1. Given: volume of reservoir = 108 m³ Rate of pouring water into cuboidal reservoir = 60 liters/minute = 60/100m³/minute [∵1l=1/100 m³] = 60x60/1000 m³/hour ∴ 1 m³ water filled in reservoir will take = 1000x60x60 hours ∴ 108 m³ water filled in reservoir will take = 108/1000/60x60 hours = 30 hours It wRead more

    Given: volume of reservoir = 108 m³
    Rate of pouring water into cuboidal reservoir = 60 liters/minute
    = 60/100m³/minute [∵1l=1/100 m³]
    = 60×60/1000 m³/hour
    ∴ 1 m³ water filled in reservoir will take = 1000x60x60 hours
    ∴ 108 m³ water filled in reservoir will take = 108/1000/60×60 hours = 30 hours
    It will take 30 hours to fill the reservoir.

    Class 8 Maths Chapter 11 Exercise 11.4 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-11/

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  2. (i) Let the edge of cube be l. Since, Surface area of the cube (A)=6l² When edge of cube is doubled, then Surface area of the cube (A’)= 6(2l)² = 6x4l² = 4x6l² A’ = 4 x A, Hence, the surface area will increase four times. (ii) Volume of cube (V) = l³ When edge of cube is doubled, then volume of cubeRead more

    (i) Let the edge of cube be l.
    Since, Surface area of the cube (A)=6l²
    When edge of cube is doubled, then
    Surface area of the cube (A’)= 6(2l)² = 6x4l² = 4x6l²
    A’ = 4 x A, Hence, the surface area will increase four times.
    (ii) Volume of cube (V) = l³
    When edge of cube is doubled, then volume of cube (V’)=(2l)³=8l³
    V’ = 8 x V, Hence, the volume will increase 8 times.

    Class 8 Maths Chapter 11 Exercise 11.4 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-11/

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  3. Given: Radius of cylindrical tank (r) = 1.5 m And Height of cylindrical tank (h) = 7 m Volume of cylindrical tank = πr²h = 22/7x1.5x1.5x7=49.5 cm³ = 49.5 x 1000 liters [∵1 m³ = 1000 liters] = 49500 liters Hence, the required quantity of milk is 49500 liters. Class 8 Maths Chapter 11 Exercise 11.4 SoRead more

    Given: Radius of cylindrical tank (r) = 1.5 m
    And Height of cylindrical tank (h) = 7 m
    Volume of cylindrical tank = πr²h
    = 22/7×1.5×1.5×7=49.5 cm³
    = 49.5 x 1000 liters [∵1 m³ = 1000 liters]
    = 49500 liters
    Hence, the required quantity of milk is 49500 liters.

    Class 8 Maths Chapter 11 Exercise 11.4 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-11/

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  4. Given: Volume of cylinder = 1.54 m³ and Diameter of cylinder = 140cm ∴ Radius (r) = d/2=140/2=70cm Volume of cylinder = πr²h ⇒ 1.54=22/7x0.7x0.7xh ⇒ h= 1.54x7/22x0.7x0.7 ⇒ h=154x7x10x10/22x7x7x100=1m Hence, the height of the cylinder is 1 m. Class 8 Maths Chapter 11 Exercise 11.4 Solution in Video fRead more

    Given: Volume of cylinder = 1.54 m³ and Diameter of cylinder = 140cm
    ∴ Radius (r) = d/2=140/2=70cm
    Volume of cylinder = πr²h
    ⇒ 1.54=22/7×0.7×0.7xh ⇒ h= 1.54×7/22×0.7×0.7
    ⇒ h=154x7x10x10/22x7x7x100=1m
    Hence, the height of the cylinder is 1 m.

    Class 8 Maths Chapter 11 Exercise 11.4 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-11/

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  5. Given: Length of cuboid (l) = 60 cm, Breadth of cuboid (b) = 54 cm and Height of cuboid (h) = 30 cm We know that, Volume of cuboid = lxbxh = 60 x 54 x 30 cm³ And Volume of cube = (Side)³ = 6x6x6cm³ ∴ Number of small cubes =Volume of cuboid/Volume of cube = 60x54x30/6x6x6=450 Hence, the required cubeRead more

    Given: Length of cuboid (l) = 60 cm, Breadth of cuboid (b) = 54 cm and
    Height of cuboid (h) = 30 cm
    We know that, Volume of cuboid = lxbxh = 60 x 54 x 30 cm³
    And Volume of cube = (Side)³ = 6x6x6cm³
    ∴ Number of small cubes =Volume of cuboid/Volume of cube = 60x54x30/6x6x6=450

    Hence, the required cubes are 450.

    Class 8 Maths Chapter 11 Exercise 11.4 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-11/

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