Given: Height of the first pole = 20m, Height of the second pole = 14m, Angle of the wire with the horizontal = 30°. Find the vertical difference Vertical difference = 20 - 14 = 6m. Use the sine function sinθ = (Vertical difference) / (Length of the wire). sin30° = 6 / L. From trigonometric values,Read more
Given:
Height of the first pole = 20m,
Height of the second pole = 14m,
Angle of the wire with the horizontal = 30°.
Use the sine function
sinθ = (Vertical difference) / (Length of the wire).
sin30° = 6 / L.
From trigonometric values, sin30° = 1/2:
1/2 = 6 / L.
Solve for L
L = 6 × 2 = 12m.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
Given: - Observer is 200m above the lake. - Angle of elevation of cloud = 30°. - Angle of depression of reflection = 60°. Using tangent for both angles: 1. tan30° = (h - 200) / d ⇒ d = √3(h - 200). 2. tan60° = (h + 200) / d ⇒ √3 = (h + 200) / d. Substitute d = √3(h - 200) into the second equation: √Read more
Given:
– Observer is 200m above the lake.
– Angle of elevation of cloud = 30°.
– Angle of depression of reflection = 60°.
Using tangent for both angles:
1. tan30° = (h – 200) / d ⇒ d = √3(h – 200).
2. tan60° = (h + 200) / d ⇒ √3 = (h + 200) / d.
Substitute d = √3(h – 200) into the second equation:
√3 = (h + 200) / (√3(h – 200)).
Simplify:
3(h – 200) = h + 200.
Solve for h:
2h = 800 ⇒ h = 400.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
Given: Height of the cliff = 25m, Angle of elevation = Angle of depression. Let the height of the tower be h. From geometry, the total height of the tower = Cliff height + Cliff height = 2 × 25 = 50 This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of TRead more
Given:
Height of the cliff = 25m,
Angle of elevation = Angle of depression.
Let the height of the tower be h.
From geometry, the total height of the tower = Cliff height + Cliff height = 2 × 25 = 50
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
The angle of depression is related to the height of the tower and the horizontal distance to the car. Using trigonometry: tanθ = (Height) / (Distance). For a 150m high tower, if the angle of depression corresponds to a standard angle like 30° or 45°, the distance can be calculated using trigonometriRead more
The angle of depression is related to the height of the tower and the horizontal distance to the car. Using trigonometry:
tanθ = (Height) / (Distance).
For a 150m high tower, if the angle of depression corresponds to a standard angle like 30° or 45°, the distance can be calculated using trigonometric ratios.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
We are given: - Height of the pole = 6m, - Length of the shadow = 2√3m. The angle of elevation (θ) of the sun can be found using the tangent function: tanθ = (Height of the pole) / (Length of the shadow). Substitute the values: tanθ = 6 / (2√3). Simplify: tanθ = 3 / √3 = √3. From trigonometric valueRead more
We are given:
– Height of the pole = 6m,
– Length of the shadow = 2√3m.
The angle of elevation (θ) of the sun can be found using the tangent function:
tanθ = (Height of the pole) / (Length of the shadow).
Substitute the values:
tanθ = 6 / (2√3).
Simplify:
tanθ = 3 / √3 = √3.
From trigonometric values, tanθ = √3 corresponds to θ = 60°.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
The tops of two poles of height 20m and 14 m are connect by a wire. If the wire makes an angle of 30° with horizontal, then the length of the wire is
Given: Height of the first pole = 20m, Height of the second pole = 14m, Angle of the wire with the horizontal = 30°. Find the vertical difference Vertical difference = 20 - 14 = 6m. Use the sine function sinθ = (Vertical difference) / (Length of the wire). sin30° = 6 / L. From trigonometric values,Read more
Given:
Height of the first pole = 20m,
Height of the second pole = 14m,
Angle of the wire with the horizontal = 30°.
Find the vertical difference
Vertical difference = 20 – 14 = 6m.
Use the sine function
sinθ = (Vertical difference) / (Length of the wire).
sin30° = 6 / L.
From trigonometric values, sin30° = 1/2:
1/2 = 6 / L.
Solve for L
L = 6 × 2 = 12m.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/
If the angle of elevation of a cloud from a point 200m above a lake is 30° and the angle of depression of its reflection in the lake is 60°, then the height of the cloud above the lake, is
Given: - Observer is 200m above the lake. - Angle of elevation of cloud = 30°. - Angle of depression of reflection = 60°. Using tangent for both angles: 1. tan30° = (h - 200) / d ⇒ d = √3(h - 200). 2. tan60° = (h + 200) / d ⇒ √3 = (h + 200) / d. Substitute d = √3(h - 200) into the second equation: √Read more
Given:
– Observer is 200m above the lake.
– Angle of elevation of cloud = 30°.
– Angle of depression of reflection = 60°.
Using tangent for both angles:
1. tan30° = (h – 200) / d ⇒ d = √3(h – 200).
2. tan60° = (h + 200) / d ⇒ √3 = (h + 200) / d.
Substitute d = √3(h – 200) into the second equation:
√3 = (h + 200) / (√3(h – 200)).
Simplify:
3(h – 200) = h + 200.
Solve for h:
2h = 800 ⇒ h = 400.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/
From the top of a cliff 25m high the angle of elevation of a tower is found to be equal to the angle of depression of the foot of the tower. The height of the tower is
Given: Height of the cliff = 25m, Angle of elevation = Angle of depression. Let the height of the tower be h. From geometry, the total height of the tower = Cliff height + Cliff height = 2 × 25 = 50 This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of TRead more
Given:
Height of the cliff = 25m,
Angle of elevation = Angle of depression.
Let the height of the tower be h.
From geometry, the total height of the tower = Cliff height + Cliff height = 2 × 25 = 50
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/
The angle of depression of a car parked on the road from the top of a 150m high tower is
The angle of depression is related to the height of the tower and the horizontal distance to the car. Using trigonometry: tanθ = (Height) / (Distance). For a 150m high tower, if the angle of depression corresponds to a standard angle like 30° or 45°, the distance can be calculated using trigonometriRead more
The angle of depression is related to the height of the tower and the horizontal distance to the car. Using trigonometry:
tanθ = (Height) / (Distance).
For a 150m high tower, if the angle of depression corresponds to a standard angle like 30° or 45°, the distance can be calculated using trigonometric ratios.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/
If a pole 6m high casts a shadow 2√3m long on the ground, then sun’s elevation is
We are given: - Height of the pole = 6m, - Length of the shadow = 2√3m. The angle of elevation (θ) of the sun can be found using the tangent function: tanθ = (Height of the pole) / (Length of the shadow). Substitute the values: tanθ = 6 / (2√3). Simplify: tanθ = 3 / √3 = √3. From trigonometric valueRead more
We are given:
– Height of the pole = 6m,
– Length of the shadow = 2√3m.
The angle of elevation (θ) of the sun can be found using the tangent function:
tanθ = (Height of the pole) / (Length of the shadow).
Substitute the values:
tanθ = 6 / (2√3).
Simplify:
tanθ = 3 / √3 = √3.
From trigonometric values, tanθ = √3 corresponds to θ = 60°.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/