Class 10 Mathematics Chapter 10 MCQ evaluates knowledge of circles, tangents, and their properties, enhancing analytical skills and exam readiness while focusing on geometric concepts critical for higher-level mathematics. For Practice MCQ visit here: https://www.tiwariacademy.in/ncert-solutions-claRead more
Class 10 Mathematics Chapter 10 MCQ evaluates knowledge of circles, tangents, and their properties, enhancing analytical skills and exam readiness while focusing on geometric concepts critical for higher-level mathematics.
Class 10 Mathematics Chapter 9 MCQ assesses understanding of trigonometric applications, enhances problem-solving skills, and prepares students for real-life scenarios involving heights, distances, and angles, crucial for exams and advanced studies. For Practice MCQ visit here: https://www.tiwariacaRead more
Class 10 Mathematics Chapter 9 MCQ assesses understanding of trigonometric applications, enhances problem-solving skills, and prepares students for real-life scenarios involving heights, distances, and angles, crucial for exams and advanced studies.
Class 10 Mathematics Chapter 8 MCQ evaluates knowledge of trigonometric ratios and identities, strengthens foundational concepts, and prepares students for advanced math applications, problem-solving, and scoring well in exams. For Practice MCQ visit here: https://www.tiwariacademy.in/ncert-solutionRead more
Class 10 Mathematics Chapter 8 MCQ evaluates knowledge of trigonometric ratios and identities, strengthens foundational concepts, and prepares students for advanced math applications, problem-solving, and scoring well in exams.
Given: - Observer is 200m above the lake. - Angle of elevation of cloud = 30°. - Angle of depression of reflection = 60°. Using tangent for both angles: 1. tan30° = (h - 200) / d ⇒ d = √3(h - 200). 2. tan60° = (h + 200) / d ⇒ √3 = (h + 200) / d. Substitute d = √3(h - 200) into the second equation: √Read more
Given:
– Observer is 200m above the lake.
– Angle of elevation of cloud = 30°.
– Angle of depression of reflection = 60°.
Using tangent for both angles:
1. tan30° = (h – 200) / d ⇒ d = √3(h – 200).
2. tan60° = (h + 200) / d ⇒ √3 = (h + 200) / d.
Substitute d = √3(h – 200) into the second equation:
√3 = (h + 200) / (√3(h – 200)).
Simplify:
3(h – 200) = h + 200.
Solve for h:
2h = 800 ⇒ h = 400.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
We are given: - Height of the pole = 6m, - Length of the shadow = 2√3m. The angle of elevation (θ) of the sun can be found using the tangent function: tanθ = (Height of the pole) / (Length of the shadow). Substitute the values: tanθ = 6 / (2√3). Simplify: tanθ = 3 / √3 = √3. From trigonometric valueRead more
We are given:
– Height of the pole = 6m,
– Length of the shadow = 2√3m.
The angle of elevation (θ) of the sun can be found using the tangent function:
tanθ = (Height of the pole) / (Length of the shadow).
Substitute the values:
tanθ = 6 / (2√3).
Simplify:
tanθ = 3 / √3 = √3.
From trigonometric values, tanθ = √3 corresponds to θ = 60°.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
What is the importance of Class 10 Mathematics Chapter 10 MCQ?
Class 10 Mathematics Chapter 10 MCQ evaluates knowledge of circles, tangents, and their properties, enhancing analytical skills and exam readiness while focusing on geometric concepts critical for higher-level mathematics. For Practice MCQ visit here: https://www.tiwariacademy.in/ncert-solutions-claRead more
Class 10 Mathematics Chapter 10 MCQ evaluates knowledge of circles, tangents, and their properties, enhancing analytical skills and exam readiness while focusing on geometric concepts critical for higher-level mathematics.
For Practice MCQ visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions-class-10-maths-chapter-10/
What is the importance of Class 10 Mathematics Chapter 9 MCQ?
Class 10 Mathematics Chapter 9 MCQ assesses understanding of trigonometric applications, enhances problem-solving skills, and prepares students for real-life scenarios involving heights, distances, and angles, crucial for exams and advanced studies. For Practice MCQ visit here: https://www.tiwariacaRead more
Class 10 Mathematics Chapter 9 MCQ assesses understanding of trigonometric applications, enhances problem-solving skills, and prepares students for real-life scenarios involving heights, distances, and angles, crucial for exams and advanced studies.
For Practice MCQ visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions-class-10-maths-chapter-9/
What is the importance of Class 10 Mathematics Chapter 8 MCQ?
Class 10 Mathematics Chapter 8 MCQ evaluates knowledge of trigonometric ratios and identities, strengthens foundational concepts, and prepares students for advanced math applications, problem-solving, and scoring well in exams. For Practice MCQ visit here: https://www.tiwariacademy.in/ncert-solutionRead more
Class 10 Mathematics Chapter 8 MCQ evaluates knowledge of trigonometric ratios and identities, strengthens foundational concepts, and prepares students for advanced math applications, problem-solving, and scoring well in exams.
For Practice MCQ visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions-class-10-maths-chapter-8/
If the angle of elevation of a cloud from a point 200m above a lake is 30° and the angle of depression of its reflection in the lake is 60°, then the height of the cloud above the lake, is
Given: - Observer is 200m above the lake. - Angle of elevation of cloud = 30°. - Angle of depression of reflection = 60°. Using tangent for both angles: 1. tan30° = (h - 200) / d ⇒ d = √3(h - 200). 2. tan60° = (h + 200) / d ⇒ √3 = (h + 200) / d. Substitute d = √3(h - 200) into the second equation: √Read more
Given:
– Observer is 200m above the lake.
– Angle of elevation of cloud = 30°.
– Angle of depression of reflection = 60°.
Using tangent for both angles:
1. tan30° = (h – 200) / d ⇒ d = √3(h – 200).
2. tan60° = (h + 200) / d ⇒ √3 = (h + 200) / d.
Substitute d = √3(h – 200) into the second equation:
√3 = (h + 200) / (√3(h – 200)).
Simplify:
3(h – 200) = h + 200.
Solve for h:
2h = 800 ⇒ h = 400.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/
If a pole 6m high casts a shadow 2√3m long on the ground, then sun’s elevation is
We are given: - Height of the pole = 6m, - Length of the shadow = 2√3m. The angle of elevation (θ) of the sun can be found using the tangent function: tanθ = (Height of the pole) / (Length of the shadow). Substitute the values: tanθ = 6 / (2√3). Simplify: tanθ = 3 / √3 = √3. From trigonometric valueRead more
We are given:
– Height of the pole = 6m,
– Length of the shadow = 2√3m.
The angle of elevation (θ) of the sun can be found using the tangent function:
tanθ = (Height of the pole) / (Length of the shadow).
Substitute the values:
tanθ = 6 / (2√3).
Simplify:
tanθ = 3 / √3 = √3.
From trigonometric values, tanθ = √3 corresponds to θ = 60°.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/