Given: OK = 5.5 cm and KA = 4.2 cm. To construct: A parallelogram OKAY. Steps of construction: (a) Draw a line segment OK = 5.5 cm. (b) Draw an angle of 90° at K and draw an arc of radius KA = 4.2 cm, which intersects at point A. (c) Draw another arc of radius AY = 5.5 cm and at point O, draw anotheRead more
Given: OK = 5.5 cm and KA = 4.2 cm.
To construct: A parallelogram OKAY.
Steps of construction:
(a) Draw a line segment OK = 5.5 cm.
(b) Draw an angle of 90° at K and draw an arc of radius KA = 4.2 cm, which
intersects at point A.
(c) Draw another arc of radius AY = 5.5 cm and at point O, draw another arc of
radius 4.2 cm which intersect at Y.
(d) Join AY and OY.
It is the required parallelogram OKAY.
Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video
Given: MN = 5 cm and MP = 4 cm. To construct: A rectangle MNOP Steps of construction: (a) Draw a segment MN = 5 cm. (b) At points M and N, draw perpendiculars of lengths 4 cm and produce them. (c) Taking centres M and N, draw two arcs of 4 cm each, which intersect P and Q respectively. (d) Join sideRead more
Given: MN = 5 cm and MP = 4 cm.
To construct: A rectangle MNOP
Steps of construction:
(a) Draw a segment MN = 5 cm.
(b) At points M and N, draw perpendiculars of lengths 4 cm and produce them.
(c) Taking centres M and N, draw two arcs of 4 cm each, which intersect P and Q
respectively.
(d) Join side PO.
It is required rectangle MNOP.
Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video
Given: Diagonals of a rhombus AC = 5.2 cm and BD = 6.4 cm. To construct: A rhombus ABCD. Steps of construction: Steps of construction: (a) Draw AC = 5.2 cm and draw perpendicular bisectors on AC. (b) Since, diagonals bisect at mid-point O, therefore get half of 6.4 cm, i.e., 3.2 cm. (c) Draw two arcRead more
Given: Diagonals of a rhombus AC = 5.2 cm and BD = 6.4 cm.
To construct: A rhombus ABCD.
Steps of construction:
Steps of construction:
(a) Draw AC = 5.2 cm and draw perpendicular bisectors on AC.
(b) Since, diagonals bisect at mid-point O, therefore get half of 6.4 cm, i.e., 3.2 cm.
(c) Draw two arcs on both sides of AC of radius 3.2 cm from intersection point
O, which intersects at B and D.
(d) Join AB, BC, CD and DA.
It is required rhombus ABCD.
Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video
Given: RE = 5.1 cm. To construct: A square READ. Steps of construction: (i) Draw RE = 5.1 cm. (ii) At point E, construct an angle of 90° and draw an arc of radius 5.1 cm, which intersects at point A. (iii) At point R, draw an arc of radius 5.1 cm at point A, draw another arc of radius 5.1 cm which iRead more
Given: RE = 5.1 cm.
To construct: A square READ.
Steps of construction:
(i) Draw RE = 5.1 cm.
(ii) At point E, construct an angle of 90° and draw an arc of radius 5.1 cm,
which intersects at point A.
(iii) At point R, draw an arc of radius 5.1 cm at point A, draw another arc of
radius 5.1 cm which intersects the first arc at point D.
(iv) Join AD and RD.
It is the required square READ,
Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video
(i) Given: DE = 4 cm, EA = 5 cm, AR = 4.5 cm, ∠E = 60° , ∠A = 90° To construct: A quadrilateral DEAR. Steps of construction: (a) Draw a line segment DE = 4 cm. (b) At point E, construct an angle of 60° . (c) Taking radius 5 cm, draw an arc from point E which intersects at A. (d) Construct ∠A = 90° ,Read more
(i) Given: DE = 4 cm, EA = 5 cm, AR = 4.5 cm, ∠E = 60° , ∠A = 90°
To construct: A quadrilateral DEAR.
Steps of construction:
(a) Draw a line segment DE = 4 cm.
(b) At point E, construct an angle of 60° .
(c) Taking radius 5 cm, draw an arc from point E which intersects at A.
(d) Construct ∠A = 90° , draw an arc of radius 4.5 cm with center A which intersect at R.
(e) Join RD.
It is the required quadrilateral DEAR.
(ii) Given: TR = 3.5 cm, RU = 3 cm, UE = 4 cm, ∠R = 75° , ∠U = 120°
To construct: A quadrilateral TRUE
Steps of construction:
(a) Draw a line segment TR = 3.5 cm.
(b) Construct an angle 75° at R and draw an arc of radius 3 cm with R as centre, which intersects at U.
(c) Construct an angle of 120° at U and produce the side UE.
(d) Draw an arc of radius 4 cm with U as centre.
(e) Join UE and TE.
It is the required quadrilateral TRUE.
Class 8 Maths Chapter 4 Exercise 4.4 Solution in Video
(i) Given MO = 6 cm, OR = 4.5 cm, ∠M=60°, ∠O=105°, ∠R=105° To construct: A quadrilateral MORE Steps of construction: (a) Draw a line segment MO = 6 cm. (b) Construct ∠R = 105° and taking radius 4.5 cm, draw an arc taking O as centre, which intersects at R. (c) Also construct an angle 105° at R and pRead more
(i) Given MO = 6 cm, OR = 4.5 cm, ∠M=60°, ∠O=105°, ∠R=105°
To construct: A quadrilateral MORE
Steps of construction:
(a) Draw a line segment MO = 6 cm.
(b) Construct ∠R = 105° and taking radius 4.5 cm, draw an arc taking O as centre, which intersects at R.
(c) Also construct an angle 105° at R and produce the side RE.
(d) Construct another angle of 60° at point M and produce the side ME. Both sides ME and RE intersect at E.
It is the required quadrilateral MORE.
(ii) Given: PL = 4 cm, LA = 6.5 cm, ∠P = 90° , ∠A = 110° , ∠N = 85°
To construct: A quadrilateral PLAN.
To find: ∠L = 360°-(90°+85°+110°)= 360°-285° = 75
Steps of construction:
(a) Draw a line segment PL = 4 cm.
(b) Construct angle of 90° at P and produce the side PN.
(c) Construct angle of 75° at L and with L as centre, draw an arc of radius
6 cm, which intersects at A.
(d) Construct ∠A = 110° at A and produce the side AN which intersects
PN at N.
It is the required quadrilateral PLAN.
(iii) Given: HE = 5 cm, EA = 6 cm, ∠R = 85°
To construct: A parallelogram HEAR.
To find: ∠H = 180° -85° =95° [ ∵Sum of adjacent angle of ||ᵍᵐis 180 ]
Steps of construction:
(a) Draw a line segment HE = 5 cm.
(b) Construct ∠H = 95° and draw an arc of radius 6 cm with centre H. It intersects AR at R.
(c) Join RH.
(d) Draw ∠R = ∠E = 85° and draw an arc of radius 6 cm with E as a centre which intersects RA at A.
(e) Join RA It is the required parallelogram HEAR.
(iv) Given: OK = 7 cm, KA = 5 cm
To construct: A rectangle OKAY.
Steps of construction:
(a) Draw a line segment OK = 7 cm.
(b) Construct angle at both points O and K and produce these sides. 90
(c) Draw two arcs of radius 5 cm from points O and K respectively. These arcs intersect at Y and A.
(d) Join YA.
It is the required rectangle OKAY.
Class 8 Maths Chapter 4 Exercise 4.3 Solution in Video
(i) Given: LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm To construct: A quadrilateral LIFT Steps of construction: (a) Draw a line segment LI = 4 cm. (b) Taking radius 4.5 cm, draw an arc taking L as centre. (c) Draw an arc of 3 cm taking I as centre which intersects the first arc at F.Read more
(i) Given: LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm
To construct: A quadrilateral LIFT
Steps of construction:
(a) Draw a line segment LI = 4 cm.
(b) Taking radius 4.5 cm, draw an arc taking L as centre.
(c) Draw an arc of 3 cm taking I as centre which intersects the first arc at F.
(d) Join FI and FL.
(e) Draw another arc of radius 2.5 cm taking L as centre and 4 cm taking I as
centre which intersect at T.
(f) Join TF, Tl and TI.
It is the required quadrilateral LIFT.
Given: OL = 7.5 cm, GL = 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm
To construct: A quadrilateral GOLD
Steps of construction:
(a) Draw a line segment OL = 7.5 cm
(b) Draw an arc of radius 5 cm taking L as centre and another arc of radius 10 cm taking O as centre which intersect the first arc point at D.
(c) Join LD and OD.
(d) Draw an arc of radius 6 cm from D and draw another arc of radius 6 cm taking L as centre, which intersects at G.
(e) Join GD and GO.
It is the required quadrilateral GOLD.
(iii) Given: BN = 5.6 cm, DE = 6.5 cm
To construct: A rhombus BEND.
Steps of construction:
(a) Draw DE = 6.5 cm.
(b) Draw perpendicular bisector of line segment DE.
(c) Draw two arcs of radius 2.8 cm from intersection point O, which intersects the line KN at B and N.
(d) Join BE, BD as well as ND and NE.
It is the required rhombus BEND.
Class 8 Maths Chapter 4 Exercise 4.2 Solution in Video
(i) Given: AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm, AC = 7 cm To construct: A quadrilateral ABCD Steps of construction: (a) Draw AB = 4.5 cm. (b) Draw an arc taking radius 5.5 cm from point B. (c) Taking radius 7 cm, draw another arc from point A which intersects the first arc at point C. (d)Read more
(i) Given: AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm, AC = 7 cm
To construct: A quadrilateral ABCD
Steps of construction:
(a) Draw AB = 4.5 cm.
(b) Draw an arc taking radius 5.5 cm from point B.
(c) Taking radius 7 cm, draw another arc from point A which intersects the first arc at point C.
(d) Join BC and AC.
(e) Draw an arc of radius 6 cm from point A
and draw another arc of radius 4 cm from point C which intersects at D.
(f) Join AD and CD.
It is required quadrilateral ABCD.
(ii) Given: JU = 3.5 cm, UM = 4 cm, MP = 5 cm, PJ = 4.5 cm, PU = 6.5 cm
To construct: A quadrilateral JUMP
Steps of construction:
(a) Draw JU = 3.5 cm.
(b) Draw an arc of radius 4.5 cm taking centre J and then draw another arc of radius 6.5 cm taking U as centre. Both arcs intersect at P.
(c) Join PJ and PU.
(d) Draw arc of radius 5 cm and 4 cm taking P and U as centres respectively, which intersect at M.
(e) Join MP and MU.
It is required quadrilateral JUMP.
(iii) Given: OR = 6 cm, RE = 4.5 cm, EO = 7.5 cm
To construct: A parallelogram MORE.
Steps of construction:
(a) Draw OR = 6 cm.
(b) Draw arcs of radius 7.5 cm and radius 4.5 cm taking O and R as centres respectively, which intersect at E.
(c) Join OE and RE.
(d) Draw an arc of 6 cm radius taking E as centre.
(e) Draw another arc of 4.5 cm radius taking O as centre, which intersects at M.
(f) Join OM and EM.
It is required parallelogram MORE.
(iv) Given: BE = 4.5 cm, ET = 6 cm
To construct: A rhombus BEST.
Steps of construction:
(a) Draw TE = 6 cm and bisect it into two equal parts.
(b) Draw up and down perpendiculars to TE.
(c) Draw two arcs of 4.5 cm taking E and T as centres, which intersect at S.
(d) Again draw two arcs of 4.5 cm taking E and T as centres, which intersects at B.
(e) Join TS, ES, BT and EB.
It is the required rhombus BEST.
Class 8 Maths Chapter 4 Exercise 4.1 Solution in Video
Draw the following: A parallelogram OKAY where OK = 5.5 cm and KA = 4.2 cm.
Given: OK = 5.5 cm and KA = 4.2 cm. To construct: A parallelogram OKAY. Steps of construction: (a) Draw a line segment OK = 5.5 cm. (b) Draw an angle of 90° at K and draw an arc of radius KA = 4.2 cm, which intersects at point A. (c) Draw another arc of radius AY = 5.5 cm and at point O, draw anotheRead more
Given: OK = 5.5 cm and KA = 4.2 cm.
To construct: A parallelogram OKAY.
Steps of construction:
(a) Draw a line segment OK = 5.5 cm.
(b) Draw an angle of 90° at K and draw an arc of radius KA = 4.2 cm, which
intersects at point A.
(c) Draw another arc of radius AY = 5.5 cm and at point O, draw another arc of
radius 4.2 cm which intersect at Y.
(d) Join AY and OY.
It is the required parallelogram OKAY.
Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/
Draw the following: A rectangle with adjacent sides of length 5 cm and 4 cm.
Given: MN = 5 cm and MP = 4 cm. To construct: A rectangle MNOP Steps of construction: (a) Draw a segment MN = 5 cm. (b) At points M and N, draw perpendiculars of lengths 4 cm and produce them. (c) Taking centres M and N, draw two arcs of 4 cm each, which intersect P and Q respectively. (d) Join sideRead more
Given: MN = 5 cm and MP = 4 cm.
To construct: A rectangle MNOP
Steps of construction:
(a) Draw a segment MN = 5 cm.
(b) At points M and N, draw perpendiculars of lengths 4 cm and produce them.
(c) Taking centres M and N, draw two arcs of 4 cm each, which intersect P and Q
respectively.
(d) Join side PO.
It is required rectangle MNOP.
Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/
Draw the following: A rhombus whose diagonals are 5.2 cm and 6.4 cm.
Given: Diagonals of a rhombus AC = 5.2 cm and BD = 6.4 cm. To construct: A rhombus ABCD. Steps of construction: Steps of construction: (a) Draw AC = 5.2 cm and draw perpendicular bisectors on AC. (b) Since, diagonals bisect at mid-point O, therefore get half of 6.4 cm, i.e., 3.2 cm. (c) Draw two arcRead more
Given: Diagonals of a rhombus AC = 5.2 cm and BD = 6.4 cm.
To construct: A rhombus ABCD.
Steps of construction:
Steps of construction:
(a) Draw AC = 5.2 cm and draw perpendicular bisectors on AC.
(b) Since, diagonals bisect at mid-point O, therefore get half of 6.4 cm, i.e., 3.2 cm.
(c) Draw two arcs on both sides of AC of radius 3.2 cm from intersection point
O, which intersects at B and D.
(d) Join AB, BC, CD and DA.
It is required rhombus ABCD.
Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/
1. Draw the following: The square READ with RE = 5.1 cm.
Given: RE = 5.1 cm. To construct: A square READ. Steps of construction: (i) Draw RE = 5.1 cm. (ii) At point E, construct an angle of 90° and draw an arc of radius 5.1 cm, which intersects at point A. (iii) At point R, draw an arc of radius 5.1 cm at point A, draw another arc of radius 5.1 cm which iRead more
Given: RE = 5.1 cm.
To construct: A square READ.
Steps of construction:
(i) Draw RE = 5.1 cm.
(ii) At point E, construct an angle of 90° and draw an arc of radius 5.1 cm,
which intersects at point A.
(iii) At point R, draw an arc of radius 5.1 cm at point A, draw another arc of
radius 5.1 cm which intersects the first arc at point D.
(iv) Join AD and RD.
It is the required square READ,
Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/
(i) Construct the quadrilateral DEAR: DE = 4 cm, EA = 5 cm, AR = 4.5 cm, ∠E = 60 , ∠A = 90 (ii) Construct the quadrilateral TRUE: TR = 3.5 cm, RU = 3 cm, UE = 4 cm, ∠R = 75 , ∠U = 120
(i) Given: DE = 4 cm, EA = 5 cm, AR = 4.5 cm, ∠E = 60° , ∠A = 90° To construct: A quadrilateral DEAR. Steps of construction: (a) Draw a line segment DE = 4 cm. (b) At point E, construct an angle of 60° . (c) Taking radius 5 cm, draw an arc from point E which intersects at A. (d) Construct ∠A = 90° ,Read more
(i) Given: DE = 4 cm, EA = 5 cm, AR = 4.5 cm, ∠E = 60° , ∠A = 90°
To construct: A quadrilateral DEAR.
Steps of construction:
(a) Draw a line segment DE = 4 cm.
(b) At point E, construct an angle of 60° .
(c) Taking radius 5 cm, draw an arc from point E which intersects at A.
(d) Construct ∠A = 90° , draw an arc of radius 4.5 cm with center A which intersect at R.
(e) Join RD.
It is the required quadrilateral DEAR.
(ii) Given: TR = 3.5 cm, RU = 3 cm, UE = 4 cm, ∠R = 75° , ∠U = 120°
To construct: A quadrilateral TRUE
Steps of construction:
(a) Draw a line segment TR = 3.5 cm.
(b) Construct an angle 75° at R and draw an arc of radius 3 cm with R as centre, which intersects at U.
(c) Construct an angle of 120° at U and produce the side UE.
(d) Draw an arc of radius 4 cm with U as centre.
(e) Join UE and TE.
It is the required quadrilateral TRUE.
Class 8 Maths Chapter 4 Exercise 4.4 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/
(i) Construct the quadrilateral MORE: MO = 6 cm, OR = 4.5 cm, ∠M = 60 , ∠O = 105 , ∠R = 105 (ii) Construct the quadrilateral PLAN: PL = 4 cm, LA = 6.5 cm, ∠P = 90 , ∠A = 110 , ∠N = 85 (iii) Construct the quadrilateral Parallelogram HEAR: HE = 5 cm, EA = 6 cm, ∠ R = 85 (iv) Construct the quadrilateral Rectangle OKAY: OK = 7 cm, KA = 5 cm
(i) Given MO = 6 cm, OR = 4.5 cm, ∠M=60°, ∠O=105°, ∠R=105° To construct: A quadrilateral MORE Steps of construction: (a) Draw a line segment MO = 6 cm. (b) Construct ∠R = 105° and taking radius 4.5 cm, draw an arc taking O as centre, which intersects at R. (c) Also construct an angle 105° at R and pRead more
(i) Given MO = 6 cm, OR = 4.5 cm, ∠M=60°, ∠O=105°, ∠R=105°
To construct: A quadrilateral MORE
Steps of construction:
(a) Draw a line segment MO = 6 cm.
(b) Construct ∠R = 105° and taking radius 4.5 cm, draw an arc taking O as centre, which intersects at R.
(c) Also construct an angle 105° at R and produce the side RE.
(d) Construct another angle of 60° at point M and produce the side ME. Both sides ME and RE intersect at E.
It is the required quadrilateral MORE.
(ii) Given: PL = 4 cm, LA = 6.5 cm, ∠P = 90° , ∠A = 110° , ∠N = 85°
To construct: A quadrilateral PLAN.
To find: ∠L = 360°-(90°+85°+110°)= 360°-285° = 75
Steps of construction:
(a) Draw a line segment PL = 4 cm.
(b) Construct angle of 90° at P and produce the side PN.
(c) Construct angle of 75° at L and with L as centre, draw an arc of radius
6 cm, which intersects at A.
(d) Construct ∠A = 110° at A and produce the side AN which intersects
PN at N.
It is the required quadrilateral PLAN.
(iii) Given: HE = 5 cm, EA = 6 cm, ∠R = 85°
To construct: A parallelogram HEAR.
To find: ∠H = 180° -85° =95° [ ∵Sum of adjacent angle of ||ᵍᵐis 180 ]
Steps of construction:
(a) Draw a line segment HE = 5 cm.
(b) Construct ∠H = 95° and draw an arc of radius 6 cm with centre H. It intersects AR at R.
(c) Join RH.
(d) Draw ∠R = ∠E = 85° and draw an arc of radius 6 cm with E as a centre which intersects RA at A.
(e) Join RA It is the required parallelogram HEAR.
(iv) Given: OK = 7 cm, KA = 5 cm
To construct: A rectangle OKAY.
Steps of construction:
(a) Draw a line segment OK = 7 cm.
(b) Construct angle at both points O and K and produce these sides. 90
(c) Draw two arcs of radius 5 cm from points O and K respectively. These arcs intersect at Y and A.
(d) Join YA.
It is the required rectangle OKAY.
Class 8 Maths Chapter 4 Exercise 4.3 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/
(i) Construct the Quadrilateral LIFT: LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm (ii) Construct the Quadrilateral GOLD: OL = 7.5 cm, GL = 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm (iii) Construct the Rhombus BEND: BN = 5.6 cm, DE = 6.5 cm
(i) Given: LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm To construct: A quadrilateral LIFT Steps of construction: (a) Draw a line segment LI = 4 cm. (b) Taking radius 4.5 cm, draw an arc taking L as centre. (c) Draw an arc of 3 cm taking I as centre which intersects the first arc at F.Read more
(i) Given: LI = 4 cm, IF = 3 cm, TL = 2.5 cm, LF = 4.5 cm, IT = 4 cm
To construct: A quadrilateral LIFT
Steps of construction:
(a) Draw a line segment LI = 4 cm.
(b) Taking radius 4.5 cm, draw an arc taking L as centre.
(c) Draw an arc of 3 cm taking I as centre which intersects the first arc at F.
(d) Join FI and FL.
(e) Draw another arc of radius 2.5 cm taking L as centre and 4 cm taking I as
centre which intersect at T.
(f) Join TF, Tl and TI.
It is the required quadrilateral LIFT.
Given: OL = 7.5 cm, GL = 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm
To construct: A quadrilateral GOLD
Steps of construction:
(a) Draw a line segment OL = 7.5 cm
(b) Draw an arc of radius 5 cm taking L as centre and another arc of radius 10 cm taking O as centre which intersect the first arc point at D.
(c) Join LD and OD.
(d) Draw an arc of radius 6 cm from D and draw another arc of radius 6 cm taking L as centre, which intersects at G.
(e) Join GD and GO.
It is the required quadrilateral GOLD.
(iii) Given: BN = 5.6 cm, DE = 6.5 cm
To construct: A rhombus BEND.
Steps of construction:
(a) Draw DE = 6.5 cm.
(b) Draw perpendicular bisector of line segment DE.
(c) Draw two arcs of radius 2.8 cm from intersection point O, which intersects the line KN at B and N.
(d) Join BE, BD as well as ND and NE.
It is the required rhombus BEND.
Class 8 Maths Chapter 4 Exercise 4.2 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/
(i) Construct the quadrilateral ABCD: AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm, AC = 7 cm (ii) Construct the quadrilateral JUMP: JU = 3.5 cm, UM = 4 cm, MP = 5 cm, PJ = 4.5 cm, PU = 6.5 cm (iii) the Parallelogram MORE: OR = 6 cm, RE = 4.5 cm, EO = 7.5 cm (iv) Construct the Rhombus BEST: BE = 4.5 cm, ET = 6 cm
(i) Given: AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm, AC = 7 cm To construct: A quadrilateral ABCD Steps of construction: (a) Draw AB = 4.5 cm. (b) Draw an arc taking radius 5.5 cm from point B. (c) Taking radius 7 cm, draw another arc from point A which intersects the first arc at point C. (d)Read more
(i) Given: AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm, AC = 7 cm
To construct: A quadrilateral ABCD
Steps of construction:
(a) Draw AB = 4.5 cm.
(b) Draw an arc taking radius 5.5 cm from point B.
(c) Taking radius 7 cm, draw another arc from point A which intersects the first arc at point C.
(d) Join BC and AC.
(e) Draw an arc of radius 6 cm from point A
and draw another arc of radius 4 cm from point C which intersects at D.
(f) Join AD and CD.
It is required quadrilateral ABCD.
(ii) Given: JU = 3.5 cm, UM = 4 cm, MP = 5 cm, PJ = 4.5 cm, PU = 6.5 cm
To construct: A quadrilateral JUMP
Steps of construction:
(a) Draw JU = 3.5 cm.
(b) Draw an arc of radius 4.5 cm taking centre J and then draw another arc of radius 6.5 cm taking U as centre. Both arcs intersect at P.
(c) Join PJ and PU.
(d) Draw arc of radius 5 cm and 4 cm taking P and U as centres respectively, which intersect at M.
(e) Join MP and MU.
It is required quadrilateral JUMP.
(iii) Given: OR = 6 cm, RE = 4.5 cm, EO = 7.5 cm
To construct: A parallelogram MORE.
Steps of construction:
(a) Draw OR = 6 cm.
(b) Draw arcs of radius 7.5 cm and radius 4.5 cm taking O and R as centres respectively, which intersect at E.
(c) Join OE and RE.
(d) Draw an arc of 6 cm radius taking E as centre.
(e) Draw another arc of 4.5 cm radius taking O as centre, which intersects at M.
(f) Join OM and EM.
It is required parallelogram MORE.
(iv) Given: BE = 4.5 cm, ET = 6 cm
To construct: A rhombus BEST.
Steps of construction:
(a) Draw TE = 6 cm and bisect it into two equal parts.
(b) Draw up and down perpendiculars to TE.
(c) Draw two arcs of 4.5 cm taking E and T as centres, which intersect at S.
(d) Again draw two arcs of 4.5 cm taking E and T as centres, which intersects at B.
(e) Join TS, ES, BT and EB.
It is the required rhombus BEST.
Class 8 Maths Chapter 4 Exercise 4.1 Solution in Video
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/