When a glass rod is rubbed with silk, the silk acquires an equal and opposite charge due to charge conservation. Thus, the charge on the silk is - 16 × 10⁻¹² C. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-11/
When a glass rod is rubbed with silk, the silk acquires an equal and opposite charge due to charge conservation. Thus, the charge on the silk is – 16 × 10⁻¹² C.
Carbon and silicon differ in atomic size and bonding properties. Carbon forms strong covalent bonds due to its smaller size and high electronegativity, enabling versatile organic compounds. Silicon, being larger, forms weaker bonds and primarily engages in extended networks like silicates. For moreRead more
Carbon and silicon differ in atomic size and bonding properties. Carbon forms strong covalent bonds due to its smaller size and high electronegativity, enabling versatile organic compounds. Silicon, being larger, forms weaker bonds and primarily engages in extended networks like silicates.
The inductance L of a solenoid depends only on its geometry (number of loops, core material, etc.) and not on the current. Thus, reducing the current to half does not change the inductance of the solenoid. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-8/
The inductance L of a solenoid depends only on its geometry (number of loops, core material, etc.) and not on the current. Thus, reducing the current to half does not change the inductance of the solenoid.
Alloys are preferred for standard resistors because they have high resistivity and low temperature coefficients of resistance. This ensures minimal variation in resistance with temperature changes, providing stability and accuracy. Alloys like manganin and constantan are commonly used for their duraRead more
Alloys are preferred for standard resistors because they have high resistivity and low temperature coefficients of resistance. This ensures minimal variation in resistance with temperature changes, providing stability and accuracy. Alloys like manganin and constantan are commonly used for their durability and resistance to oxidation.
In a p-n junction at equilibrium, diffusion of charge carriers (electrons and holes) is balanced by drift due to the built-in electric field of the depletion region. These opposing currents cancel each other out, resulting in no net current flow across the junction under equilibrium conditions. ForRead more
In a p-n junction at equilibrium, diffusion of charge carriers (electrons and holes) is balanced by drift due to the built-in electric field of the depletion region. These opposing currents cancel each other out, resulting in no net current flow across the junction under equilibrium conditions.
The physical quantity with the unit J T⁻¹ (joule per tesla) is the magnetic dipole moment, which measures the strength and orientation of a magnetic source. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-6/
The physical quantity with the unit J T⁻¹ (joule per tesla) is the magnetic dipole moment, which measures the strength and orientation of a magnetic source.
The work done by the magnetic field on the electron is zero. This is because the magnetic force is always perpendicular to the velocity of the electron, resulting in no displacement along the direction of the force, hence no work is done. For more visit here: https://www.tiwariacademy.com/ncert-soluRead more
The work done by the magnetic field on the electron is zero. This is because the magnetic force is always perpendicular to the velocity of the electron, resulting in no displacement along the direction of the force, hence no work is done.
For a simple microscope, when the object is at the lens's focus, the magnifying power ( M) is given by: M = 1 + D/f where D = 25cm (near point) and f = 5 cm. M = 1 + 25/5 = 6 Thus, the magnifying power is 6. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-Read more
For a simple microscope, when the object is at the lens’s focus, the magnifying power (
M) is given by:
M = 1 + D/f
where D = 25cm (near point) and f = 5 cm.
M = 1 + 25/5 = 6
Thus, the magnifying power is 6.
When the iron core is removed, the solenoid's inductance decreases, reducing opposition to current changes. However, in a d.c. circuit, inductance has minimal effect in steady state. The current remains the same, so the brightness of the bulb does not change. For more visit here: https://www.tiwariaRead more
When the iron core is removed, the solenoid’s inductance decreases, reducing opposition to current changes. However, in a d.c. circuit, inductance has minimal effect in steady state. The current remains the same, so the brightness of the bulb does not change.
As the object approaches the converging lens, the image moves away from the lens with increasing speed, remaining real, inverted, and diminished. When the object reaches the focus, the image forms at infinity. If the object stops at the focus, the image becomes highly magnified and theoretically forRead more
As the object approaches the converging lens, the image moves away from the lens with increasing speed, remaining real, inverted, and diminished. When the object reaches the focus, the image forms at infinity. If the object stops at the focus, the image becomes highly magnified and theoretically forms at an infinite distance.
A glass rod rubbed with silk acquires a charge + 1.6 x 10-¹² C. What is the charge on the silk?
When a glass rod is rubbed with silk, the silk acquires an equal and opposite charge due to charge conservation. Thus, the charge on the silk is - 16 × 10⁻¹² C. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-11/
When a glass rod is rubbed with silk, the silk acquires an equal and opposite charge due to charge conservation. Thus, the charge on the silk is – 16 × 10⁻¹² C.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-11/
Carbon and silicon both have four valence electrons each. How then are they distinguished?
Carbon and silicon differ in atomic size and bonding properties. Carbon forms strong covalent bonds due to its smaller size and high electronegativity, enabling versatile organic compounds. Silicon, being larger, forms weaker bonds and primarily engages in extended networks like silicates. For moreRead more
Carbon and silicon differ in atomic size and bonding properties. Carbon forms strong covalent bonds due to its smaller size and high electronegativity, enabling versatile organic compounds. Silicon, being larger, forms weaker bonds and primarily engages in extended networks like silicates.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-14/
A solenoid with N loops of wire tightly wrapped around an iron core is carrying an electric current. If the current through this solenoid is reduced to half, then what change would you expect in inductance L of solenoid?
The inductance L of a solenoid depends only on its geometry (number of loops, core material, etc.) and not on the current. Thus, reducing the current to half does not change the inductance of the solenoid. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-8/
The inductance L of a solenoid depends only on its geometry (number of loops, core material, etc.) and not on the current. Thus, reducing the current to half does not change the inductance of the solenoid.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-8/
Why do we prefer alloys for making standard resistors?
Alloys are preferred for standard resistors because they have high resistivity and low temperature coefficients of resistance. This ensures minimal variation in resistance with temperature changes, providing stability and accuracy. Alloys like manganin and constantan are commonly used for their duraRead more
Alloys are preferred for standard resistors because they have high resistivity and low temperature coefficients of resistance. This ensures minimal variation in resistance with temperature changes, providing stability and accuracy. Alloys like manganin and constantan are commonly used for their durability and resistance to oxidation.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
In a p-n junction, under equilibrium, there is no net current. Why?
In a p-n junction at equilibrium, diffusion of charge carriers (electrons and holes) is balanced by drift due to the built-in electric field of the depletion region. These opposing currents cancel each other out, resulting in no net current flow across the junction under equilibrium conditions. ForRead more
In a p-n junction at equilibrium, diffusion of charge carriers (electrons and holes) is balanced by drift due to the built-in electric field of the depletion region. These opposing currents cancel each other out, resulting in no net current flow across the junction under equilibrium conditions.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
Name the physical quantity having unit J T-¹.
The physical quantity with the unit J T⁻¹ (joule per tesla) is the magnetic dipole moment, which measures the strength and orientation of a magnetic source. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-6/
The physical quantity with the unit J T⁻¹ (joule per tesla) is the magnetic dipole moment, which measures the strength and orientation of a magnetic source.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-6/
An electron with charge e and mass m travels at a speed v in a plane perpendicular to a magnetic field of magnitude B. The electron follows a circular path of radius R. In a time ‘t, the electron travels halfway round the circle. What is the amount of work done by the magnetic field?
The work done by the magnetic field on the electron is zero. This is because the magnetic force is always perpendicular to the velocity of the electron, resulting in no displacement along the direction of the force, hence no work is done. For more visit here: https://www.tiwariacademy.com/ncert-soluRead more
The work done by the magnetic field on the electron is zero. This is because the magnetic force is always perpendicular to the velocity of the electron, resulting in no displacement along the direction of the force, hence no work is done.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
In a simple microscope a convex lens of focal length 5 cm is used. Calculate the magnifying power when the object is placed at the focus of the lens.
For a simple microscope, when the object is at the lens's focus, the magnifying power ( M) is given by: M = 1 + D/f where D = 25cm (near point) and f = 5 cm. M = 1 + 25/5 = 6 Thus, the magnifying power is 6. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-Read more
For a simple microscope, when the object is at the lens’s focus, the magnifying power (
M) is given by:
M = 1 + D/f
where D = 25cm (near point) and f = 5 cm.
M = 1 + 25/5 = 6
Thus, the magnifying power is 6.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/
A solenoid with an iron core and a bulb are connected to a d.c. source. How does the brightness of the bulb change, when the iron core is removed from the solenoid?
When the iron core is removed, the solenoid's inductance decreases, reducing opposition to current changes. However, in a d.c. circuit, inductance has minimal effect in steady state. The current remains the same, so the brightness of the bulb does not change. For more visit here: https://www.tiwariaRead more
When the iron core is removed, the solenoid’s inductance decreases, reducing opposition to current changes. However, in a d.c. circuit, inductance has minimal effect in steady state. The current remains the same, so the brightness of the bulb does not change.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-8/
An object approaches a converging lens with a uniform speed of 5 m s⁻¹ and stops at the focus. How will the image move with respect to the lens? Specify its nature.
As the object approaches the converging lens, the image moves away from the lens with increasing speed, remaining real, inverted, and diminished. When the object reaches the focus, the image forms at infinity. If the object stops at the focus, the image becomes highly magnified and theoretically forRead more
As the object approaches the converging lens, the image moves away from the lens with increasing speed, remaining real, inverted, and diminished. When the object reaches the focus, the image forms at infinity. If the object stops at the focus, the image becomes highly magnified and theoretically forms at an infinite distance.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/