ = 1 – 1/10 = 10 – 1/10 = 9/10
⇒ sin θ = ± √9/10 = ± 3/√10 ⇒ sin θ = -3√10
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
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Which of the following is correct?
Choice (b) is correct. We know that sine function is an increasing function in first quadrant and 1 radian = 57.296 degrees. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit hereRead more
Choice (b) is correct. We know that sine function is an increasing function in first quadrant and 1 radian = 57.296 degrees. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3