1. Given: OK = 5.5 cm and KA = 4.2 cm. To construct: A parallelogram OKAY. Steps of construction: (a) Draw a line segment OK = 5.5 cm. (b) Draw an angle of 90° at K and draw an arc of radius KA = 4.2 cm, which intersects at point A. (c) Draw another arc of radius AY = 5.5 cm and at point O, draw anotheRead more

    Given: OK = 5.5 cm and KA = 4.2 cm.
    To construct: A parallelogram OKAY.
    Steps of construction:
    (a) Draw a line segment OK = 5.5 cm.
    (b) Draw an angle of 90° at K and draw an arc of radius KA = 4.2 cm, which
    intersects at point A.
    (c) Draw another arc of radius AY = 5.5 cm and at point O, draw another arc of
    radius 4.2 cm which intersect at Y.
    (d) Join AY and OY.
    It is the required parallelogram OKAY.

    Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/

    See less
    • 8
  2. Given: MN = 5 cm and MP = 4 cm. To construct: A rectangle MNOP Steps of construction: (a) Draw a segment MN = 5 cm. (b) At points M and N, draw perpendiculars of lengths 4 cm and produce them. (c) Taking centres M and N, draw two arcs of 4 cm each, which intersect P and Q respectively. (d) Join sideRead more

    Given: MN = 5 cm and MP = 4 cm.
    To construct: A rectangle MNOP
    Steps of construction:
    (a) Draw a segment MN = 5 cm.
    (b) At points M and N, draw perpendiculars of lengths 4 cm and produce them.
    (c) Taking centres M and N, draw two arcs of 4 cm each, which intersect P and Q
    respectively.
    (d) Join side PO.
    It is required rectangle MNOP.

    Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/

    See less
    • 8
  3. Given: Diagonals of a rhombus AC = 5.2 cm and BD = 6.4 cm. To construct: A rhombus ABCD. Steps of construction: Steps of construction: (a) Draw AC = 5.2 cm and draw perpendicular bisectors on AC. (b) Since, diagonals bisect at mid-point O, therefore get half of 6.4 cm, i.e., 3.2 cm. (c) Draw two arcRead more

    Given: Diagonals of a rhombus AC = 5.2 cm and BD = 6.4 cm.
    To construct: A rhombus ABCD.
    Steps of construction:
    Steps of construction:
    (a) Draw AC = 5.2 cm and draw perpendicular bisectors on AC.
    (b) Since, diagonals bisect at mid-point O, therefore get half of 6.4 cm, i.e., 3.2 cm.
    (c) Draw two arcs on both sides of AC of radius 3.2 cm from intersection point
    O, which intersects at B and D.
    (d) Join AB, BC, CD and DA.
    It is required rhombus ABCD.

    Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/

    See less
    • 7
  4. Given: RE = 5.1 cm. To construct: A square READ. Steps of construction: (i) Draw RE = 5.1 cm. (ii) At point E, construct an angle of 90° and draw an arc of radius 5.1 cm, which intersects at point A. (iii) At point R, draw an arc of radius 5.1 cm at point A, draw another arc of radius 5.1 cm which iRead more

    Given: RE = 5.1 cm.
    To construct: A square READ.
    Steps of construction:
    (i) Draw RE = 5.1 cm.
    (ii) At point E, construct an angle of 90° and draw an arc of radius 5.1 cm,
    which intersects at point A.
    (iii) At point R, draw an arc of radius 5.1 cm at point A, draw another arc of
    radius 5.1 cm which intersects the first arc at point D.
    (iv) Join AD and RD.
    It is the required square READ,

    Class 8 Maths Chapter 4 Exercise 4.5 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/

    See less
    • 6
  5. (i) Given: DE = 4 cm, EA = 5 cm, AR = 4.5 cm, ∠E = 60° , ∠A = 90° To construct: A quadrilateral DEAR. Steps of construction: (a) Draw a line segment DE = 4 cm. (b) At point E, construct an angle of 60° . (c) Taking radius 5 cm, draw an arc from point E which intersects at A. (d) Construct ∠A = 90° ,Read more

    (i) Given: DE = 4 cm, EA = 5 cm, AR = 4.5 cm, ∠E = 60° , ∠A = 90°
    To construct: A quadrilateral DEAR.
    Steps of construction:
    (a) Draw a line segment DE = 4 cm.
    (b) At point E, construct an angle of 60° .
    (c) Taking radius 5 cm, draw an arc from point E which intersects at A.
    (d) Construct ∠A = 90° , draw an arc of radius 4.5 cm with center A which intersect at R.
    (e) Join RD.
    It is the required quadrilateral DEAR.

    (ii) Given: TR = 3.5 cm, RU = 3 cm, UE = 4 cm, ∠R = 75° , ∠U = 120°
    To construct: A quadrilateral TRUE
    Steps of construction:
    (a) Draw a line segment TR = 3.5 cm.
    (b) Construct an angle 75° at R and draw an arc of radius 3 cm with R as centre, which intersects at U.
    (c) Construct an angle of 120° at U and produce the side UE.
    (d) Draw an arc of radius 4 cm with U as centre.
    (e) Join UE and TE.
    It is the required quadrilateral TRUE.

    Class 8 Maths Chapter 4 Exercise 4.4 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-4/

    See less
    • 7