We need to find the value of: 95 × 96 Step 1: Use the Difference of Squares Formula We express the number in a way that simplifies multiplication: 95 × 96 = (95 × (95 +1)) We use this identify: (a - 1) (a) = a² - a Here, a = 96: 95 × 96² - 96 Step 2: Compute 96² 96² = 9216 Step 3: Subtract 96 9216 -Read more
We need to find the value of: 95 × 96
Step 1: Use the Difference of Squares Formula
We express the number in a way that simplifies multiplication:
95 × 96 = (95 × (95 +1))
We use this identify:
(a – 1) (a) = a² – a
Here, a = 96: 95 × 96² – 96
Step 2: Compute 96²
96² = 9216
Step 3: Subtract 96
9216 – 96 = 9120
Final Answer: The correct option is (b) 9120
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
A zero ( or root) of a polynomial p(x) is the value of x that makes p(x) = 0. Given polynomial: p(x) = 9x + 4 Step 1: Solve for x when p(x) = 0 9x + 4 = 0 Step 2: Isolate x 9x = -4 x = -4/9 Final Answer: The zero of p(x) = 9x + 4 is: (c) -4/9. This question related to Chapter 2 Mathematics Class 9thRead more
A zero ( or root) of a polynomial p(x) is the value of x that makes p(x) = 0.
Given polynomial: p(x) = 9x + 4
Step 1: Solve for x when p(x) = 0
9x + 4 = 0
Step 2: Isolate x
9x = -4
x = -4/9
Final Answer: The zero of p(x) = 9x + 4 is: (c) -4/9.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
A zero (or root) of a polynomial p(x) is the value of x that makes p(x) = 0. Given Polynomial: p(x) = 2x - 7 Step 1: Solve for x when p(x) = 0 2x - 7 = 0 Step 2: Isolate x 2x = 7 x = 7/2 Final Answer: The zero of p(x) = 2x - 7 is (a) 7/2. This question related to Chapter 2 Mathematics Class 9th NCERRead more
A zero (or root) of a polynomial p(x) is the value of x that makes p(x) = 0.
Given Polynomial: p(x) = 2x – 7
Step 1: Solve for x when p(x) = 0
2x – 7 = 0
Step 2: Isolate x
2x = 7
x = 7/2
Final Answer: The zero of p(x) = 2x – 7 is (a) 7/2.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
The coefficient of a term in a polynomial is the numerical factor multiplied by the variable. Given Polynomial: 2 - x² + x³ Step 1: Identify the x² Term The polynomial is written as: 2 + (-1)x² + x³ The term containing x² is - x² . The coefficient of x² is -1. Final Answer: The correct option is: (dRead more
The coefficient of a term in a polynomial is the numerical factor multiplied by the variable.
Given Polynomial: 2 – x² + x³
Step 1: Identify the x² Term
The polynomial is written as: 2 + (-1)x² + x³
The term containing x² is – x² .
The coefficient of x² is -1.
Final Answer: The correct option is: (d) -1
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
The degree of a polynomial is the highest power of the variable in the given expression. Given Expression: 3 Since 3 is a constant, it can be written as: 3 = 3x⁰ where x⁰ = 1. Step 1: Identify the Degree A constant term always has a degree of 0, because it does not contain a variable. Final Answer:Read more
The degree of a polynomial is the highest power of the variable in the given expression.
Given Expression: 3
Since 3 is a constant, it can be written as:
3 = 3x⁰
where x⁰ = 1.
Step 1: Identify the Degree
A constant term always has a degree of 0, because it does not contain a variable.
Final Answer: The degree of 3 is 0, so the correct option is : (a) zero.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
The value of 95 x 96 is:
We need to find the value of: 95 × 96 Step 1: Use the Difference of Squares Formula We express the number in a way that simplifies multiplication: 95 × 96 = (95 × (95 +1)) We use this identify: (a - 1) (a) = a² - a Here, a = 96: 95 × 96² - 96 Step 2: Compute 96² 96² = 9216 Step 3: Subtract 96 9216 -Read more
We need to find the value of: 95 × 96
Step 1: Use the Difference of Squares Formula
We express the number in a way that simplifies multiplication:
95 × 96 = (95 × (95 +1))
We use this identify:
(a – 1) (a) = a² – a
Here, a = 96: 95 × 96² – 96
Step 2: Compute 96²
96² = 9216
Step 3: Subtract 96
9216 – 96 = 9120
Final Answer: The correct option is (b) 9120
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The zero of p(x) = 9x + 4 is:
A zero ( or root) of a polynomial p(x) is the value of x that makes p(x) = 0. Given polynomial: p(x) = 9x + 4 Step 1: Solve for x when p(x) = 0 9x + 4 = 0 Step 2: Isolate x 9x = -4 x = -4/9 Final Answer: The zero of p(x) = 9x + 4 is: (c) -4/9. This question related to Chapter 2 Mathematics Class 9thRead more
A zero ( or root) of a polynomial p(x) is the value of x that makes p(x) = 0.
Given polynomial: p(x) = 9x + 4
Step 1: Solve for x when p(x) = 0
9x + 4 = 0
Step 2: Isolate x
9x = -4
x = -4/9
Final Answer: The zero of p(x) = 9x + 4 is: (c) -4/9.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The zero of p(x) = 2x – 7 is:
A zero (or root) of a polynomial p(x) is the value of x that makes p(x) = 0. Given Polynomial: p(x) = 2x - 7 Step 1: Solve for x when p(x) = 0 2x - 7 = 0 Step 2: Isolate x 2x = 7 x = 7/2 Final Answer: The zero of p(x) = 2x - 7 is (a) 7/2. This question related to Chapter 2 Mathematics Class 9th NCERRead more
A zero (or root) of a polynomial p(x) is the value of x that makes p(x) = 0.
Given Polynomial: p(x) = 2x – 7
Step 1: Solve for x when p(x) = 0
2x – 7 = 0
Step 2: Isolate x
2x = 7
x = 7/2
Final Answer: The zero of p(x) = 2x – 7 is (a) 7/2.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
In 2 – x² + x³ the coefficient of x² is:
The coefficient of a term in a polynomial is the numerical factor multiplied by the variable. Given Polynomial: 2 - x² + x³ Step 1: Identify the x² Term The polynomial is written as: 2 + (-1)x² + x³ The term containing x² is - x² . The coefficient of x² is -1. Final Answer: The correct option is: (dRead more
The coefficient of a term in a polynomial is the numerical factor multiplied by the variable.
Given Polynomial: 2 – x² + x³
Step 1: Identify the x² Term
The polynomial is written as: 2 + (-1)x² + x³
The term containing x² is – x² .
The coefficient of x² is -1.
Final Answer: The correct option is: (d) -1
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/
The degree of 3 is:
The degree of a polynomial is the highest power of the variable in the given expression. Given Expression: 3 Since 3 is a constant, it can be written as: 3 = 3x⁰ where x⁰ = 1. Step 1: Identify the Degree A constant term always has a degree of 0, because it does not contain a variable. Final Answer:Read more
The degree of a polynomial is the highest power of the variable in the given expression.
Given Expression: 3
Since 3 is a constant, it can be written as:
3 = 3x⁰
where x⁰ = 1.
Step 1: Identify the Degree
A constant term always has a degree of 0, because it does not contain a variable.
Final Answer: The degree of 3 is 0, so the correct option is : (a) zero.
This question related to Chapter 2 Mathematics Class 9th NCERT. From the Chapter 2 Polynomials. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/