Hints:- (a) L.C.M. of 5 and 20 = 2 x 2 x 5 = 20 (b) L.C.M. of 6 and 18 = 2 x 3 x 3 = 18 (c) L.C.M. of 12 and 48 = 2 x 2 x 2 x 2 x 3 = 48 (d) L.C.M. of 9 and 45 = 3 x 3 x 5 = 45 From these all cases, we can conclude that if the smallest number if the factor of largest number, then the L.C.M. of theseRead more

Hints:- L.C.M. of 18, 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288 The smallest four-digit number = 1000 Therefore, the required number is 1000 + (288 – 136) = 1152. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/

Hints:- The maximum capacity of container = H.C.F. (403, 434, 465) Factors of 403 = 13 x 31 Factors of 434 = 2 x 7 x 31 Factors of 465 = 3 x 5 x 31 H.C.F. = 31 Therefore, 31 litres of container is required to measure the quantity.   https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chRead more

Hints:- L.C.M. of 8, 10, 12 = 2 x 2 x 2 x 3 x 5 = 120 The largest three digit number = 999 Therefore, the required number = 999 – 39 = 960   https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/

The measurement of longest tape = H.C.F. of 825 cm, 675 cm and 450 cm. Factors of 825 = 3 x 5 x 5 x 11 Factors of 675 = 3 x 5 x 5 x 3 x 3 Factors of 450 = 2 x 3 x 3 x 5 x 5 H.C.F. = 3 x 5 x 5 = 75 cm Therefore, the longest tape is 75 cm.   https://www.tiwariacademy.com/ncert-solutions/class-6/mRead more