Let the duration of each period be x. Period 8 9 Duration of period (in minutes) 45 x Here the number of periods and the duration of periods are in inverse proportion. ∴ 8/9 = x/45 ⇒ xX9 = 8x45 ⇒ x = 8x45/9 = 40 minutes Hence, the duration of each period would be 40 minutes. Class 8 Maths Chapter 11Read more
Let the duration of each period be x.
Period 8 9
Duration of period (in minutes) 45 x
Here the number of periods and the duration of periods are in inverse proportion.
∴ 8/9 = x/45 ⇒ xX9 = 8×45 ⇒ x = 8×45/9 = 40 minutes
Hence, the duration of each period would be 40 minutes.
Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video
(i) Let the number of days be x. Persons 2 1 Days 3 x Here, the number of persons and the number of days are in inverse proportion. ∴ 2/1 = x/3 ⇒ xX1=2x3 ⇒ x=2x3/1 = 6 days (ii) Let the number of persons be x. Persons 2 x Days 3 1 Here, the number of persons and the number of days are in inverse proRead more
(i) Let the number of days be x.
Persons 2 1
Days 3 x
Here, the number of persons and the number of days are in inverse proportion.
∴ 2/1 = x/3 ⇒ xX1=2×3 ⇒ x=2×3/1 = 6 days
(ii) Let the number of persons be x.
Persons 2 x
Days 3 1
Here, the number of persons and the number of days are in inverse proportion.
∴ 2/x = 1/3 ⇒ xX1=2×3 ⇒ x=2×3/1= 6 persons
Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video
Let the number of hours be x. Speed (in km/hr) 60 80 Time (in hours) 2 x Here, the speed of car and time are in inverse proportion. ∴ 60/80 = x/2 ⇒ xX80 = 60x2 ⇒ x= 60x2/80=3/2 = (1)1/2 hrs Hence, the car will take hours (1)1/2 hrs to reach its destination. Class 8 Maths Chapter 11 Exercise 13.2 SolRead more
Let the number of hours be x.
Speed (in km/hr) 60 80
Time (in hours) 2 x
Here, the speed of car and time are in inverse proportion.
∴ 60/80 = x/2 ⇒ xX80 = 60×2 ⇒ x= 60×2/80=3/2 = (1)1/2 hrs
Hence, the car will take hours (1)1/2 hrs to reach its destination.
Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video
Let the number of machines required be x. Days 63 54 Machines 42 x Here, the number of machines and the number of days are in inverse proportion. ∴ 63/54 = x/42 ⇒ xX54=63x42 ⇒ x=63x42/54 = 49 Hence, 49 machines would be required. Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video for more answRead more
Let the number of machines required be x.
Days 63 54
Machines 42 x
Here, the number of machines and the number of days are in inverse proportion.
∴ 63/54 = x/42 ⇒ xX54=63×42 ⇒ x=63×42/54 = 49
Hence, 49 machines would be required.
Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video
Let the number of boxes be x. No. of bottles in each box 12 20 Boxes 25 x Here the number of bottles and the number of boxes are in inverse proportion. ∴ 12/20 = x/25 ⇒ xX20=12x25 ⇒ x=12x25/20=15 Hence, 15 boxes would be filled. Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video for more answeRead more
Let the number of boxes be x.
No. of bottles in each box 12 20
Boxes 25 x
Here the number of bottles and the number of boxes are in inverse proportion.
∴ 12/20 = x/25 ⇒ xX20=12×25 ⇒ x=12×25/20=15
Hence, 15 boxes would be filled.
Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video
A school has 8 periods a day each of 45 minutes duration. How long would each period be, if the school has 9 periods a day, assuming the number of school hours to be the same?
Let the duration of each period be x. Period 8 9 Duration of period (in minutes) 45 x Here the number of periods and the duration of periods are in inverse proportion. ∴ 8/9 = x/45 ⇒ xX9 = 8x45 ⇒ x = 8x45/9 = 40 minutes Hence, the duration of each period would be 40 minutes. Class 8 Maths Chapter 11Read more
Let the duration of each period be x.
Period 8 9
Duration of period (in minutes) 45 x
Here the number of periods and the duration of periods are in inverse proportion.
∴ 8/9 = x/45 ⇒ xX9 = 8×45 ⇒ x = 8×45/9 = 40 minutes
Hence, the duration of each period would be 40 minutes.
Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-13/
Two persons could fit new windows in a house in 3 days. (i) One of the persons fell ill before the work started. How long would the job take now? (ii) How many persons would be needed to fit the windows in one day?
(i) Let the number of days be x. Persons 2 1 Days 3 x Here, the number of persons and the number of days are in inverse proportion. ∴ 2/1 = x/3 ⇒ xX1=2x3 ⇒ x=2x3/1 = 6 days (ii) Let the number of persons be x. Persons 2 x Days 3 1 Here, the number of persons and the number of days are in inverse proRead more
(i) Let the number of days be x.
Persons 2 1
Days 3 x
Here, the number of persons and the number of days are in inverse proportion.
∴ 2/1 = x/3 ⇒ xX1=2×3 ⇒ x=2×3/1 = 6 days
(ii) Let the number of persons be x.
Persons 2 x
Days 3 1
Here, the number of persons and the number of days are in inverse proportion.
∴ 2/x = 1/3 ⇒ xX1=2×3 ⇒ x=2×3/1= 6 persons
Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-13/
A car takes 2 hours to reach a destination by travelling at the speed of 60 km/hr. How long will it take when the car travels at the speed of 80 km/hr?
Let the number of hours be x. Speed (in km/hr) 60 80 Time (in hours) 2 x Here, the speed of car and time are in inverse proportion. ∴ 60/80 = x/2 ⇒ xX80 = 60x2 ⇒ x= 60x2/80=3/2 = (1)1/2 hrs Hence, the car will take hours (1)1/2 hrs to reach its destination. Class 8 Maths Chapter 11 Exercise 13.2 SolRead more
Let the number of hours be x.
Speed (in km/hr) 60 80
Time (in hours) 2 x
Here, the speed of car and time are in inverse proportion.
∴ 60/80 = x/2 ⇒ xX80 = 60×2 ⇒ x= 60×2/80=3/2 = (1)1/2 hrs
Hence, the car will take hours (1)1/2 hrs to reach its destination.
Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-13/
A factory requires 42 machines to produce a given number of articles in 63 days. How many machines would be required to produce the same number of articles in 54 days?
Let the number of machines required be x. Days 63 54 Machines 42 x Here, the number of machines and the number of days are in inverse proportion. ∴ 63/54 = x/42 ⇒ xX54=63x42 ⇒ x=63x42/54 = 49 Hence, 49 machines would be required. Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video for more answRead more
Let the number of machines required be x.
Days 63 54
Machines 42 x
Here, the number of machines and the number of days are in inverse proportion.
∴ 63/54 = x/42 ⇒ xX54=63×42 ⇒ x=63×42/54 = 49
Hence, 49 machines would be required.
Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-13/
A batch of bottles was packed in 25 boxes with 12 bottles in each box. If the same batch is packed using 20 bottles in each box, how many boxes would be filled?
Let the number of boxes be x. No. of bottles in each box 12 20 Boxes 25 x Here the number of bottles and the number of boxes are in inverse proportion. ∴ 12/20 = x/25 ⇒ xX20=12x25 ⇒ x=12x25/20=15 Hence, 15 boxes would be filled. Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video for more answeRead more
Let the number of boxes be x.
No. of bottles in each box 12 20
Boxes 25 x
Here the number of bottles and the number of boxes are in inverse proportion.
∴ 12/20 = x/25 ⇒ xX20=12×25 ⇒ x=12×25/20=15
Hence, 15 boxes would be filled.
Class 8 Maths Chapter 11 Exercise 13.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-13/