The classical Rutherford model fails because orbiting electrons, according to electromagnetic theory, should continuously emit radiation, lose energy, and spiral into the nucleus. This instability cannot explain atomic stability or discrete spectral lines observed in atomic emission, contradicting eRead more
The classical Rutherford model fails because orbiting electrons, according to electromagnetic theory, should continuously emit radiation, lose energy, and spiral into the nucleus. This instability cannot explain atomic stability or discrete spectral lines observed in atomic emission, contradicting experimental results.
Ionization energy is the energy required to remove the outermost electron from an atom in its ground state to infinity. For a hydrogen atom, its ionization energy is 13.6eV (electron volts) or 2.18 × 10⁻¹⁸ J. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapterRead more
Ionization energy is the energy required to remove the outermost electron from an atom in its ground state to infinity. For a hydrogen atom, its ionization energy is
13.6eV (electron volts) or 2.18 × 10⁻¹⁸ J.
Bohr’s quantization condition states that the angular momentum of an electron in a stationary orbit is quantized and given by mvr = nℏ, where m is mass, v is velocity, r is radius, and n is an integer. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-12/
Bohr’s quantization condition states that the angular momentum of an electron in a stationary orbit is quantized and given by mvr = nℏ, where m is mass, v is velocity, r is radius, and n is an integer.
When a hydrogen atom is in the third excited state (n = 4), the maximum number of spectral lines is given by n(n−1)/2 . For n = 4, the number of lines is 4(4−1)/2 = 6. Class 12 Physics Chapter 12 Atoms Session 2024-2025.
When a hydrogen atom is in the third excited state (n = 4), the maximum number of spectral lines is given by n(n−1)/2 . For n = 4, the number of lines is 4(4−1)/2 = 6.
Class 12 Physics
Chapter 12 Atoms Session 2024-2025.
When a hydrogen atom is in the third excited state (n = 4), the maximum number of spectral lines is given by n(n−1)/2 . For n = 4, the number of lines is 4(4−1)/2 = 6. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-12/
When a hydrogen atom is in the third excited state (n = 4), the maximum number of spectral lines is given by n(n−1)/2 . For n = 4, the number of lines is 4(4−1)/2 = 6.
Why is the classical (Rutherford) model for an atom, of electron orbiting around the nucleus, not able to explain the atomic structure?
The classical Rutherford model fails because orbiting electrons, according to electromagnetic theory, should continuously emit radiation, lose energy, and spiral into the nucleus. This instability cannot explain atomic stability or discrete spectral lines observed in atomic emission, contradicting eRead more
The classical Rutherford model fails because orbiting electrons, according to electromagnetic theory, should continuously emit radiation, lose energy, and spiral into the nucleus. This instability cannot explain atomic stability or discrete spectral lines observed in atomic emission, contradicting experimental results.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-12/
Define ionisation energy. What is its value for a hydrogen atom?
Ionization energy is the energy required to remove the outermost electron from an atom in its ground state to infinity. For a hydrogen atom, its ionization energy is 13.6eV (electron volts) or 2.18 × 10⁻¹⁸ J. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapterRead more
Ionization energy is the energy required to remove the outermost electron from an atom in its ground state to infinity. For a hydrogen atom, its ionization energy is
13.6eV (electron volts) or 2.18 × 10⁻¹⁸ J.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-12/
State Bohr’s quantisation condition for defining stationary orbits.
Bohr’s quantization condition states that the angular momentum of an electron in a stationary orbit is quantized and given by mvr = nℏ, where m is mass, v is velocity, r is radius, and n is an integer. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-12/
Bohr’s quantization condition states that the angular momentum of an electron in a stationary orbit is quantized and given by mvr = nℏ, where m is mass, v is velocity, r is radius, and n is an integer.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-12/
What is the maximum number of spectral lines emitted by a hydrogen atom when it is in the third excited state?
When a hydrogen atom is in the third excited state (n = 4), the maximum number of spectral lines is given by n(n−1)/2 . For n = 4, the number of lines is 4(4−1)/2 = 6. Class 12 Physics Chapter 12 Atoms Session 2024-2025.
When a hydrogen atom is in the third excited state (n = 4), the maximum number of spectral lines is given by n(n−1)/2 . For n = 4, the number of lines is 4(4−1)/2 = 6.
Class 12 Physics
See lessChapter 12 Atoms Session 2024-2025.
What is the maximum number of spectral lines emitted by a hydrogen atom when it is in the third excited state?
When a hydrogen atom is in the third excited state (n = 4), the maximum number of spectral lines is given by n(n−1)/2 . For n = 4, the number of lines is 4(4−1)/2 = 6. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-12/
When a hydrogen atom is in the third excited state (n = 4), the maximum number of spectral lines is given by n(n−1)/2 . For n = 4, the number of lines is 4(4−1)/2 = 6.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-12/