Since the object is moving with a constant velocity on a frictionless surface, there’s no net force acting on it! According to Newton’s first law, an object in motion stays in motion with the same velocity unless acted upon by ...

Newton’s second law of motion states that the force acting on an object is equal to the product of its mass and acceleration (F = ma). This law helps to determine the magnitude of force, making the correct answer: (a) ...

We use the kinematic equation: v² = u² +2as Substituting the values: 0 =(20)²+ 2a(200) 0 = 400 + 400a 400a = −400 a =−1 m/s² The negative sign indicates retardation. Thus, the retardation = 1 m/s². Class 9th Science ...

Radius of circular track = 100 m Time for one complete lap = 62.8 s Calculating Average Speed: Speed = Total distance / Total time Total distance covered in one lap = Circumference of the circle = 2πR = 2 ...

The athlete completes one round of the circular track in 40 seconds. Total time given = 2 minutes 20 seconds = 140 seconds Number of rounds completed = 140 ÷ 40 = 3.5 rounds Class 9th Science NCERT MCQ Questions

(c) The total distance covered by Arun is 20 km, but his displacement is zero. Distance is the total length of the path traveled, so Arun covers 10 km to station B and 10 km back, totaling 20 km. However, ...