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Janvi Shinha

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Janvi Shinha
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Janvi Shinha
Asked: February 25, 2025In: Class 12 Physics

In a meter bridge experiment, resistance box (with R = 2 n) is connected in the left gap and the unknown resistance S in the right gap. If the balancing length be 40 cm, calculate the value of S

In a meter bridge, the balancing condition is R / S = L / (100 – L). Given R = 2 Ω and L = 40 cm, we get 2 / S = 40 / 60. Solving for S, S ...

class 12thmcqscience
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Janvi Shinha
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Janvi Shinha
Asked: February 25, 2025In: Class 12 Physics

A cell supplies a current of 0-9 A through a 2Ω resistor and a current of 0.3 A through 7Ω resistor. The internal resistance of the cell is :

Let the EMF of the cell be E and internal resistance be r. Using Ohm’s law:For 2Ω resistor: E = 0.9 (2 + r) For 7 resistor E = 0.3 (7 + r) Equating both: 0.9(2 + r) = 0.3 ...

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