Total number of students = 25 Number of good students in mathematics = 72% of 25 = 72/100x25=18 Number of students not good in mathematics = 25 – 18 = 7 Hence percentage of students not good in mathematics = 7/25x100=28% Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video for more answers vist toRead more
Total number of students = 25
Number of good students in mathematics = 72% of 25 = 72/100×25=18
Number of students not good in mathematics = 25 – 18 = 7
Hence percentage of students not good in mathematics = 7/25×100=28%
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
Here, Principal (P) = ₹ 18,000, Time (n) = 2(1/2) years, Rate of interest (R) = 10% p.a. Amount (A) = P (1+R/100)ⁿ = 18000 (1+10/100)² = (1+1/10)² = 18000 (11/10)² = 18000 x11/10×11/10 = ₹ 21,780 Interest for 1/2 years on ₹ 21,780 at rate of 10% = 1/2 x21780x10x1/100=₹ 1,089 Total amount for 2(1/2)Read more
Here,
Principal (P) = ₹ 18,000, Time (n) = 2(1/2) years, Rate of interest (R) = 10% p.a.
Amount (A) = P (1+R/100)ⁿ = 18000 (1+10/100)² = (1+1/10)²
= 18000 (11/10)² = 18000 x11/10×11/10 = ₹ 21,780
Interest for 1/2 years on ₹ 21,780 at rate of 10% = 1/2 x21780x10x1/100=₹ 1,089
Total amount for 2(1/2) years = ₹ 21,780 + ₹ 1089 = ₹ 22,869
Compound Interest (C.I.) = A – P = ₹ 22869 – ₹ 18000 = ₹ 4,869
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
72% of 25 students are good in mathematics. How many are not good in mathematics?
Total number of students = 25 Number of good students in mathematics = 72% of 25 = 72/100x25=18 Number of students not good in mathematics = 25 – 18 = 7 Hence percentage of students not good in mathematics = 7/25x100=28% Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video for more answers vist toRead more
Total number of students = 25
Number of good students in mathematics = 72% of 25 = 72/100×25=18
Number of students not good in mathematics = 25 – 18 = 7
Hence percentage of students not good in mathematics = 7/25×100=28%
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
Calculate the amount and compound interest on: ₹ 10,000 for 1 years at 8% per annum compounded half yearly.
Here, Principal (P) = ₹ 10,000, Time (n) = 1 years = 2 half-years (compounded half yearly) Rate of interest (R) = 8% = 4% (compounded half yearly) Amount (A) = P (1+R/100)ⁿ = 10000(1+4/100)² = 10000(1+1/25)² = 10000(26/25)=26/25 x 26/25 = ₹ 10,816 Compound Interest (C.I.) = A – P = ₹ 10,816 – ₹ 10,0Read more
Here, Principal (P) = ₹ 10,000,
Time (n) = 1 years = 2 half-years (compounded half yearly)
Rate of interest (R) = 8% = 4% (compounded half yearly)
Amount (A) = P (1+R/100)ⁿ = 10000(1+4/100)² = 10000(1+1/25)²
= 10000(26/25)=26/25 x 26/25 = ₹ 10,816
Compound Interest (C.I.) = A – P = ₹ 10,816 – ₹ 10,000 = ₹ 816
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
Calculate the amount and compound interest on: ₹ 8,000 for 1 year at 9% per annum compounded half yearly. (You could the year by year calculation using S.I. formula to verify).
Here, Principal (P) = ₹ 8000, Time (n) = 1 years = 2 half-years(compounded half yearly) Rate of interest (R) = 9% = (9/2)% (compounded half yearly) Amount (A) = P (1+R/100)ⁿ = 8000(1+9/2×100)² = 8000(1+9/200)² = 8000(209/200)² = 8000 x 209/200 x 209/200 = ₹ 8,736.20 Compound Interest (C.I.) = A – PRead more
Here,
Principal (P) = ₹ 8000,
Time (n) = 1 years = 2 half-years(compounded half yearly)
Rate of interest (R) = 9% = (9/2)% (compounded half yearly)
Amount (A) = P (1+R/100)ⁿ = 8000(1+9/2×100)² = 8000(1+9/200)²
= 8000(209/200)² = 8000 x 209/200 x 209/200 = ₹ 8,736.20
Compound Interest (C.I.) = A – P = ₹ 8736.20 – ₹ 8000 = ₹ 736.20
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
Calculate the amount and compound interest on: ₹ 62,500 for 1(1/2) % years at 8% per annum compounded annually.
Here, Principal (P) = ₹ 62500, Time (n) = 1(1/2) = 3/2 years = 3 half-years (compounded half yearly) Rate of interest (R) = 8% = 4% (compounded half yearly) Amount (A) = P (1+R/100)ⁿ = 62500(1+4/100)² = 62500(1+1/25)³ = 62500 (26/25)³ = 62500 x 26/25 x 26/25 x 26/25 = ₹ 70,304 Compound Interest (C.IRead more
Here, Principal (P) = ₹ 62500,
Time (n) = 1(1/2) = 3/2 years = 3 half-years (compounded half yearly)
Rate of interest (R) = 8% = 4% (compounded half yearly)
Amount (A) = P (1+R/100)ⁿ = 62500(1+4/100)² = 62500(1+1/25)³
= 62500 (26/25)³ = 62500 x 26/25 x 26/25 x 26/25 = ₹ 70,304
Compound Interest (C.I.) = A – P = ₹ 70304 – ₹ 62500 = ₹ 7,804
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/
Calculate the amount and compound interest on: ₹ 18,000 for 2 (1/2) % years at 10% per annum compounded annually.
Here, Principal (P) = ₹ 18,000, Time (n) = 2(1/2) years, Rate of interest (R) = 10% p.a. Amount (A) = P (1+R/100)ⁿ = 18000 (1+10/100)² = (1+1/10)² = 18000 (11/10)² = 18000 x11/10×11/10 = ₹ 21,780 Interest for 1/2 years on ₹ 21,780 at rate of 10% = 1/2 x21780x10x1/100=₹ 1,089 Total amount for 2(1/2)Read more
Here,
Principal (P) = ₹ 18,000, Time (n) = 2(1/2) years, Rate of interest (R) = 10% p.a.
Amount (A) = P (1+R/100)ⁿ = 18000 (1+10/100)² = (1+1/10)²
= 18000 (11/10)² = 18000 x11/10×11/10 = ₹ 21,780
Interest for 1/2 years on ₹ 21,780 at rate of 10% = 1/2 x21780x10x1/100=₹ 1,089
Total amount for 2(1/2) years = ₹ 21,780 + ₹ 1089 = ₹ 22,869
Compound Interest (C.I.) = A – P = ₹ 22869 – ₹ 18000 = ₹ 4,869
Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-9/