1. The potential energy of a magnetic dipole is maximum when it is oriented opposite to the magnetic field. In this position, the angle between the magnetic moment and the field is 180°, resulting in maximum potential energy. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/pRead more

    The potential energy of a magnetic dipole is maximum when it is oriented opposite to the magnetic field. In this position, the angle between the magnetic moment and the field is 180°, resulting in maximum potential energy.

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  2. The diamagnetic substance among the listed options is Bi. Diamagnetic materials have all electrons paired, resulting in no net magnetic moment, causing them to be weakly repelled by magnetic fields. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-5/

    The diamagnetic substance among the listed options is Bi. Diamagnetic materials have all electrons paired, resulting in no net magnetic moment, causing them to be weakly repelled by magnetic fields.

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    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-5/

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  3. Two characteristic properties distinguishing paramagnetic and diamagnetic materials are: (i) Diamagnetic substances move from stronger to weaker regions of a non-uniform magnetic field, whereas paramagnetic substances move from weaker to stronger regions. (ii) When placed in an external magnetic fieRead more

    Two characteristic properties distinguishing paramagnetic and diamagnetic materials are:
    (i) Diamagnetic substances move from stronger to weaker regions of a non-uniform magnetic field, whereas paramagnetic substances move from weaker to stronger regions.
    (ii) When placed in an external magnetic field, diamagnetic materials expel magnetic field lines, weakening the field inside. In contrast, paramagnetic materials allow the field lines to concentrate, slightly enhancing the magnetic field inside.

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  4. (i) ∴ Magnetic moment of the magnet M = τ/Bsinθ = 0.060/0.02×0.5 = 6A\cdotpm². (ii) For stable equilibrium, the magnet's axis aligns with the magnetic field (θ=0°). For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-5/

    (i) ∴ Magnetic moment of the magnet

    M = τ/Bsinθ = 0.060/0.02×0.5 = 6A\cdotpm².

    (ii) For stable equilibrium, the magnet’s axis aligns with the magnetic field (θ=0°).

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  5. Magnetic susceptibility χ = μ r −1, where μ r is the relative permeability. Material A (μ r =0.96) is diamagnetic due to χ < 0, while material B (μ r = 500) is ferromagnetic with strong alignment (χ ≫1). For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-5Read more

    Magnetic susceptibility χ = μ r −1, where μ r is the relative permeability. Material A (μ r =0.96) is diamagnetic due to χ < 0, while material B (μ r = 500) is ferromagnetic with strong alignment (χ ≫1).

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    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-5/

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