(a) 297 x 17 + 297 x 3 = 297 x (17 + 3) = 297 x 20 = 5940 (b) 54279 x 92 + 8 x 542379 = 54279 x (92 + 8) = 54279 x 100 = 5427900 (c) 81265 x 169 – 81265 x 69 = 81265 x (169 – 69) = 81265 x 100 = 8126500 (d) 3845 x 5 x 782 + 769 x 25 x 218 = 3845 x 5 x 782 + 769 x 5 x 5 x 218) = 3845 x 5 x 782 + 3845Read more
(a) 297 x 17 + 297 x 3
= 297 x (17 + 3)
= 297 x 20
= 5940
(b) 54279 x 92 + 8 x 542379
= 54279 x (92 + 8)
= 54279 x 100
= 5427900
(c) 81265 x 169 – 81265 x 69
= 81265 x (169 – 69)
= 81265 x 100
= 8126500
(d) 3845 x 5 x 782 + 769 x 25 x 218
= 3845 x 5 x 782 + 769 x 5 x 5 x 218)
= 3845 x 5 x 782 + 3845 x 5 x 218
= 3845 x 5 x (782 + 218)
= 3845 x 5 x 1000
= 19225000
Factors of 12 are 1, 2, 3, 4, 6 and 12. Therefore, the number also be divisible by 1, 2, 3 4 and 6. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
Factors of 12 are 1, 2, 3, 4, 6 and 12.
Therefore, the number also be divisible by 1, 2, 3 4 and 6.
(a) Factors of 18 = 1, 2, 3, 6, 9, 18 Factors of 35 = 1, 5, 7, 35 Common factor = 1 Since, both have only one common factor, i.e., 1, therefore, they are co-prime numbers. (b) Factors of 15 = 1, 3, 5, 15 Factors of 37 = 1, 37 Common factor = 1 Since, both have only one common factor, i.e., 1, therefRead more
(a) Factors of 18 = 1, 2, 3, 6, 9, 18
Factors of 35 = 1, 5, 7, 35
Common factor = 1
Since, both have only one common factor, i.e., 1, therefore, they are co-prime numbers.
(b) Factors of 15 = 1, 3, 5, 15
Factors of 37 = 1, 37
Common factor = 1
Since, both have only one common factor, i.e., 1, therefore, they are co-prime numbers.
(c) Factors of 30 = 1, 2, 3, 5, 6, 15, 30
Factors of 415 = 1, 5, …….., 83, 415
Common factor = 1, 5
Since, both have more than one common factor, therefore, they are not co-prime numbers.
(d) Factors of 17 = 1, 17
Factors of 68 = 1, 2, 4, 17, 34, 86
Common factor = 1, 17
Since, both have more than one common factor, therefore, they are not co-prime numbers.
(e) Factors of 216 = 1, 2, 3, 4, 6, 8, 36, 72, 108, 216
Factors of 215 = 1, 5, 43, 215
Common factor = 1
Since, both have only one common factor, i.e., 1, therefore, they are co-prime numbers.
(f) Factors of 81 = 1, 3, 9, 27, 81
Factors of 16 = 1, 2, 4, 8, 16
Common factor = 1
Since, both have only one common factor, i.e., 1, therefore, they are co-prime numbers.
Find the value of the following: (a) 297 x 17 + 297 x 3 (b) 54279 x 92 + 8 x 54279 (c) 81265 x 169 – 81265 x 69 (d) 3845 x 5 x 782 + 769 x 25 x 218
(a) 297 x 17 + 297 x 3 = 297 x (17 + 3) = 297 x 20 = 5940 (b) 54279 x 92 + 8 x 542379 = 54279 x (92 + 8) = 54279 x 100 = 5427900 (c) 81265 x 169 – 81265 x 69 = 81265 x (169 – 69) = 81265 x 100 = 8126500 (d) 3845 x 5 x 782 + 769 x 25 x 218 = 3845 x 5 x 782 + 769 x 5 x 5 x 218) = 3845 x 5 x 782 + 3845Read more
(a) 297 x 17 + 297 x 3
= 297 x (17 + 3)
= 297 x 20
= 5940
(b) 54279 x 92 + 8 x 542379
= 54279 x (92 + 8)
= 54279 x 100
= 5427900
(c) 81265 x 169 – 81265 x 69
= 81265 x (169 – 69)
= 81265 x 100
= 8126500
(d) 3845 x 5 x 782 + 769 x 25 x 218
= 3845 x 5 x 782 + 769 x 5 x 5 x 218)
= 3845 x 5 x 782 + 3845 x 5 x 218
= 3845 x 5 x (782 + 218)
= 3845 x 5 x 1000
= 19225000
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
See lessWhich of the following will not represent zero:
(a) 1 + 0 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
(a) 1 + 0
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
See lessA number is divisible by 12. By what other numbers will that number be divisible?
Factors of 12 are 1, 2, 3, 4, 6 and 12. Therefore, the number also be divisible by 1, 2, 3 4 and 6. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
Factors of 12 are 1, 2, 3, 4, 6 and 12.
Therefore, the number also be divisible by 1, 2, 3 4 and 6.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
See lessA number is divisible by both 5 and 12. By which other number will that number be always divisible?
5 x 12 = 60. The number must be divisible by 60. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
5 x 12 = 60. The number must be divisible by 60.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
See lessWhich of the following numbers are co-prime: (a) 18 and 35 (b) 15 and 37 (c) 30 and 415 (d) 17 and 68 (e) 216 and 215 (f) 81 and 16
(a) Factors of 18 = 1, 2, 3, 6, 9, 18 Factors of 35 = 1, 5, 7, 35 Common factor = 1 Since, both have only one common factor, i.e., 1, therefore, they are co-prime numbers. (b) Factors of 15 = 1, 3, 5, 15 Factors of 37 = 1, 37 Common factor = 1 Since, both have only one common factor, i.e., 1, therefRead more
(a) Factors of 18 = 1, 2, 3, 6, 9, 18
Factors of 35 = 1, 5, 7, 35
Common factor = 1
Since, both have only one common factor, i.e., 1, therefore, they are co-prime numbers.
(b) Factors of 15 = 1, 3, 5, 15
Factors of 37 = 1, 37
Common factor = 1
Since, both have only one common factor, i.e., 1, therefore, they are co-prime numbers.
(c) Factors of 30 = 1, 2, 3, 5, 6, 15, 30
Factors of 415 = 1, 5, …….., 83, 415
Common factor = 1, 5
Since, both have more than one common factor, therefore, they are not co-prime numbers.
(d) Factors of 17 = 1, 17
Factors of 68 = 1, 2, 4, 17, 34, 86
Common factor = 1, 17
Since, both have more than one common factor, therefore, they are not co-prime numbers.
(e) Factors of 216 = 1, 2, 3, 4, 6, 8, 36, 72, 108, 216
Factors of 215 = 1, 5, 43, 215
Common factor = 1
Since, both have only one common factor, i.e., 1, therefore, they are co-prime numbers.
(f) Factors of 81 = 1, 3, 9, 27, 81
Factors of 16 = 1, 2, 4, 8, 16
Common factor = 1
Since, both have only one common factor, i.e., 1, therefore, they are co-prime numbers.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
See less