(i) x²+xy+8x+8y = x(x+y) +8(x+y) = (x+y)(x+8) (ii) 15xy-6x-5y-2 = 3x(5y-2)+1(5y-2) = (5y-2)(3x+1) Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/
(i) 7x - 42 = 7Xx-2X3X7 Taking common factors from each term, = 7(x-2X3) = 7(x-6) (ii) 6p-12q = 2X3Xp-2X2X3Xq Taking common factors from each term, = 2X3(p-2q) = 6(p-2q) Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/cRead more
(i) 7x – 42 = 7Xx-2X3X7
Taking common factors from each term,
= 7(x-2X3) = 7(x-6)
(ii) 6p-12q = 2X3Xp-2X2X3Xq
Taking common factors from each term,
= 2X3(p-2q) = 6(p-2q)
Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video
(i) 12x = 2X2X3X x 36 = 2X2X3X3 Hence, the common factors are 2, 2 and 3 = 2 x 2 x 3 = 12 (ii) 2y = 2X y 22xy = 2X11X xX y Hence, the common factors are 2 and y = 2X y X 2y Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video
(i) 12x = 2X2X3X x
36 = 2X2X3X3
Hence, the common factors are 2, 2 and 3 = 2 x 2 x 3 = 12
(ii) 2y = 2X y
22xy = 2X11X xX y
Hence, the common factors are 2 and y = 2X y X 2y
Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video
Factorize: (i) x²+xy+8x+8y (ii) 15xy-6x-5y-2
(i) x²+xy+8x+8y = x(x+y) +8(x+y) = (x+y)(x+8) (ii) 15xy-6x-5y-2 = 3x(5y-2)+1(5y-2) = (5y-2)(3x+1) Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/
(i) x²+xy+8x+8y = x(x+y) +8(x+y)
= (x+y)(x+8)
(ii) 15xy-6x-5y-2 = 3x(5y-2)+1(5y-2)
= (5y-2)(3x+1)
Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/
Factorize the following expressions. (i) 7x X 42 (ii) 6 p -12q
(i) 7x - 42 = 7Xx-2X3X7 Taking common factors from each term, = 7(x-2X3) = 7(x-6) (ii) 6p-12q = 2X3Xp-2X2X3Xq Taking common factors from each term, = 2X3(p-2q) = 6(p-2q) Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/cRead more
(i) 7x – 42 = 7Xx-2X3X7
Taking common factors from each term,
= 7(x-2X3) = 7(x-6)
(ii) 6p-12q = 2X3Xp-2X2X3Xq
Taking common factors from each term,
= 2X3(p-2q) = 6(p-2q)
Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-14/
Find the common factors of the given terms. (i) 12x,36 (ii) 2y,22xy
(i) 12x = 2X2X3X x 36 = 2X2X3X3 Hence, the common factors are 2, 2 and 3 = 2 x 2 x 3 = 12 (ii) 2y = 2X y 22xy = 2X11X xX y Hence, the common factors are 2 and y = 2X y X 2y Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video
(i) 12x = 2X2X3X x
36 = 2X2X3X3
Hence, the common factors are 2, 2 and 3 = 2 x 2 x 3 = 12
(ii) 2y = 2X y
22xy = 2X11X xX y
Hence, the common factors are 2 and y = 2X y X 2y
Class 8 Maths Chapter 11 Exercise 14.1 Solution in Video
See less