Statistics, covered in Chapter 14 of the NCERT Math textbook for Class 10, is the study of information gathering, summary, analysis, and explanation. Exercise 14.4, which focuses on finding the mean, median, and mode of grouped data, constitutes one of the exercises in it. See here for explanation fRead more
Statistics, covered in Chapter 14 of the NCERT Math textbook for Class 10, is the study of information gathering, summary, analysis, and explanation. Exercise 14.4, which focuses on finding the mean, median, and mode of grouped data, constitutes one of the exercises in it.
See here for explanation for better understanding😃👇
The frequency distribution table of less than type is as follows. Taking upper class limits of class intervals on x-axis and their respective frequencies on y-axis, its ogive can be drawn as follows.
The frequency distribution table of less than type is as follows.
Taking upper class limits of class intervals on x-axis and their respective frequencies on y-axis, its ogive can be drawn as follows.
Radius = 45 cm There are total 8 sectors. Therefore, the angle of each sector= 360°/8 = 45° The area between the two consecutive ribs = Area of sector = 45°/360° × πr² = 1/8 × π(45)² = 1/8 × 22/7 × 45 × 45 = 22275/28 cm² Here is the video explanation of the above question😮👇
Radius = 45 cm
There are total 8 sectors.
Therefore, the angle of each sector= 360°/8 = 45°
The area between the two consecutive ribs = Area of sector
= 45°/360° × πr² = 1/8 × π(45)²
= 1/8 × 22/7 × 45 × 45 = 22275/28 cm²
Here is the video explanation of the above question😮👇
Angle of each wiper = 115° Radius 25 cm Area cleaned at each sweep of the blade = Area of sector formed by wiper = 115°/360° × πr² = 23/72 × π(25)² = 23/72 × 22/7 × 25 × 25 = 151125/252 cm² Area cleaned by two wiper's blades = 2 × 158125/252 = 158125/126 cm²
Angle of each wiper = 115°
Radius 25 cm
Area cleaned at each sweep of the blade = Area of sector formed by wiper
= 115°/360° × πr² = 23/72 × π(25)²
= 23/72 × 22/7 × 25 × 25 = 151125/252 cm²
Area cleaned by two wiper’s blades = 2 × 158125/252 = 158125/126 cm²
The light house spreads red light in the form of sector of angle 80°, whose radius is 16.5 km. Therefore, the area of sector = 80°/360° × πr² = 2/9 × π(16.5)² = 2/9 × 3.14 × 16.5 × 16.5 = 189.97 km²
The light house spreads red light in the form of sector of angle 80°, whose radius is 16.5 km.
Therefore, the area of sector
= 80°/360° × πr²
= 2/9 × π(16.5)²
= 2/9 × 3.14 × 16.5 × 16.5
= 189.97 km²
The following table gives production yield per hectare of wheat of 100 farms of a village.
Statistics, covered in Chapter 14 of the NCERT Math textbook for Class 10, is the study of information gathering, summary, analysis, and explanation. Exercise 14.4, which focuses on finding the mean, median, and mode of grouped data, constitutes one of the exercises in it. See here for explanation fRead more
Statistics, covered in Chapter 14 of the NCERT Math textbook for Class 10, is the study of information gathering, summary, analysis, and explanation. Exercise 14.4, which focuses on finding the mean, median, and mode of grouped data, constitutes one of the exercises in it.
See here for explanation for better understanding😃👇
See lessThe following distribution gives the daily income of 50 workers of a factory.
The frequency distribution table of less than type is as follows. Taking upper class limits of class intervals on x-axis and their respective frequencies on y-axis, its ogive can be drawn as follows.
The frequency distribution table of less than type is as follows.
Taking upper class limits of class intervals on x-axis and their respective frequencies on y-axis, its ogive can be drawn as follows.
See lessAn umbrella has 8 ribs which are equally spaced Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.
Radius = 45 cm There are total 8 sectors. Therefore, the angle of each sector= 360°/8 = 45° The area between the two consecutive ribs = Area of sector = 45°/360° × πr² = 1/8 × π(45)² = 1/8 × 22/7 × 45 × 45 = 22275/28 cm² Here is the video explanation of the above question😮👇
Radius = 45 cm
There are total 8 sectors.
Therefore, the angle of each sector= 360°/8 = 45°
The area between the two consecutive ribs = Area of sector
= 45°/360° × πr² = 1/8 × π(45)²
= 1/8 × 22/7 × 45 × 45 = 22275/28 cm²
Here is the video explanation of the above question😮👇
See lessA car has two wipers which do not overlap. Each wiper has a blade of length 25 cm sweeping through an angle of 115°. Find the total area cleaned at each sweep of the blades.
Angle of each wiper = 115° Radius 25 cm Area cleaned at each sweep of the blade = Area of sector formed by wiper = 115°/360° × πr² = 23/72 × π(25)² = 23/72 × 22/7 × 25 × 25 = 151125/252 cm² Area cleaned by two wiper's blades = 2 × 158125/252 = 158125/126 cm²
Angle of each wiper = 115°
See lessRadius 25 cm
Area cleaned at each sweep of the blade = Area of sector formed by wiper
= 115°/360° × πr² = 23/72 × π(25)²
= 23/72 × 22/7 × 25 × 25 = 151125/252 cm²
Area cleaned by two wiper’s blades = 2 × 158125/252 = 158125/126 cm²
To warn ships for underwater rocks, a lighthouse spreads a red colored light over a sector of angle 80° to a distance of 16.5 km. Find the area of the sea over which the ships are warned. (Use π= 3.14)
The light house spreads red light in the form of sector of angle 80°, whose radius is 16.5 km. Therefore, the area of sector = 80°/360° × πr² = 2/9 × π(16.5)² = 2/9 × 3.14 × 16.5 × 16.5 = 189.97 km²
The light house spreads red light in the form of sector of angle 80°, whose radius is 16.5 km.
See lessTherefore, the area of sector
= 80°/360° × πr²
= 2/9 × π(16.5)²
= 2/9 × 3.14 × 16.5 × 16.5
= 189.97 km²