Hints:- (a) L.C.M. of 5 and 20 = 2 x 2 x 5 = 20 (b) L.C.M. of 6 and 18 = 2 x 3 x 3 = 18 (c) L.C.M. of 12 and 48 = 2 x 2 x 2 x 2 x 3 = 48 (d) L.C.M. of 9 and 45 = 3 x 3 x 5 = 45 From these all cases, we can conclude that if the smallest number if the factor of largest number, then the L.C.M. of theseRead more
Hints:-
(a) L.C.M. of 5 and 20
= 2 x 2 x 5
= 20
(b) L.C.M. of 6 and 18
= 2 x 3 x 3
= 18
(c) L.C.M. of 12 and 48
= 2 x 2 x 2 x 2 x 3
= 48
(d) L.C.M. of 9 and 45
= 3 x 3 x 5
= 45
From these all cases, we can conclude that if the smallest number if the factor of largest number, then the L.C.M. of these two numbers is equal to that of larger number.
Hints:- (a) L.C.M. of 9 and 4 = 2 x 2 x 3 x 3 = 36 (b) L.C.M. of 12 and 5 = 2 x 2 x 3 x 5 = 60 (c) L.C.M. of 6 and 5 = 2 x 3 x 5 = 30 (d) L.C.M. of 15 and 4 = 2 x 2 x 3 x 5 = 60 Yes, the L.C.M. is equal to the product of two numbers in each case. And L.C.M. is also the multiple of 3. https://www.tiwRead more
Hints:-
(a) L.C.M. of 9 and 4
= 2 x 2 x 3 x 3
= 36
(b) L.C.M. of 12 and 5
= 2 x 2 x 3 x 5
= 60
(c) L.C.M. of 6 and 5
= 2 x 3 x 5
= 30
(d) L.C.M. of 15 and 4
= 2 x 2 x 3 x 5
= 60
Yes, the L.C.M. is equal to the product of two numbers in each case.
And L.C.M. is also the multiple of 3.
Hints:- L.C.M. of 18, 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288 The smallest four-digit number = 1000 Therefore, the required number is 1000 + (288 – 136) = 1152. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
Hints:-
L.C.M. of 18, 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288
The smallest four-digit number = 1000
Therefore, the required number is 1000 + (288 – 136) = 1152.
L.C.M. of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90 Therefore, the required number = 90 + 5 = 95 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
L.C.M. of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90
Therefore, the required number = 90 + 5 = 95
Hints:- The maximum capacity of container = H.C.F. (403, 434, 465) Factors of 403 = 13 x 31 Factors of 434 = 2 x 7 x 31 Factors of 465 = 3 x 5 x 31 H.C.F. = 31 Therefore, 31 litres of container is required to measure the quantity. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chRead more
Hints:-
The maximum capacity of container = H.C.F. (403, 434, 465)
Factors of 403 = 13 x 31
Factors of 434 = 2 x 7 x 31
Factors of 465 = 3 x 5 x 31
H.C.F. = 31
Therefore, 31 litres of container is required to measure the quantity.
Find the L.C.M. of the following numbers in which one number is the factor of other: (a) 5, 20 (b) 6, 18 (c) 12, 48 (d) 9, 45 What do you observe in the result obtained?
Hints:- (a) L.C.M. of 5 and 20 = 2 x 2 x 5 = 20 (b) L.C.M. of 6 and 18 = 2 x 3 x 3 = 18 (c) L.C.M. of 12 and 48 = 2 x 2 x 2 x 2 x 3 = 48 (d) L.C.M. of 9 and 45 = 3 x 3 x 5 = 45 From these all cases, we can conclude that if the smallest number if the factor of largest number, then the L.C.M. of theseRead more
Hints:-
(a) L.C.M. of 5 and 20
= 2 x 2 x 5
= 20
(b) L.C.M. of 6 and 18
= 2 x 3 x 3
= 18
(c) L.C.M. of 12 and 48
= 2 x 2 x 2 x 2 x 3
= 48
(d) L.C.M. of 9 and 45
= 3 x 3 x 5
= 45
From these all cases, we can conclude that if the smallest number if the factor of largest number, then the L.C.M. of these two numbers is equal to that of larger number.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
See lessFind the L.C.M. of the following numbers: (a) 9 and 4 (b) 12 and 5 (c) 6 and 5 (d) 15 and 4 Observe a common property in the obtained L.C.Ms. Is L.C.M. the product of two numbers in each case?
Hints:- (a) L.C.M. of 9 and 4 = 2 x 2 x 3 x 3 = 36 (b) L.C.M. of 12 and 5 = 2 x 2 x 3 x 5 = 60 (c) L.C.M. of 6 and 5 = 2 x 3 x 5 = 30 (d) L.C.M. of 15 and 4 = 2 x 2 x 3 x 5 = 60 Yes, the L.C.M. is equal to the product of two numbers in each case. And L.C.M. is also the multiple of 3. https://www.tiwRead more
Hints:-
(a) L.C.M. of 9 and 4
= 2 x 2 x 3 x 3
= 36
(b) L.C.M. of 12 and 5
= 2 x 2 x 3 x 5
= 60
(c) L.C.M. of 6 and 5
= 2 x 3 x 5
= 30
(d) L.C.M. of 15 and 4
= 2 x 2 x 3 x 5
= 60
Yes, the L.C.M. is equal to the product of two numbers in each case.
And L.C.M. is also the multiple of 3.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
See lessFind the smallest 4-digit number which is divisible by 18, 24 and 32.
Hints:- L.C.M. of 18, 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288 The smallest four-digit number = 1000 Therefore, the required number is 1000 + (288 – 136) = 1152. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
Hints:-
L.C.M. of 18, 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288
The smallest four-digit number = 1000
Therefore, the required number is 1000 + (288 – 136) = 1152.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
See lessFind the least number which when divided by 6, 15 and 18, leave remainder 5 in each case.
L.C.M. of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90 Therefore, the required number = 90 + 5 = 95 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
L.C.M. of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90
Therefore, the required number = 90 + 5 = 95
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
See lessThree tankers contain 403 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of three containers exact number of times.
Hints:- The maximum capacity of container = H.C.F. (403, 434, 465) Factors of 403 = 13 x 31 Factors of 434 = 2 x 7 x 31 Factors of 465 = 3 x 5 x 31 H.C.F. = 31 Therefore, 31 litres of container is required to measure the quantity. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chRead more
Hints:-
The maximum capacity of container = H.C.F. (403, 434, 465)
Factors of 403 = 13 x 31
Factors of 434 = 2 x 7 x 31
Factors of 465 = 3 x 5 x 31
H.C.F. = 31
Therefore, 31 litres of container is required to measure the quantity.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/
See less