Choice (c) is correct. Here, z = 1 - cos 2 θ + i sin 2 θ ∣ z ∣ = ∣1 - cos 2 θ + i sin 2 θ∣ = √(1 - cos 2θ)² + (sin 2θ)² = √ 1 -2 cos 2 θ + sin² 2θ = √1 - 2 cos2θ + 1 = √2 -2 cos 2 θ = √2(1- cos 2θ ) = √2(2 sin² θ) = 2 ∣ sin θ ∣ This question related to Chapter 4 maths Class 11th NCERT. From the ChRead more
Choice (c) is correct.
Here, z = 1 – cos 2 θ + i sin 2 θ
∣ z ∣ = ∣1 – cos 2 θ + i sin 2 θ∣ = √(1 – cos 2θ)² + (sin 2θ)²
= √ 1 -2 cos 2 θ + sin² 2θ = √1 – 2 cos2θ + 1
= √2 -2 cos 2 θ = √2(1- cos 2θ ) = √2(2 sin² θ) = 2 ∣ sin θ ∣
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
Choice (b) is correct. i¹⁰⁰² = i¹⁰⁰⁰ × i² = (i⁴ )²⁵⁰ × (-1) = 1²⁵⁰ × (-1) = -1 This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.cRead more
Choice (b) is correct.
i¹⁰⁰² = i¹⁰⁰⁰ × i²
= (i⁴ )²⁵⁰ × (-1) = 1²⁵⁰ × (-1) = -1
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
Choice (c) is correct. We know that the square root of negative number is imaginary number. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwRead more
Choice (c) is correct. We know that the square root of negative number is imaginary number.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
Choice (d) is correct. Given, a + ib = c +id ⇒ a = c and b = d ⇒ a² + b² = c² + d² This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacadRead more
Choice (d) is correct.
Given, a + ib = c +id
⇒ a = c and b = d
⇒ a² + b² = c² + d²
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
Choices (d) is correct. Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1 ⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1. Thus, z lies on a circle with centre (-1, 0) and radius 1. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex NRead more
Choices (d) is correct.
Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1
⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1.
Thus, z lies on a circle with centre (-1, 0) and radius 1.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
If z = 1 – cos 2 θ + i sin 2 θ, then ∣ z ∣
Choice (c) is correct. Here, z = 1 - cos 2 θ + i sin 2 θ ∣ z ∣ = ∣1 - cos 2 θ + i sin 2 θ∣ = √(1 - cos 2θ)² + (sin 2θ)² = √ 1 -2 cos 2 θ + sin² 2θ = √1 - 2 cos2θ + 1 = √2 -2 cos 2 θ = √2(1- cos 2θ ) = √2(2 sin² θ) = 2 ∣ sin θ ∣ This question related to Chapter 4 maths Class 11th NCERT. From the ChRead more
Choice (c) is correct.
Here, z = 1 – cos 2 θ + i sin 2 θ
∣ z ∣ = ∣1 – cos 2 θ + i sin 2 θ∣ = √(1 – cos 2θ)² + (sin 2θ)²
= √ 1 -2 cos 2 θ + sin² 2θ = √1 – 2 cos2θ + 1
= √2 -2 cos 2 θ = √2(1- cos 2θ ) = √2(2 sin² θ) = 2 ∣ sin θ ∣
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
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The value of i¹⁰⁰² is
Choice (b) is correct. i¹⁰⁰² = i¹⁰⁰⁰ × i² = (i⁴ )²⁵⁰ × (-1) = 1²⁵⁰ × (-1) = -1 This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.cRead more
Choice (b) is correct.
i¹⁰⁰² = i¹⁰⁰⁰ × i²
= (i⁴ )²⁵⁰ × (-1) = 1²⁵⁰ × (-1) = -1
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
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Which of the following options define imaginary number?
Choice (c) is correct. We know that the square root of negative number is imaginary number. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwRead more
Choice (c) is correct. We know that the square root of negative number is imaginary number.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
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If a + ib = c + id, then
Choice (d) is correct. Given, a + ib = c +id ⇒ a = c and b = d ⇒ a² + b² = c² + d² This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacadRead more
Choice (d) is correct.
Given, a + ib = c +id
⇒ a = c and b = d
⇒ a² + b² = c² + d²
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
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The complex number z = x + iy satisfies the condition ∣ z + 1 ∣ = 1, then z lies on
Choices (d) is correct. Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1 ⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1. Thus, z lies on a circle with centre (-1, 0) and radius 1. This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex NRead more
Choices (d) is correct.
Given ∣ z + 1 ∣ = 1 ⇒ ∣ z -(- 1 + 0i ∣ = 1
⇒ The distance of the point z from the point (-1, 0) is constant and is equal to 1.
Thus, z lies on a circle with centre (-1, 0) and radius 1.
This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-4